A buoyancy question those interested come in .

d.The buoyancy experienced by an object is equal to the weight of the liquid it dispels. But this 10n of water is not the water that is discharged by the object, but the remaining water, so a force greater than 10n can be generated.

The key is to make the pressure generated by the remaining water and the bottom area of the buoyant object meet the gh*s>10n, and the buoyancy generated is greater than 10n. Specifically, the gap between the container and the object is required to be small enough so that the height of the water surface from the bottom of the object is high enough.

d can be greater than 10n. The amount of buoyancy is determined by the volume of water dislodged (gravity), in other words, as long as an object dispels more than 1 liter of water (about 10n) in the water, the buoyancy force will be greater than 10n.

d can be greater than 10n. The amount of buoyancy is determined by the volume of water discharged, and if an object displaces more than 1 liter of water (about 10n) in the water, the buoyancy will be greater than 10n.

If you are interested, you can take a look at Pascal's law, also known as the principle of hydraulic presses, which discharges the volume of water, not pressure or pressure.

c.If there is only 10n of water, the buoyancy generated is less than 10n, but if it is put together with other water, it is fine.

It is all used to generate buoyancy, so the maximum is 10N.

Because f=g

d.See if the water is sufficient, because buoyancy looks at the volume of the discharge.

The buoyancy produced by d has nothing to do with the gravity of the water.

The volume of water discharged is related to the density of the water, and as long as the container is suitable, 10N of water can produce much more buoyancy than 10N.

In question, h'and h are the bottom of the container, and for other analysis objects, in the above analysis, they also try to convert to the bottom of the container as the reference.

h1 is the depth at which the tube sinks, and its direction is downward, and this depth is based on the water surface in the vessel. However, the height of the water surface inside the container also changes. The direction is upwards and the value is h2.

As a result, the bottom of the tube is lowered relative to the bottom of the vessel (H1-H2).

The liquid level in the tube rises to h0, which is relative to the bottom of the tube. As a result, the liquid level in the tube rises relative to the bottom of the container - h1-h2)+h0.

So, h'=h-（h1-h2）+h0

Because h0=h1

So, h'=h+h2

Answer: Because ball A is exactly the same as ball B, and the mass of the liquid discharged by B when floating in water is 40g, so.

ma=mb=40g。Therefore, the row bend is divided into options.

When globule A sinks in the fluid of the a, v 1 = 32 g

When the ball B floats in liquid B (5 6V) 2=40g because the ball A is exactly the same as the ball B, so the volume V is equal, and the solution can be 1: 2=2:3, so the bridge banquet C is chosen

Set the volume of ice to v

g ice = f float.

Ice * g * v = water * g * (v-1000) substitute data to find v=10000f float = water * g * (v-1000) = 1 10 3 * 10 * (10000-1000) =

The solution to the problem of buoyancy.

Choice B Because the density of aluminum and iron is greater than that of water, if they are both solid, they will sink, and only when they are hollow, the average density can be less than that of water. A large buoyancy does not necessarily float, and the buoyancy is greater than the gravity before it floats.

When the object floats on the water, the vertical downward gravity of the object is balanced with the vertical upward buoyancy, so the buoyancy is equal to the gravitational force is equal to 20n; The weight of the water discharged by half of the volume of the object floating on the water surface is 20N, and the weight of the water discharged by the whole volume is 40N, that is, the buoyancy force experienced by the object in the total invasion of the water is 40N.

When an object floats on the surface of the water, the vertical downward gravitational force and the vertical upward buoyancy force are balanced, so f float = g = .

Since the volume of the object is only half of the total volume at this time, the weight of the water discharged by half the volume of the object is.

That is, the weight of the water discharged by the entire volume is, so the buoyancy experienced by the object when it is fully immersed in the water is.

(1) The weight of this object is g object = m object g = 2kg *, because it floats on the water surface, so according to the buoyancy force when floating is equal to the gravitational force of the object, that is, f floats 1 = g object =

2) When floating, V row 1 = V object 2, and when submerged, V row 2=V object = 2V row 1, according to Archimedes' principle, F float = G row, then we can know F buoyancy 2 = 2 f buoyancy 1 = 2g object =

(1) When floating, the buoyancy experienced by the object is equal to the gravitational force. F float = g matter = mg = 2kg *

In other words, if this object is to be submerged, it must be subjected to a downward force.