Heroes, help! Poor in math and can t write!! Extra points after writing!!

Updated on educate 2024-05-26
18 answers
  1. Anonymous users2024-02-11

    >5x+3

    2x<-8

    x<-4

    x=m-3,y=5-m

    x>y, i.e. m-3>5-m, m>4

    15. Xiaoying's household water is more than 5cm3

    Set up water with xcm 3

    Then there is (x-5)*2+9 15

    x≥87.There are x rooms.

    8(x-2)<5x+5<8(x-1)

    13 3 And because x is an integer, x=5or6

    When x=5, there are 5*5+5=30 people.

    When x=6, there are 6*5+5=35 people, which contradicts the question and is discarded.

    In summary, there are 5 dormitories with 30 female students.

  2. Anonymous users2024-02-10

    1)x/2-5>=3

    2)x<-4

    4)60<=x<=80

    5) Multiply the left and right sides of the equation to obtain: 6x 2+7xy+2y 2=m 2-1, and when m=1, x>y

    6) Set water x: >=15

    9+2x-10>=15

    x>=8

  3. Anonymous users2024-02-09

    Let A be x and B be y

    to get a system of equations. 3/8x=2/5y

    1/4x-1/5y=4

    Solve the equation. y=60 x=64 I don't know if you can understand it.

  4. Anonymous users2024-02-08

    13、(1)

    How many times is it a monomial?

    Let's say it's 4 times.

    then 2+(a-1)=4

    a=3a²+2a+1

    a+1) If not 4 times, the method is the same.

    And the values of a +2a+1 and (a + 1) are equal.

    14. The number of times is the same.

    then m+(n+2)=(m+2)+(4-n).

    m+n+2=m+2+4-n

    2n=4n=2

  5. Anonymous users2024-02-07

    As shown in the figure, the same two wheels A, B radius R1 = 10CM, connected with a conveyor belt, C wheel radius R2 = 5CM, connected with the motor shaft. It is known that the speed of the motor is n=300rad min, and there is no slippage between the C wheel and the A wheel, and between the AB wheel and the belt. The object p slides onto the conveyor belt from the left end with the horizontal initial velocity of v0=1 m s, and the dynamic friction factor between p and the conveyor belt u=,a,b is 2m, find:

    1, What is the angular velocity of the B wheel? 2, object p with.

  6. Anonymous users2024-02-06

    If there are 20 stations, and each of the two adjacent stations is about 1 km apart, then there are 19 stations with a total of 19 km, which is the definition domain x n (natural number), and 0 x 19f(x) = 2, 0 x 5

    3,5<x≤10

    4,10<x≤15

    5,15<x≤19

    The function is a jump function (truncated), and the image has a solid point and a hollow point (note this).

  7. Anonymous users2024-02-05

    Solution: 1) A product produces x pieces, then chain mountain B product produces 50-x pieces of clever calling wheels.

    So it is needed: A: 9x+4(50-x)<=360 B: 3x+10(50-x)<=290

    9x+4(50-x)<=360

    9x + 200-4x "filial piety = 360

    5x<=160

    x<=32

    3x+10(50-x)<=290

    3x+500-10x<=290

    7x>=210

    x>=30

    30<=x<=32

    So x=30,31,32

    50-x=20,19,18

    So there are 3 kinds.

    A30 pieces, B20 pieces.

    A31 pieces, B19 pieces.

    A32 pieces, B18 pieces.

  8. Anonymous users2024-02-04

    9x+4(50-x)≤360

    3x+10(50-x)≤290

    Solution (1).

    30≤x≤32

    When x=30, 50-x=20, the remaining A raw material is 360-9x-4(50-x)=10, and the remaining B cosporium is 290-3x-10(50-x)=0

    When x=31, 50-x=19 is 360-9x-4(50-x)=5, and 290-3x-10(50-x)=7

    When x=32, 50-x=18, the remaining A raw material is 360-9x-4(50-x)=0, and the remaining B raw material is 290-3x-10(50-x)=14

  9. Anonymous users2024-02-03

    1) a--x then b is (guess 50 x).

