Math gurus do the math! Which math master!

Updated on educate 2024-05-29
5 answers
  1. Anonymous users2024-02-11

    6x-5y+z=-6...1

    6x+y+4z=3...2

    6x+3y-5z=0...3

    1 + 3.

    2y-4z=6

    y+2z=-3...4

    2 + 3.

    4y-z=3...5

    4 type + 5 type *2 get.

    9y=3y=1/3...6

    Replace 6 with 4.

    y+2z=-3

    1/3+2z=-3

    2z=-10/3

    z=-5/3...7

    Replace 6 and 7 with 3.

    6x+3y-5z=0

    6x+3*1/3-5*(-5/3)=0

    6x+1+25/3=0

    6x+28/3=0

    6x=28/3

    3x=14/3

    x=14/9

    So x=14 9, y=1 3, z=-5 3

  2. Anonymous users2024-02-10

    Personally, I think you're overthinking the problem.

    In fact, in terms of profit, don't think about it so much.

    Total: 12000

    The purchase price is the ask price.

    Actual number of transactions: 10000

    The profit is: 10,000 * yuan.

    One of the things that bothers you is nothing more than the testing part, but this one is unknown. You may not really exchange 20% of the goods for free. So, in fact, your profit is greater than 200. The profit range is between 200-800.

  3. Anonymous users2024-02-09

    It should be {3800 divided by (10000 plus 2000)} and multiplied by 10000.

  4. Anonymous users2024-02-08

    1.(2m+1) crypto-[3(m-2)+1]=3, brackets open, 2m+1-3m+6-1=3

    Finishing -m=-3 yields m=3

    Find m=32Let the side length be x on one side and yx*y=150 on the other side

    2x+y=35

    Find x=10 or x=, respectively, to get y=15 or y=20, because y is less than or equal to 18.

    x=,y=20 is not a buried solution.

    x=10,y=15

  5. Anonymous users2024-02-07

    Proof: Connect AN.

    d is the midpoint of am, dn am. dn is the am bisector.

    AMN is an isosceles triangle with an=mn, and man= amnman= mac+ nac.

    amn= b+ bam (outer corner of the triangle mab) am bisected bac, bam= mac

    Broadman b= nac

    anm=∠anm.∴△abn∽△can

    an²=bn×cn.i.e. mn = bn cn

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