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1 This car is if.
It is mentioned in the original text: if there is a car
2 The little black cat said, "Meow."
d I often read bad jokes
There is a broadcast in the entertainment star world
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1 This car is if.
It is mentioned in the original text: if there is a car
2 The little black cat said, "Meow."
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1 car is the driver's!
2 spoke"Meow"
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1.The car is "if" because the question mentions: if there is a car ......
2.The little black cat said: Meow ......Because cats only say this.
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Answer to the first question: The car is if.
Answer to Question 2: The night gave me black eyes, but I rolled my eyes with him.
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1.The car is if.
2.He said, "Meow."
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1 This car is"If"Target.
Because "if" there is a car.
2 The little black cat said, "Meow."
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1 Little Red 2 How did you turn black.
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1 car is the driver's!
2 Little Black Cat: "Meow".
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1 This car is if.
2 The little black cat said, "Meow."
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1.(if) there is a car, Xiao Gang sits in the driver's seat, Xiao Ming sits in the passenger seat, Xiao Hong does the back row alone, and Xiao Zhang sits in the trunk. Q: Whose cars are they??
The car is if.
2.The little black cat fell into the water, and the little white sketch pulled him out, and the little black cat said a word to him and asked the little black cat what he said??
The little black cat said: Meow ......
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Haha: That's interesting.
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1 Zhang's was kidnapped.
2 meow - 1 This car is if.
It is mentioned in the original text: if there is a car
2 The little black cat said, "Meow."
1 car is the driver's!
2 spoke"Meow"
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Damn, it won't, the car is if Khan.
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1 Zhang's was kidnapped.
2 Meow
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The difference in birthday date is a multiple of 7.
If the difference is 7 Xiao Ming = (36-7) 2=
It is impossible so the difference is two weeks, 14 days.
Xiao Ming's birthday = (36-14) 11th.
Little Red's birthday is March 25th.
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Set Xiao Ming's birthday to be March x.
Set Xiaohong's birthday to be March Y.
0y-x=7k (1)
x+y=36 (2)
y=18+<=31
k<=26/7
k is an even number. So k=2
x=11,y=25
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1 Four chopsticks are put together, one pair is stacked on top of the other, the chopsticks have two ends, one end is round, the other end is square, and the square end is a Tian character.
2 to buy 2 taels of salt, a total of 3 jiao 4 cents, rounded to 3 jiao, buy 5 times you can buy enough a catty, and as long as the yuan, the remaining 2 jiao can buy a pack of matches Oh 3
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Four matches in a square and aligned, head to head and tail to tail. From the tail, it looks like the four chopsticks of the word Tian are held together, and the one on the side is the word Tian!
To buy 2 taels of salt, it costs a total of 3 jiao and 4 cents, rounded to 3 jiao, and you can buy enough for a catty if you buy 5 times, and as long as you have yuan, the remaining 2 jiao can buy a pack of matches 49
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Let's start with x coconuts, and let's write x as (x+4) 4
The first man came and gave 1 to the monkey, and at this time a coconut.
x+4) 4 1=(x+4) 5, which can be divided into exactly 5 portions, and the number of coconuts in each serving is.
x+4)-5]/5=(x+4)/5-1
x+4) 5 must be an integer, so (x+4) is a multiple of 5, and after the first person takes a portion, the remaining coconut is:
4/5)×[x+4)-5]=(4/5)×(x+4)-4
Again, the second man came, gave 1 to the monkey, and after taking a portion, the remaining coconuts numbered.
4/5)×[4/5)×(x+4)-5]
Since (4 5) (4 5) (x+4) is an integer, (x+4) should be a multiple of 5 5 25, so that five people take one point at a time, and there is exactly one left.
x+4)-5 coconuts, so (x+4) must be a multiple of 5 5 5 5 5, i.e. x+4 = 5 5
So: x=3125-4=3121
That is, there is a minimum of 3121 coconuts at the beginning.
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This pile of coconuts has at least 15621
The first man gave 1 monkey, 3,124 hidden, and 12,496 remained;
The second man gave 1 to the monkey, hid 2499, and left 9996;
The third man gave 1 monkey, hid 1999, and left 7996;
The fourth man gave 1 monkey, 1599 hidden, and 6396 remained;
The fifth man gave 1 monkey, 1279 hidden, and 5116 remained;
In the end, everyone divided it into 5 portions, 1023 pieces each, 1 more, and gave it to the monkey.
You first use six sticks to make 2 equilateral triangles, and then you can overlap the 2 equilateral triangles on top of each other to create an equilateral triangle. You can't have a sticker on it, I don't know if I'm making it clear.
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