It is known that in Rt ABC, ACB 90, AC BC, BE CE at point E, AD 2 5 cm, DE 1 7 cm, find the length o

Because the angle ACB is 90 degrees.

So the angle BCE is 90 degrees angle ACD

In ADC, the angle DAC is 180 degrees and the angle ADC angle ACD is because the AD is perpendicular to CE

So the angle ADC is 90 degrees.

So the angle DAC is 90 degrees angle ACD

So the angle bce angle cad(1).

And because of the BE vertical CE

So the angle e 90 degrees angle ADC (2).

And because of AC ab (3).

So ADC is all equal to CEB(AAS).

So ce ad , be dc

From the diagram, we can see that DC ce de

So be

Proof: BCE+ ACD= CAD+ACD=90° BCE= CAD

be⊥ce，ad⊥ce

adc=∠ceb

In ADC vs. CEB.

bce=∠cad

adc=∠ceb

ac=bc△adc≌△ceb（aas）

ad=ce,cd=be (the corresponding sides of congruent triangles are equal) ad=,de=

cd=ad-de

be=cd=

B BCE=90° BCE ACD=90° BC= ACD

In the key BCE and Sparrowniper CAD, e= adcb= acd

BC=CA BCE is fully equal to CAD

be=dc= ec=ad=ed=

Hello, it's a pleasure to answer your questions.

Solution: ADC=90°, DCA+ CAD=90° and ACB=90°

dca+∠bce=90°

Leather cad = BCE

CAD= BCE, BEC= CDA=90°, AC=BC ADC is all equal to CEB (corner edge AAS).

ad=ce=

de=ce-cd=

Answer: de=Hope mine is helpful to you. Satisfied, thank you o(o!

Since the ABC triangle is an equilateral right triangle and AC = BC, and because the angle BCE+angle ECA =90 angle BCE+ angle CBE=90, then the triangle ace = triangle CBE, and cbe gives CE =AD=

cd = be

cd = ce – ed = ad – ed = =

Proof: BCE+ ACD= CAD+ACD=90° BCE= CAD

be⊥ce，ad⊥ce

adc=∠ceb

In ADC vs. CEB.

∠bce=∠cad

adc=∠ceb

ac=bc△adc≌△ceb（aas）

ad=ce,cd=be (the corresponding sides of congruent triangles are equal) ad=,de=

cd=ad-de

be=cd=

There are right angles, there are equilateral, purely an isosceles right triangle, so that d, e is coincidental, I guess you have written something wrong in the question, no wonder no one answered Otherwise, you will be pictured above.

Solution: <>

To find the condition of triangle congruence, you can do it by converting the line segments.

No auxiliary lines are required.

Angle E = Angle ADC = 90°

AC = BC because: angle BCE + angle DCA = angle DCA + angle DAC = 90° so angle BCE = angle DAC

So the triangle ADC is all equal to the triangle CEB.

So cd=be ad=ce

Because ad= de= so cd=ce-de= i.e. be=

Because the angle bce and the angle ace are equal to 90

The angle DAC is equal to the angle ACD is equal to 90, so the angle BCE is equal to the angle and the angle DACAC is equal to BC

Angular BEC equals angular ADC equals 90

So the triangle ceb congruence is the same as the triangle cda

Therefore ce is equal to ad and ad is equal to 12

de is equal to 5

So cd is equal to 7

The proband BCE is equal to the CDA

This gives AD=CE

You can find cd=7