A few questions about organic matter, one question about chemical organic matter

ch3cl+cl2==ch2cl2+hcl

ch2cl2+cl2==chcl3+hcl

chcl3+cl2==ccl4+hcl

The amount of monochloromethane, dichloromethane, chloroform, and tetrachloroform substances is equal, and methane is only 1mol, so the four substitutes are each, so the total amount of chlorine gas is consumed.

2.The density of the gas mixture is a multiple of that of hydrogen, so the average relative molecular mass is 29, so 28x+32(1-x)=29, so x=, so d.

3.There is no carbon-carbon double bond present in the benzene molecule, which is actually a conjugated large bond of six carbon atoms.

4.Selection: Ethylene and acetylene are introduced into bromine water to fade bromine water; b：

Ethylene fades bromine water, whereas toluene does not fade bromine water, but extracts; C: Neither benzene nor xylene can discolor bromine water, both are extracted; D: Neither benzene nor hexane can discolor bromine water, both are extracted.

5.Choose C. Ethanol cannot react with bromine water, copper hydroxide, sodium carbonate; Sodium propionate cannot react with copper hydroxide and sodium carbonate; Propylene cannot react with copper hydroxide and sodium carbonate.

The guy upstairs answered in detail.

Add some well:

1.Total reaction formula: 4CH4+10Cl2==CH3Cl+CH2Cl2+CHCL3+CCL4+10HCl

4.Benzene can react with pure bromine under the catalysis of iron powder to obtain bromobenzene.

Hello The answer is d

First of all, methane and chlorine produce methyl chloride and HCl under light conditionsThen, methylene chloride and the chlorine gas produced by HCL form methylene chloride and HCLThen, dichloromethane and HCl produce chlorine gas to form chloroform (also known as chloroform).

Finally, chloroform (also known as chloroform) and HCL produce chlorine gas to form tetrachloroform (also known as carbon tetrachloride).

The reaction process is sequential. The main reaction formula CH3Cl side reaction is generated 2 CH2CI2 3 CHCi3 4 CCI4

Regardless of the ratio of methane to chlorine, their reaction products are 5.

CH4 + Cl2 --CH3Cl+ HCLCH3Cl + Cl2 --CH2Cl2 + HCLch2Cl2 + Cl2 --CHCl3 + HCLCl3 + Cl2 --CCL4 + HCl, because every reaction has reactants and conditions that are present, that is, even the exact amount of the product cannot be determined.

But the product is there.

D should be chosen, and all four products are available.

The substitution reaction of alkanes, unlike other organic reactions, is a chain reaction. When one chlorine atom replaces one hydrogen on methane, the second chlorine atom immediately continues the reaction ,......Until the reaction produces CCL4, which is a complete chain initiating chain termination, in which CH3Cl, CH2Cl2, CHCL3, CCL4 are produced in turn

Due to the randomness of the chlorine atomic reaction, all the reactions occur at the same time, and the condition given in the title is the amount of the same substance, it is obvious that chlorine is not enough to completely replace methane with Ccl4, so that all the products will exist at the moment when the reaction is terminated. So choose D. If there is an absolute excess of chlorine, it can be considered that the product consists of only Ccl4.

a .Alcohol and iodine [miscible].

b .Bromine and water [miscible].

c .Nitrobenzene and water [nitrobenzene is insoluble in water] eliminate sails.

d .Benzene and nitrobenzene [preamble each other].

Option C: If there is still Huiqiaobi who doesn't understand, you can continue to ask me.

If you are satisfied, please remember

CCL4, CHCL3, CH2Cl2, CH3Cl each.

then the sum of cl elements is .

Each CL substitute consumes 1molCl2, so chlorine is consumed.

If one substitution and one mole of chlorine are reacted to produce four mol equal, the number of moles of chlorine is (1+2+3+4) 4=