100 keys to open 100 locks, how many times do you have to try at most?

5050 times.

Let's say the first key doesn't open the lock until 100 times.

Then the second key will take up to 99 times to open one of the remaining 99.

Then if the third one takes up to 98 times, it will definitely open one of the remaining 98 pieces.

In the same way, in the end, there is only one key left, which can be opened once.

That is, 1+2+3+......98+99+100=5050

4950, because you just say try, not open, so let's say that every lock you try is the last key, but you don't need to open it for the last hundred times, so it is (100+1)*50-100=4950

That is to say, when the first lock is opened, after 99 keys are opened, the last one does not need to be tried, so 100 should be subtracted

Hey, you're stupid, at most a million times, and he didn't say he couldn't pick the lock repeatedly, so my answer was a million times.

I can't turn it on every time.

The first time you have to try 100 times, and the last one is.

The second time I had to try 99 times. And so on.

Most? Can't you try it all the time?

The least number of times, the minimum number of times to determine the key is 9 times, and it must be opened more than 10 times, and the best luck is to get the right key every time

The most times, to determine that the key is 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45 times, must be opened on each lock to one more time, is 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55 times.

Precautions. Pay attention when matching keys: some key blanks look metal on the surface, but they are really very inferior, and it won't take long to break before the teeth wear out.

These key blanks are not visible to the naked eye, but they can be distinguished by a simple toss on a hard countertop such as a concrete floor or a glass top – the good ones make a metal crunch, while the bad ones make a dull sound similar to the collision between plastic and hard countertops.

It is not uncommon for a poor quality key to break into two sections, and the first section of the head is broken in the keyhole. In order to take out this half, it took a lot of effort to remove the locks, but its practical ingenuity was solved, and shared with netizens: Use a wooden screw (maybe the fast wire is better), carefully insert the tip of the screw into the gap between the key head and the hole, and you can pick it out without being too deep.

At least 9 times, that is, every time is wrong, at most every time is wrong, that is, 10+9+. 2= 54.I'm not counting the last key and a lock, but if I do, I'll add it once.

That's it, the first one has to be tried 9 times (at most) and then a lock is excluded in the second one is 8 times (up to the most) and so on The last one-on-one is not to be tried, so it's 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 = 54 (times) This is the most.

At least, you're lucky, you open the first lock, and you try it once, and then the second one just once, and so on, nine times, and the last one again, so nine times.

A maximum of 45 trials are required. Because these 10 keys are the ones that open these 10 locks. In this way, wipe it with the first key up to 9 times, and if you can't open the lock 9 times, then you don't have to try again, and you must have this key to be the key to the 10th lock.

By analogy, the second key can be opened up to 8 times ......The 9th key can be opened at most once, and the remaining 1 key and 1 lock do not need to be tried at all. That is to say, using the method of trial opening, in the worst case, 10 keys and 10 locks should be matched, and the maximum test opening is 9 8 7 ....2 1 (9 1) 9 2 45 (times).

Definition of addition: The operation of combining two numbers into a single number.

Subtraction: The operation of finding another addition in the sum of two known additions and one of them.

Multiplication: The operation of finding the product of two numbers.

Division: The operation of knowing the product of two factors and one of the factors, and finding the other factor.

The minimum number of times the question should be asked.

Up to 45 trial openings will allow you to match all the keys and locks.

Because these 10 keys do not balance the keys that open these 10 locks. In this way, use the first key to wipe it open up to 9 times, and if you can't open the lock 9 times, then you don't have to try again, and you must have this key is the key to the 10th lock.

By analogy, the second key can be opened up to 8 times ......The 9th key can be opened at most once, and the last remaining key and 1 lock will not be tried at all.

That is to say, using the method of trial opening, in the worst case, 10 keys and 10 locks should be matched, and the maximum test opening is 9 8 7 ....2 1 45 (times).

(49+1) or stare at 49 2

1225 (times) denier skin.

Answer: Shirt late and 'omitted.

Open a lock with a key, and the existing 20 keys and 20 locks need to be tested up to 190 times, and all the keys and locks can be matched.

The calculation and chain process is as follows:

Depending on the question, the maximum number of tests to be tested can be calculated.

190 (times).

Extended information: multiply from the single digit, and use the number on each of the second factors to multiply by the first Mingsun factor; Multiply by the digit of the second factor, and the last digit of the number is aligned with the digit of the second factor; Add up the number that you have multiplied several times.

The difference between two numbers divided by one number can be obtained by subtracting the subtraction by dividing the quotient obtained by dividing the subtraction by this number. For example: (65-39) 13=65 13-39 13=2.

20 keys20 locks need to be tested up to 190 times, and all the keys and locks can be matched.