A math problem, urgently needed! Please teach a math problem, it is urgently needed!

1) Set: p(x,y).

y=k/x ∴k=xy

S moment = xy = 8

k=8 ∴y=8/x

2) Set: q(x,y).

From the coefficient of the primary term in y=-x+m=-1, we can see that DCO=45°DO=CO, if S QOC=2S QOD

oc*y=2od*x

y=2x and xy=8

x=2 y=4 q(2,4)

3) Correct.

The perpendicular line of the x-axis and the y-axis are respectively e, nnm x-axis.

and hm=gm

hnm≌△mge

The coefficient of the primary term remains unchanged after the translation of the nm=me primary function.

Same as (2) mge=45°

me=eg ∴an=eg

oe=og-eg ph=ob-an

ob=ogoe=ph

oem=∠pnm=90°

oem≌△pnm

pm=ompm om definitely.

There's no way to upload a video, just watch it according to my description)

Typing word by word is very hard and quite detailed, and you should be able to understand "Expecting Extra Points".

Passing by, every time I tried to answer for you, and after knocking, I didn't give any points.

I'm looking for the answer to this question as well

If the ducks on the shore are x, then the ducks in the river are 3x, according to the title.

3x-26=x+26

Solution x=26

So the total number of ducks in this flock is 4x=104. Thank you.

x÷60+x÷90=

3x+2x=

5x=x=x=90 The rule of division:

The law of change of the product: in multiplication, one factor does not change, and the other factor expands (or shrinks) by several times, and the product also expands (or shrinks) by the same multiple.

1: One factor expands by a fold, another factor expands by a fold, and the product expands by a factor ab.

One factor is reduced by a fold, the other factor by a factor of b, and the product by a factor of ab.

Quotient invariant law: In division, the dividend and the divisor expand (or shrink) by the same multiple at the same time, and the quotient does not change.

2: The dividend is enlarged (or reduced) by a time, and the divisor remains unchanged, and the quotient is also expanded (or reduced) by a time.

The dividend does not change, the divisor expands (or shrinks) a times, and the quotient shrinks (or expands) a times.

Some calculations can be made easy by using the law of change of the product and the law of quotient invariance, but in the division with remainders, it is necessary to pay attention to the remainders.

For example: 8500+200=You can divide the dividend and the divisor by shrinking it by 100 times at the same time, that is, 85+2=, the quotient remains the same, but the remainder 1 at this time is reduced by 100, so the original remainder should be 100.

1: 2: 3 = 28:5:3, let one be x

28x+5x+3x=180

x=5∠2=5*5=25

Good luck with your studies.

Untie. The annual electricity bill of the machinery factory before the establishment of Wanyou silver ruler was '1'

Last year's electricity bill = 1 + 1 9 = 10 9 This year's electricity front clearance fee = 10 9 ( 1 - 1 9) = 80 81 million The electricity cost of Huai Machinery Factory this year is 80/81 of the year before last

Solution: The electricity bill for the previous year was x.

1+1 9)x]*(1+1 9).This year's.

x...Last year's.

1+1/9）x]*(1+1/9)

10/9x*10/9

100/81x

Answer: It was 100 81 the year before the limb Zheng Xu.

When 4 is the waist and 5 is the bottom, the first belt, the elder of the Zhou judgment shirt is chong lu.

4×2+5=13cm

While. When 5 is the waist and 4 is the bottom, the circumference is 5 2 + 4 = 14cm

There are two cases: if 4 is the waist, the circumference is 4+4+5=13, and if 5 is the waist, the circumference is 5+5+4=14

Let the distance between the two villages be x, then x 4-x 5=, and x=5km is obtained.

Solution: Let the velocity of A be xkm h and the velocity of B be ykm h and the system of equations:

4x+4y=36

36-6x=2(36-6y)

x=4 y=5

A: The speed of A is 4km h, and the speed of B is 5km h

From the 4-hour encounter, it can be seen that the speed of the two people is 9 kilometers per hour. Then six hours can cover 54 kilometers, and the sum of the remaining distance is twice as much as 36 minus 54 equals 18 kilometers. Of the 18 kilometers, the remaining distance of A is twice as long as the remaining distance of B, so we can find that A has 12 kilometers left and B has 6 kilometers left.

In other words, if A walks 24 kilometers in 6 hours, then his speed is 4 kilometers per hour. And B walked 30 kilometers in 6 hours, and his speed was 5 kilometers per hour.

36 divided by 4 9.

36 2 72 (two men have completed the distance, it should be 2 x 36 km) 72 54 18

18 divided by (1 2) 6

36 12) divided by 6 4

36 6) divided by 6 5