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6x-5y+z=-6...1
6x+y+4z=3...2
6x+3y-5z=0...3
1 + 3.
2y-4z=6
y+2z=-3...4
2 + 3.
4y-z=3...5
4 type + 5 type *2 get.
9y=3y=1/3...6
Replace 6 with 4.
y+2z=-3
1/3+2z=-3
2z=-10/3
z=-5/3...7
Replace 6 and 7 with 3.
6x+3y-5z=0
6x+3*1/3-5*(-5/3)=0
6x+1+25/3=0
6x+28/3=0
6x=28/3
3x=14/3
x=14/9
So x=14 9, y=1 3, z=-5 3
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Personally, I think you're overthinking the problem.
In fact, in terms of profit, don't think about it so much.
Total: 12000
The purchase price is the ask price.
Actual number of transactions: 10000
The profit is: 10,000 * yuan.
One of the things that bothers you is nothing more than the testing part, but this one is unknown. You may not really exchange 20% of the goods for free. So, in fact, your profit is greater than 200. The profit range is between 200-800.
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It should be {3800 divided by (10000 plus 2000)} and multiplied by 10000.
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1.(2m+1) crypto-[3(m-2)+1]=3, brackets open, 2m+1-3m+6-1=3
Finishing -m=-3 yields m=3
Find m=32Let the side length be x on one side and yx*y=150 on the other side
2x+y=35
Find x=10 or x=, respectively, to get y=15 or y=20, because y is less than or equal to 18.
x=,y=20 is not a buried solution.
x=10,y=15
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Proof: Connect AN.
d is the midpoint of am, dn am. dn is the am bisector.
AMN is an isosceles triangle with an=mn, and man= amnman= mac+ nac.
amn= b+ bam (outer corner of the triangle mab) am bisected bac, bam= mac
Broadman b= nac
anm=∠anm.∴△abn∽△can
an²=bn×cn.i.e. mn = bn cn
Set up a building[x+5] Abbreviation.
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1.(2) Divide by 5 = 8/20 = 6: (15) =
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