Two questions won t be done, help

Updated on educate 2024-05-27
15 answers
  1. Anonymous users2024-02-11

    kmLet the speed of the jeep be xkm hours, then the speed of the large truck is (3 4)x2x+2*(3 4)x=375-6

    x=2.It is necessary to add x kg of water.

    8%*400=5%*(400+x)

    x=240

  2. Anonymous users2024-02-10

    15*2500000=s1

    Let the speed of the jeep be x, and the speed of the big truck is 3 4x, then the equation is s1-6000=2*(x+3 4x), and finally calculate x, and 3 4x.

  3. Anonymous users2024-02-09

    It will be a topic of elementary school

    Oh. 15*2500000=37500000 (cm) 375 (km).

    375-6) 2=km).

    And then it was forgotten.

    The following set of formulas for concentration questions will do.

  4. Anonymous users2024-02-08

    Question 1: (15*25 6) [(1 3 4)x]=2 where x is the speed of the jeep.

    Question 2: Set x grams.

  5. Anonymous users2024-02-07

    It's going to be easy.

    Is the landlord an elementary school student? ~

  6. Anonymous users2024-02-06

    1 2,500,000 = 25 km.

    25 x 15 = 375 km.

    375-9 = 369 km.

    369 2 = kilometers.

    2 (400*8%) 5%-400 240g.

  7. Anonymous users2024-02-05

    I don't have scratch paper in the computer room, I can't do the math.

    It looks like it's very simple.

  8. Anonymous users2024-02-04

    Analysis: 1. Car A is faster than car B, when the two cars meet, car A has exceeded the midpoint of AB and 40 kilometers, and car B has 40 kilometers to the midpoint of AB and 2.

    2. The time from the departure of car A and car B to the meeting is equal.

    According to the title, the distance between the two places is x kilometers.

    Solve equations. x 1800 km.

    ab The two places are 1,800 kilometers apart.

  9. Anonymous users2024-02-03

    Glad to answer for you in detail.

    2 yes, he is.

    3 she is a chinese teacher.

    4 no, he isn't.

    5 she is a housewife .

  10. Anonymous users2024-02-02

    are five people in 's family.(His parents, his wife and his son).

    he is.

    3.(Ask him about his wife's occupation, the answer is in the fifth sentence) she is a chineses teacher

    4.(Ask him if his son's Japanese is good, the answer is in the last sentence) no, he isn't.

    5.(Ask him about his mother's occupation, what does his mother do, the answer is in the fourth sentence) she is a housewife

  11. Anonymous users2024-02-01

    Full text translation:

    Mr. Lu went to Japan last year. He went with his extended family, which included his parents, his wife, and his son. Mr. Lu's father is retired.

    His mother was a housewife. His wife is a Chinese teacher. She teaches Chinese in Japan.

    His son, Lu Xiao, is a primary school student. But he is not very fluent in Japanese.

    Topic: 1. How many people are in Mr. Lu's family?

    There were five parents, a wife, a son, and myself.

    2. Is Mr. Lu's father retired?

    3. What does Mr. Lu's wife do?

    4. Does Lu Xiao speak Japanese very well?

    5. What does Mr. Lu's mother do?

  12. Anonymous users2024-01-31

    Cuboid: Shadow = 1:1 4 = 4:1

    Cuboid: Shadow = 1:1 6 = 6:1

    Cuboid: Small cuboid = 6:4 = 3:2

    Let the original numerator be x and the denominator be 3x

    3x-x=28

    2x=28x=14

    This score is 14 42

  13. Anonymous users2024-01-30

    1. The area of the large and small rectangles is a and b respectively

    a*1/6=b*1/4

    a:b=6:4=3:2

    2. If the numerator is a, the denominator is 3a

    3a-a=28

    a = 14 with a score of 14 42

  14. Anonymous users2024-01-29

    (The area of their overlapping parts is equal to 1 4 of the area of the small rectangle, and equal to 1 6 of the area of the large rectangle).

    1 solution: Let the areas of the large and small rectangles be x, y, respectively;

    Then: 1 4*y=1 6*x solution x:y=3:22 Let the fraction be x y, and the problem gets: x-y=28, x:y=1:3. The solution is x=-14, y=-42

    So the original score is -14 -42

  15. Anonymous users2024-01-28

    The circumference of a circle enclosed by a rope one meter long is the length of the rope - one meter. The radius is calculated backwards by the perimeter formula, and then the area is calculated.

    The same goes for the rest of the circles.

    Outside the road is actually a ring. The area of this ring = (flowerbed area + road area) - flowerbed area. (Flower bed area + road area) is a large circle, and its radius is the flower bed radius + 2.

    The radius of the flower bed can be calculated backwards from the known perimeter meter, and the area of the flower bed can be calculated by knowing the radius. The capital is 200* road area.

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