Theoretical questions about memory

Updated on number 2024-05-24
6 answers
  1. Anonymous users2024-02-11

    Bit width is not the amount of data sent by memory in a clock cycle, the unit of bit width is bit, which is how many data channels there are between memory and memory controller, which is a fixed value. The unit of bandwidth is bit s, which is the amount of data transferred per unit of time.

    Let's be clearer, the concept of frequency 800MHz is that the speed of sending data on each bit-width channel is 800MB s, then the speed at 64 bit-width is 800MB s 64 51200MB s, which is converted into byte units of 51200MB s 8. This is the bandwidth, which indicates the amount of data transferred per unit of time.

  2. Anonymous users2024-02-10

    That's how I understand it, the number of bits is 64, that is, there are 64 data wires, DDR800, the frequency of each wire is 200, it reads 4 signals at a frequency, so the effective frequency is 800 Then the signal read and written per second is 200 * 64 * 4 = 51200m signals, which is 51200mhz, then every 8 signals is a byte, then divide by 8, which is equal to 6400m bytes, which is a bit similar to a road with 64 lanes, if it is a dual channel, the memory channel will become 128, then the total bandwidth will be doubled

  3. Anonymous users2024-02-09

    Bandwidth = Frequency * Bit Width 8

    Calculation of the bandwidth of DDR2 800 = 800MHz * 64bit 8 = 6400MB s

    Calculation of the bandwidth of dual-channel DDR2 800 = 800MHz * 64bit * 2 8 = 12800MB s

    The bit width is equivalent to the channel, and the dual channel is equivalent to double the bit width.

    I don't want to explain the rest, I suggest you look at the composition of computers or the principles of microcomputers.

    Your problem is that 64bit does not represent the amount of data transmitted in a clock cycle, it indicates how many bits can be transmitted at most by the memory bus to transmit data at one time, so the problem is simple, there are 64 lines in total, and the high and low level changes mean that the data is transmitted once, and the maximum can be 64bit, so the bit width is 64.

  4. Anonymous users2024-02-08

    It seems that the landlord has learned the principles of computer composition and electronic technology very well, right?!

    Understand what is something like bit width ...

    The emergence of any new technology is always that the current technology can not meet the current needs, or there are market prospects, so engineers will focus on solving various technical bottlenecks.

    For us end users, these things are just a matter of knowing a rough idea of what. There's no need to get it too thoroughly, otherwise it's easy to do with just one storage unit.

  5. Anonymous users2024-02-07

    Nonsense, I research DIY thinking about what to do with this. It's good to know that DDR2-800 is better than 667.

  6. Anonymous users2024-02-06

    Cow is completely heavenly. The landlord is strong

Related questions
8 answers2024-05-24

The above is so detailed!!

7 answers2024-05-24

The first thing to say is that the DDR memory specification does not have DDR300, the closest to it is DDR333, if you buy 512M DDR 400 specification memory and your 256M DDR266 memory at the same time. >>>More

9 answers2024-05-24

Wave theory is just an ideal standard form, and it does not have much operational significance in actual combat. What we usually do is just to judge whether it is similar to the god and not the likeness. And this theory, the same graph, different people can count different waves, what do you say is the practical significance of that? >>>More

8 answers2024-05-24

Try tuning up your virtual memory:"My computer" "attributes", point"Advanced" .Again"Performance"of"Settings". >>>More

6 answers2024-05-24

First of all, the memory of DDR2 800, it runs at a frequency of 400, and 800 is just the equivalent frequency. >>>More