Why is the midpoint potential of the equivalence negative charge line the highest, while the equival

The so-called potential energy can be understood as a certain tendency to do work or capital converted into other energy, for example, the higher the object above the ground, the higher the gravitational potential energy, which means that the more work that gravity does on the object when the object lands or the greater the kinetic energy of the object.

The electric field at the midpoint of the line connecting the same positive charge is zero, and there is no force on the charge placed in it, and it does not have the capital to do work, so the electric potential is the lowest. In the same way, the electric field at infinity of the middle perpendicular line is zero and the electric potential is lowest.

Due to the symmetrical distribution of the electric field, the direction of the resultant electric field acting on the charge is along the direction of the middle perpendicular line, and the Coulomb force is produced on the charge, and the potential energy is continuously converted into kinetic energy, and theoretically until the infinity potential energy is zero, the potential energy will be converted into kinetic energy.

Based on the above analysis, it should be said that the potential energy is the highest at the midpoint of the slight deviation from the connecting line on the perpendicular line.

The electric potential is reduced in the direction of the electric field lines. Let's take a look at the electric field lines in these two cases.

1. The potential of the midpoint of the equal negative charge line and the infinity point is the same. The potential at infinity is the highest, so the potential at the midpoint of the line of an equal amount of negative charge is the highest.

2. The midpoint of the equivalence positive charge line is also the same as the electric potential at infinity. The potential is lowest at infinity, so the potential at the midpoint of the line of equal positive charges is the lowest.

Kiss. Please don't forget to be in time.

This question is discussed in two cases (the previous broad argument is that the electric potential at infinity is assumed to be zero).

1. For an equal amount of positive charges, the potential on the line of the two charges is the smallest at the midpoint, and this minimum is only with them.

Compare other points on the line; The field strength at the midpoint of the line is the largest on their perpendicular line, which is only compared to the other points on their perpendicular.

2. For the same amount of negative charge, the potential on the line of the two charges is the largest at the midpoint; On their mid-perpendicular line, the potential at this point is again the smallest.

Assuming that the 2 charges are placed horizontally, with the midpoint O as the boundary, the combined field strength on the left side of the O point on the connection line is horizontally to the right, which can be equivalent to an electric field line horizontally to the right, and the potential along the electric field line is getting lower and lower, then the potential at point O is the lowest. In the same way, the combined field strength of the right half of the line at point O is horizontally to the left, and the potential of point O is still the lowest.

It can also be understood in this way: in addition to the point o on the line of the two positive charges, a positive charge is released at any stationary station, and it can be judged that the positive charge accelerates first and then decelerates, and the kinetic energy is the highest at the o point, and the potential energy should be the lowest if the energy is conserved. Where the positive charge is low in potential energy, the electric potential is low.

The electric potential is zero at infinity. The perpendicular bisector (surface) of the two positive charges is an equipotential surface, which leads to infinity, i.e., is equal to the infinity electric potential, so it is zero. Minimum.

Your question is not right. The electric potential at the midpoint is not the lowest.

However, the electric field strength is the lowest, and the electric field strength is equal to zero.

The team will answer for you.

According to the potential superposition theorem, the electric potential is highest at the midpoint of the line and lowest at infinity.

The characteristics of the electric field distribution on the perpendicular line of the same positive point charge line of equal magnitude are as follows: with the minimum of the midpoint being zero, the field of any two points symmetrical about the midpoint is strong and small, and the direction is opposite, and both point to infinity along the perpendicular line; The potential decreases progressively along the electric field line, so it is at the midpoint that the potential is the highest.

From the aspect of functional relationship, the tentative charge of one positive is moved along the perpendicular line of the two positive charge line to the middle line of the line, and the resistive force is overcome, so the midpoint potential of the connection line is the highest.

Happy learning!

No, according to the electric potential decreases with the direction of the electric field line, the above sentence is completely unfounded, whether it is a positive or negative charge.

Because the positive and negative properties of a point charge are not stated, this statement is wrong.

Analysis: If the electric potential at infinity is 0, then the total electric potential of each point can be obtained by the principle of potential superposition.

If the electric charge of these two equal charges of the same kind is q (plus or minus) and the distance between them is l, then the total electric potential at the distance of one of the charges on their line is u (kq r) [kq (l r ) where q is plus or minus.

When q is positive (the point charge is positive), it is easy to see that when r l 2, u is positive and u has a minimum.

That is, on a positive point charge line of the same amount, the potential at the midpoint is the lowest. Correctly when q is a negative value (the point charge is a negative charge), it is easy to see that when r l 2, u is a negative value, but the absolute value of u has a minimum value, that is, at the midpoint of the line, the electric potential (including positive and negative) is not the lowest.

That is, on the point charge line of the same negative of the same amount, the potential at the midpoint is the lowest. Mistake.

If you leave the midpoint, you will be close to one of the charges, and the potential will be high.

This point potential is not the lowest, if you choose an infinite point with a potential of zero, the potential of this point is 2kq r, where q is the charge charge, k is the electrostatic force constant, r is the distance from the midpoint of the line to the charge, no matter which point is the zero potential point selected, you can always find a lower potential than this point, but the electric field strength of this point is zero.

Is the potential of the contour line in the middle of a negative charge 0?

Answer: If the positive charge is equal to the negative charge and the amount of electricity with it, but only the difference between the positive and negative signs, then the perpendicular bisector of their lines.

It is a potential line with an electric potential of 0 everywhere, which is actually an equipotential surface.

If they are overpowered, the absolute value of the charge.

If they are not equal, then there is a curve on their connecting line, strictly speaking, it should be a curved surface, and the potential of each electricity on it is 0.