Five questions for help The fifth question

1.Original = (a+2b)(a-2b)(a+2b)(a-2b)(a-2b)(a2-4b 2) 2

a^4+16b^4-8a^2b^2

2.Original = (-3x+5y) * 3x+5y) -3x+5y) 2

25y^2-9x^2-30xy

3.Original formula = 2a2-ab + 4ab-2b 22 (a 2-b 2)-3ab

2(a+b)(a-b)-3ab

4.Original = (y-3) 2-2(y 2-4)y 2+9-6y-2y 2+8

y^2-6y+17

5.Original = (a-b)-2 2-(a+b) a-b)-2 * a+b)-2

(a+b)(a-b)-2(a-b)-2(a+b)+4」-(a^2-b^2-4a+4)

(a-2)^2-b^2」

a-2+b)(a-2-b)

Watch my process.

a+2b) 2(a-2b) 2

a+2b)(a-2b))^2

a^2-(2b)^2)^2

a^2-4b^2)^2

a^4-8a^2b^2+16b^4

2. -3x+5y) (-3x-5y).

3x)^2-(5y)^2

9x^2-25y^2

The above two questions are mainly to test your (A+B)(A-B) A 2-B 2 Third, there is no skill in this question.

a+2b)(2a-b) 2a 2+3ab-2b 2 4. (y-3) 2-2(y+2)(y-2) test your (a+b)(a-b) a 2-b 2

y^2-6y+17

(a-b-2)(2-a-b).

To perform two symbolic transformations, it becomes (a+b)(a-b) a 2-b 2 form.

Original (-b+2-a))(2-a-b) for the first time.

(b+2-a))(b-2+a)) for the second time.

b+2-a)(b-2+a) This formula is obtained by removing the outer brackets.

b+(2-a)((b-(2-a)) Isn't this the form of (a+b)(a-b) a 2-b 2?!

b^2-(2-a)^2

4a-a^2-4+b^2

5.The function is shifted 1 2 units of length in the direction of the function first, and then the ordinate remains the same, and the abscissa is reduced to the original 3

8.- 3 4 under the root number, 3 3 under the root number

Think for yourself, the denominator can be dissolved.

4/25×100=16kg

1t = 1000kg of beans.

4/25×1000=160kg

Answer: 100kg of beans contains about 16kg of oil, and 1t of soybeans contains about 160kg of oil

The answers are 16 and 160 Do you know what your teacher is.