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Updated on educate 2024-05-15
9 answers
  1. Anonymous users2024-02-10

    CaCO3 reacts with carbon dioxide to form CaHCO3 that dissolves in water

    Calcium hydroxide can generate up to 10g of precipitate, so the formation of 8g may be due to insufficient CO2, or it may be due to excess CO2, which reflects some CaCO3 precipitate.

  2. Anonymous users2024-02-09

    Ca(OH)2+CO2==CaCO3+H2OCAco3+CO2+H2O==Ca(HCO3)2 calcium hydroxide, calcium carbonate.

    It could be: Ca(OH)2+CO2==CaCO3+H2O. Ca(OH)2+CO2==CaCO3+H2OCAco3+CO2+H2O==Ca(HCO3)2 is consumed in this case, which is converted to a volume greater than.

  3. Anonymous users2024-02-08

    Because: when CO2 is low, the following reaction occurs: Ca(OH)2 + CO2 = CaCO3 + H2O

    When CO2 is high, the precipitated CaCO3 reacts with CO2: CaCO3 + H2O + CO2 = 2Ca (HCO3).

    And Ca(HCO3) is soluble, so the 8g precipitate is not sure if it is all CaCO3 understand?

  4. Anonymous users2024-02-07

    The calcium hydroxide can produce up to 10 calcium carbonate precipitates, now only 8

    Moreover, calcium carbonate in the case of excess carbon dioxide, will produce calcium bicarbonate, which is a dissolvable substance, now only 8, can not be sure what the amount of carbon dioxide is, more, less, can be.

  5. Anonymous users2024-02-06

    CO2 is introduced to produce calcium carbonate, and if it continues, calcium carbonate will produce calcium bicarbonate.

  6. Anonymous users2024-02-05

    Assuming that the gas happens to be all calcium carbonate produced by calcium hydroxide, it should be 10 gThe relationship between 1 to 2 is obtained from the equation. Therefore, in the case of insufficient gas, the calcium hydroxide is still unreacted, and it may only be precipitated by 8 g; Or there is an excess of gas, which partially produces calcium bicarbonate, which makes the precipitate less than 100g

  7. Anonymous users2024-02-04

    A gram has b because the molar mass of water is 18

    So 18 grams of water has 18b a hydrogen atoms, which is two moles, and the number of one mole is 9b a and b

  8. Anonymous users2024-02-03

    a 18*2*n=b,n=9b a (* for multiplication).

    18 is the relative atomic mass of water, a 18 to find the molar mass of a gram of water, multiply by n (Avogadro's constant) to find the number of water molecules contained, and multiply by 2 to calculate the number of hydrogen atoms contained. Complete.

  9. Anonymous users2024-02-02

    2co+o2=2co2

    2h2+o2=2h2o

    The reaction ratio of Co, H2 and O2 is 2:1

    So the original gas O2 20ml

    co+h2 40ml

    The average relative molecular mass of the product is the volume fraction of H2 in the product gas is x

    18*x+44*(1-x)=

    x=1 4, so the volume ratio h2 co=1:3

    Because the volume fraction of H2 plus CO in the raw gas is 2 3

    So the volume fraction of H2 in the original gas is 1 4 * 2 3 = 1 6

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