    9x+4(50-x)≤360

    3x+10(50-x)≤290

    2) Solve the inequality group: 30 x 32 (x is an integer), so x can be used to justify the three kinds of Lingzhao ruler deficiency cases.

  10. Anonymous users2024-02-02

    y'=3x^2

    So the slope of the tangent at point p is: 3*1 2=3

    So the tangent is: y-12=3(x-1).

    y=3x+9

    The intersection points with the y-axis are: x=0, y=9

    So the ordinate of the intersection is 9

    The derivative is obtained first, and then substituted for the x-point coordinates, and the tangent slope is known as the slope k, and the linear equation for the crossing point (a, b) is:

    y-b=k(x-a)。。

  11. Anonymous users2024-02-01

    Knowing p(1,12), let y-12=k(x-1) so x 2+11=k(x-1)+12 , x 2-kx+k-1=0 can be seen from the problem, there is only one intersection point. So =0 , k 2-4(k-1) = 0 solution k=2, so y=2x+10 , so the ordinate is (0, 10).

  12. Anonymous users2024-01-31

    In the college entrance examination, if this question is 12 points, it should have 2 points.

  13. Anonymous users2024-01-30

    1)y=√(5+4x-x^2)

    i.e. 5+4x-x 2=(5+x)(1-x)>=0, i.e., 5+x>=0 1-x>=0 or 5+x<=0 1-x<=0=> 1=>x>=-5 or x<=-5 and x>=1 The latter set has no solution.

    So the definition domain is 1=>x>=-5

    2)f(x-1/x)=x2+1/x2+1

    Let x-1 x=a

    Then there is (x-1 x) 2=x 2+1 x 2 -2=a 2 ==x 2+1 x 2=a 2+2

    So there is f(a)=a 2+3

    So f( 2-1)=(2-1) 2+3=6-2 23)f(x+1) is , then there is -2<=x<=3==>1<=x+1<=4

    So there is -1<=2x-1<=4 ==0<=x<=5 2 So the definition domain of the function y=f(2x-1) is 0<=x<=5 2 I can help you, you set me first, and I will teach you.

  14. Anonymous users2024-01-29

    I don't understand, please tell me if you have an answer.

  15. Anonymous users2024-01-28

    There are two cases in this problem, first, ab is on the same side as cd, doing of of perpendicular to cd and intersecting with ab with the point e, with ob and od

    Because the diameter of 50 and because of the chord ab cd, from the chord cut theorem, ae is equal to be, df is equal to cf, and the square of 25 minus the square of 24 is equal to 49

    The root number 49 is equal to 7, so oe is 7 25 squared minus 20 squared to get 225 225 square root is 15

    So the distance between AB and CD is 8 with an OF of 15

    When AB and CD are opposite, the distance between AB and CD is 7 plus 15 equals 22

  16. Anonymous users2024-01-27

    For chord AB, d1 = root number ((50 2) -40 2) ) = root number (225) = 15;

    For chord cd, d2 = root number ((50 2) -48 2) ) = root number (49) = 7;

    Considering the position of AB and CD, there are:

    When they are on the same side of the parallel diameter, d=d1-d2=8cm, and when they are on different sides of the parallel diameter, d=d1+d2=22cm.

  17. Anonymous users2024-01-26

    The distance from circle o to chord ab is h1 = 25 20 = 15 the distance from circle o to chord is h2 = 25 24 = 7 When ab and cd are on the same side of the center of the circle o, the distance between the two strings is h1 h2 = 8 When ab and cd are not on the same side of the center of the circle o, the distance between the two strings is h1 h2 = 22

  18. Anonymous users2024-01-25

    The distance between AB and CD is 56I remember that I had heard this question from the teacher before. Additional questions on the test paper, forgetting ...... in the process

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