Detailed explanation of college points, college points problems

I don't know if you study Shenma major. If you are a liberal arts and business major, you don't have to worry too much, you can get high scores if you work hard. If it's science and engineering, then you have to work hard, or you can't even get C0 or C+, and you may get F, let alone a high score.

The passing score is 60, which is the passing line, and the corresponding letters are F below, and fail.

As long as you are good at Korean or English, there is no problem in listening to the class, the key is to see how hard you work.

It is necessary to have a good relationship with the professor, and the foreign student should make a good impression on the professor. But don't expect that if you don't do well in the exam, you will ask the professor for a score or something like that, some professors will, but most professors won't.

It is recommended that you do not have the psychology of speculation, and the level of the exam is all in normal times. When choosing courses each semester, try to get 15-20 points. Because if your GPA is good, you can also apply for a scholarship for foreigners, and if you choose a score of less than 15, it will not be a good idea.

Now that you have come to South Korea, you should study steadily, or how to be worthy of your parents, what do you say?

This is the advice given to you as a senior in Hanyang, think about it carefully.

Dude, let's listen to the class.

Using the properties of odd functions, it is enough to apply another formula. The formula for calculating the nth trigonometric function in the interval 0-pi 2 can be directly set with this formula.

It can be gradually reduced to power.

sin2nπ=0

Final points = 5 8

Here's how.

Please check carefully.

I wish you happy studying, a fulfilling daily life, and academic progress!

Eigenroot equations.

r^4-4r^3+8r^2-8r+3=0

r=1 is obviously the root.

r^4-r^3-3r^3+3r^2+5r^2-5r-3r+3=0r^3(r-1)-3r^2(r-1)+5r(r-1)-3(r-1)=0

r-1)(r 3-3r 2+5r-3)=0, and the second r=1 is also the root to continue to dismantle.

r^3-r^2-2r^2+2r+3r-3

r^2(r-1)-2r(r-1)+3(r-1)=(r-1)(r^2-2r+3)

So (r-1) 2(r 2-2r+3)=0r=1,1,1+root2 i, 1-root2 iy=(at+b)e t+e t[ccos(root2t)+dsin(root2t)].

e t [at+b+ccos(root number2 t)+dsin(root number2 t)].

The first question is trigonometric formula, the original formula = (1 2) sinxdx=-(1 2)cosx+c.

The second question can be differentiated, the original formula = (1 6) e (3x 2+4) d(3x 2+4) = (1 6) e (3x 2+4) + c.

Solution: t 4)e (-t 2)dt=- (t 3)e (-t 2)d(t 2)=- (t 3)d[e (-t 2)], and then divide the integral method [the "-3" in the question should not have a "-" sign].

The next application should be "x n(0,1),e(x 2)=d(x)=1".

FYI.