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Both the phenolic hydroxyl group and the carboxyl group on C6H4OHCOOH react with Na2CO3, but Na2CO3 reacts with the phenolic hydroxyl group to form -ONA and NaHCO3, while the carboxyl group produces CO2 and water.
Hence the reaction equation:
2c6h4ohcooh+2na2co3=2c6h4onacoona+co2+h2o
You can't play the structural formula.,You're going to just look at it.。。。
If there's anything else you won't do, you can keep asking me.
Addendum: But the key is how do you know that -OH reacts with Na2CO3 first, and the resulting NaHCO3 reacts with -CoOH? The solution has Na2CO3 at the beginning, and -COOH is more acidic than the phenolic hydroxyl group, so -COOH reacts with salicylic acid first, and at the same time as the reaction, -OH also reacts with Na2CO3, but it will not appear as you said:
OH reacts with Na2CO3 first, and after the reaction is over, NaHCO3 is generated and then reacts with -CoOH, because at this time, -CoOH has already reacted with Na2CO3!
The kind you are talking about should theoretically work (unless you control the reaction condition called -cooh and don't react with Na2CO3 first, but it should be difficult to control this condition...).
Do you understand? Well, I made a mistake.
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This kind of question starts with the ranking of acidity and alkalinity.
Acidic: AR-COOH > H2CO3 > AR-OH > H2O) >HCO3[-].
Basic: ar-o[-]CO3[2-] HCO3[-]ar-coo[-].
If there is too much sodium carbonate, the carbonate first binds to the protons ionized by the carboxyl group and is converted to bicarbonate, and the remaining carbonate is combined with the protons ionized by the hydroxyl group to get the bicarbonate as well.
The equation is C6H4OHCooh + 2 Na2CO3 ==== C6H4ONACOona + 2 NaHCO3
If there is an excess of salicylic acid, the previous process is the same as above, and the phenolic anion will bind to the protons ionized by the carboxyl group.
The equation is 2 C6H4OHCooh + 2 Na2CO3 ==== 2 C6H4OHCoOnA + 2 NaHCO3
Because the ratio of carboxyl to hydroxyl groups is 1:1, no CO2 is formed from beginning to end.
If there are more carboxyl groups than hydroxyl groups, CO2 is formed
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The sodium bicarbonate solution reacts with dilute sulfuric acid to produce sodium sulfate, water, and carbon dioxide.
The chemical equation that occurs:
2nahco3 + h2so4 = na2so4 + 2h2o + 2co2 ↑
For the ionic equation:
h+ +hco3- =h2o + co2↑ .
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h+ +hco3-==h2o+co2↑。
The role of sodium bicarbonate.
1. This property is often used as a leavening agent in the food production process. Sodium bicarbonate will remain sodium carbonate after action, and too much use will make the finished product have an alkaline taste.
2. Excessive stomach acidity.
3. Used in film production, tanning, mineral processing, smelting, metal heat treatment and fiber, rubber industry, etc.
4. It can be compounded with alum to make alkaline baking powder.
5. It can be used as a butter preservative.
6. Fire-fighting equipment is used to produce acid and alkali fire extinguishers and foam fire extinguishers.
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The reaction of sodium bicarbonate solution with dilute sulfuric acid is the reaction of acid salts and acids to produce carbon dioxide gas and water, and the ion equation is:
hco3- +h+ =co2+h2o
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Salicylic acid: C7H6O3, sodium carbonate Na2CO3
Salicylic acid is o-carboxic acid phenol.
The phenolic hydroxyl group is combined with sodium carbonate to produce sodium phenol and sodium bicarbonate.
Formic acid and sodium carbonate produce sodium acid and carbon dioxide and water.
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This kind of topic.
Sort the acidity and alkalinity first.
Acidic: AR-COOH
h2co3ar-oh
h2o)hco3[-]
Basic: ar-o[-].
co3[2-]
hco3[-]
ar-coo[-]
If there is an excess of sodium carbonate.
The carbonate first binds to the protons ionized by the carboxyl group.
Converted to bicarbonate.
The remaining carbonate binds to the protons ionized by the hydroxyl group.
Bicarbonate is also obtained.
The equation is. c6h4ohcooh+2
na2co3
c6h4onacoona+2
nahco3
If there is an excess of salicylic acid, the previous process is the same as above, and the phenol anion ions will combine with the carboxyl group ionization to ionize the proton equation is.
2c6h4ohcooh+2
na2co3
2c6h4ohcoona+2
nahco3
Because the ratio of carboxyl group to hydroxyl group is 1:1, there is no CO2 formation from the beginning to the end, and if there are more carboxyl groups than hydroxyl groups, CO2 will be formed
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1) Equation for the reaction of sodium bicarbonate and sulfuric acid.
2nahco3 + h2so4 = na2so4 + 2co2(g)+2h2o
2) Reaction ion equation between sodium bicarbonate and sulfuric acid.
hco3- +h+ =co2(g)+h2o
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The chemical equation for the reaction of sodium bisulfate and sodium bicarbonate: NaHSO4+NaHCO3==NA2SO4+H2O+CO2 Ion equation: HCO3
h+=h2o+co2↑
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Chemical equation: NaHCO3
nahso4
na2so4
H2OCO2 ion equation: HCO3-+H+
h2oco2↑
Sodium bisulfate is equivalent to a strong acid of one element, which can ionize H+ and react with the weak acid group HCO3- to obtain CO2
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The chemical equation for the reaction of sodium bicarbonate solution with dilute sulfuric acid is given below:
2nahco3+h2so4=na2so4+2h2o+2co2↑
The ionic equation for the reaction of sodium bicarbonate solution with dilute sulfuric acid is given below
hco3- +h+ = h2o + co2↑
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Salicylic acid is an organic compound with the chemical formula C7H6O3, which can react with sodium to form phenol and carbon dioxide. The reaction equation is as follows:
c7h6o3 + 2na → c6h5oh + na2co3
Among them, C7H6O3 represents salicylic acid, 2Na represents two sodium atoms, C6H5OH represents phenol, and Na2CO3 represents sodium carbonate. In the reaction, salicylic acid and sodium undergo a displacement reaction to produce phenol and sodium carbonate.
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Salicylic acid (also known as sodium salicylate, chemical name is sodium 2-hydroxybenzoate) and sodium reaction equation such as Woolun lead:
2C7H6O3 + 2Na ->2C7H5O3Na + H2 Where, C7H6O3 is the chemical formula of salicylic acid, Na is the symbol of sodium, C7H5O3Na is the chemical formula of sodium salicylate, and H2 is the hydrogen tung gas.
This reaction is a chemical reaction between salicylic acid and sodium to produce sodium salicylate and hydrogen. Sodium salicylate is the sodium salt of salicylic acid, which is often used in the pharmaceutical cavity and cosmetics industry.
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Whether sodium bicarbonate reacts with a sufficient amount or a small amount of hydrogen sodium oxide solution, it is either a round ion equation.
Sodium bicarbonate reacts with a small amount of sodium hydroxide ion equation:
oh-+hco3-=h2o+co3
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Because the reaction of sodium carbonate with dilute hydrochloric acid is carried out in two steps: the first step: Na2CO3+HCl=NaHCO3+NaCl The second step:
NaHCO3+HCl=NaCl+H2O+ CO2 Only when the first step reaction occurs completely will the second step reaction occur, and the second step reaction will occur after a certain time, so the reaction between Na2CO3 and dilute HCl is not to release CO2 immediately, but to attack the reaction for a while before generating gas.
The structural formula is as follows:
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