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CaCO3 reacts with carbon dioxide to form CaHCO3 that dissolves in water
Calcium hydroxide can generate up to 10g of precipitate, so the formation of 8g may be due to insufficient CO2, or it may be due to excess CO2, which reflects some CaCO3 precipitate.
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Ca(OH)2+CO2==CaCO3+H2OCAco3+CO2+H2O==Ca(HCO3)2 calcium hydroxide, calcium carbonate.
It could be: Ca(OH)2+CO2==CaCO3+H2O. Ca(OH)2+CO2==CaCO3+H2OCAco3+CO2+H2O==Ca(HCO3)2 is consumed in this case, which is converted to a volume greater than.
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Because: when CO2 is low, the following reaction occurs: Ca(OH)2 + CO2 = CaCO3 + H2O
When CO2 is high, the precipitated CaCO3 reacts with CO2: CaCO3 + H2O + CO2 = 2Ca (HCO3).
And Ca(HCO3) is soluble, so the 8g precipitate is not sure if it is all CaCO3 understand?
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The calcium hydroxide can produce up to 10 calcium carbonate precipitates, now only 8
Moreover, calcium carbonate in the case of excess carbon dioxide, will produce calcium bicarbonate, which is a dissolvable substance, now only 8, can not be sure what the amount of carbon dioxide is, more, less, can be.
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CO2 is introduced to produce calcium carbonate, and if it continues, calcium carbonate will produce calcium bicarbonate.
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Assuming that the gas happens to be all calcium carbonate produced by calcium hydroxide, it should be 10 gThe relationship between 1 to 2 is obtained from the equation. Therefore, in the case of insufficient gas, the calcium hydroxide is still unreacted, and it may only be precipitated by 8 g; Or there is an excess of gas, which partially produces calcium bicarbonate, which makes the precipitate less than 100g
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A gram has b because the molar mass of water is 18
So 18 grams of water has 18b a hydrogen atoms, which is two moles, and the number of one mole is 9b a and b
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a 18*2*n=b,n=9b a (* for multiplication).
18 is the relative atomic mass of water, a 18 to find the molar mass of a gram of water, multiply by n (Avogadro's constant) to find the number of water molecules contained, and multiply by 2 to calculate the number of hydrogen atoms contained. Complete.
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2co+o2=2co2
2h2+o2=2h2o
The reaction ratio of Co, H2 and O2 is 2:1
So the original gas O2 20ml
co+h2 40ml
The average relative molecular mass of the product is the volume fraction of H2 in the product gas is x
18*x+44*(1-x)=
x=1 4, so the volume ratio h2 co=1:3
Because the volume fraction of H2 plus CO in the raw gas is 2 3
So the volume fraction of H2 in the original gas is 1 4 * 2 3 = 1 6
Generally speaking, an outer electron number of 8 is a stable structure, and atoms have a tendency to make their outermost electrons become 8-electron stable structure. The X element with an outer electron number of 3 can gain 5 electrons or lose 3 electrons (the subouter shell is generally 8 electrons) can make itself a stable structure with the outermost shell of 8 electrons, because it is much more difficult to get 5 electrons than to lose 3 electrons, so it often loses the outermost 3 electrons and becomes a stable structure with the outermost 8 electrons, showing a valency of +3 valence. >>>More
Alkaline Therefore, c(oh-)>c(h+) a is wrong.
Soluble in water alkaline, it is its weak acid S2 - step by step hydrolysis and the production of OH- makes the solution alkaline, these OH- all come from water, and only for the aqueous solution, there is C (OH-) = C (H+) and H+ in the solution in the form of Hs- H2S H+, so option B: >>>More
Because LNA2CO3 reacts with BACl2 to form BAC3, and NA2SO4 reacts with BACl2 to form BASO4 >>>More
1: Choose a and take a closer look at the definition of relative atomic mass. >>>More
NO2 may be 30ml or.
Analysis: There are two scenarios. The remaining gas may be O2, and the reaction is carried out according to 2H2O+4NO+3O2=4HNO3 and 2H2O+4NO2+O2=4HNO3, and all NO2 and NO2 are reacted. >>>More