Ask for a few Olympiad math questions, ask for answers today, kneel and beg!

1) In accordance with"The number of A processed accounts for five-eighths of the total", that is, the speed of A and B is 5:3So A can do 108 * 5 3 = 180 per hour.

It takes 16 hours for A to work independently, indicating that the total number is 180 * 16 = 2880.

B is done 3 8 * 2880 = 1080

2) The length of the two wires is 8 meters apart, and the difference is still 8 meters after everyone cuts the same section.

These 8 meters correspond to a gap of 7 in 8:1, so.

The short one is left 8 7 meters, and the long one is 64 7 meters.

3) The number of people cannot be a decimal, 7:8 can have many answers.

Further up. That's more than 60 people.

I brushed one side of all 3 planks for 3 minutes, then waited 1 minute, and 4 minutes passed. Start brushing directly from the first board, and one minute per block is 3 minutes, a total of 3+3+1=7 minutes.

1..The big double got the remaining half of the more than 5 pieces, just after the division, indicating that 5 pieces are the remaining half, then the big double, 5 * 2 10, the small double got one half of the more than 5 pieces, indicating that the big double, plus 5 is half of the total, (10 + 5) * 2 30

There are 30 pieces of sugar in total.

(5 ÷ 1/2)+5) ÷1/2=302.After 4 days, two-fifths of the total length was repaired, and one-fifth of the total length was not repaired, indicating that the total length (1-2 5-1 5) = 2 5, ., was repaired in the first 4 days25 meters per day, 4 * 25 100 in 4 days, 100 (2 5) = 250 (meters), the road is 250 meters long.

4*25 2 5=250 (m),

Solve the second question first. 25*4=100m The total length minus two-fifths of the later repairs and subtracting the remaining one-fifth is equal to 100m repaired

So let's say that the total length is x 100 + 2/5 + 1/5 = x

As a result, the road is 250 meters long, and you see that I am right.

11, the first layer is definitely 9, and the second layer can put one on each of the square diagonal of the first layer, so at least 11.

9, to explain the top view of the question, put two small cubes on the right side of the first row of the top view, that is, the small cube in the upper right corner, and put a small cube on the first small cube in the second row, a total of 6 + 2 + 1 = 9.

If the length is reduced by 3 centimeters, the width and height remain the same, its volume is reduced by 39 cubic centimeters. That is: width and height = 39 3 = 13

If the width is increased by 2 cm, the length and height remain the same, his volume is added by 58 cubic centimeters. That is: length height = 58 2 = 29

If the height is increased by 5 centimeters, the length and width remain the same, and his volume is added by 105 cubic centimeters, i.e., length and width = 105 5 = 21

The surface area of the original cuboid is: (length and width + length and height + width and height) 2 = (21 + 29 + 13) 2 = 126

4.The edge length of the middle cube is 4 2, and the edge length of the bottom cube is 8

The surface area of the bottom cube = 6 * 8 * 8 = 384

The cube in the middle minus the calculated surface area = 4 * 4 2 * 4 2 = 256

The above cube minus the already calculated surface area = 4 * 4 * 4 = 64

The surface area of this cube shape = 384 + 256 + 64 = 704

There are 2 layers, the first layer, 9 in the top view, the second layer, the 9, and one on each of the four corners. 3 3 + 4 = 13 (pcs).

3 layers, the first layer, 6 in the top view, 3 in the second layer, one in the upper right corner of the top view, adjacent to it, on the right-angled edge.

of each one. 1 on the third layer and 1 in the upper right corner of the top view.

3. The length is reduced by 3 cm, the width and height remain the same, and its volume is reduced by 39 cubic centimeters. That is: width and height = 39 3 = 13

The width is increased by 2 cm, the length and height remain the same, and his volume is added by 58 cubic centimeters. That is: length height = 58 2 = 29

The height is added by 5 centimeters, the length and width remain the same, and his volume is added by 105 cubic centimeters, that is: length and width = 105 5 = 21

The surface area of the original cuboid is: (length and width + length and height + width and height) 2 = (21 + 29 + 13) 2 = 126

The volume of the original box is: Length, Width, Height= (Length, Width, Height, Height).

4. The surface area of the top cube is: 4 4 5 = 80 (square decimeters).

The edge length of the middle cube is: 2 (4 4 2) = 2 8 = 32

The surface area of the middle cube is: 32 32 5 - 4 4 = 144 (square decimeters).

The surface area of the bottom cube is: 64 6 - 32 = 352 (square decimeters).

The total is: 80 + 144 + 352 = 576 (square decimeters).