C language A is 97 and B is 98, so what is AB?

This is not understood in this way, e.g. char value = 'a'; char value2 = 97；Then value == value2, the two values are equal. But they are all basic types and take up 1 byte.

But what is "ab"? It's a string.

Occupy two consecutive bytes, if you have to say how many these two consecutive bytes are, then you can calculate it like this, the first byte 97, if in the high bit, the second byte 98 in the low bit, then finally can be combined into a short int type, a byte 8 bits, that is, 97x2 8 + 98 = 24930;

Its practical hexadecimal.

It means more clearly: 97 corresponds to hexadecimal.

Yes 61, 98 corresponds to hexadecimal is 62, and combined into a number is 0x6162, corresponding to decimal.

That's 24930

I think you're a little unclear about the concept of characters and strings. The most obvious difference is the single quotation marks for the characters and the double quotation marks for the strings.

When used as a character'a' = 97 = 0x61。For example, char x ='a'.It is clear that the value of x is a character'a'

As a string, when "a", it doesn't have an explicit value. For example, char *s ="a"；Meaning s is a pointer that points to a string whose contents are"a", the string contains the characters'a'

What you say AB should be"ab", which is a string.

In the C language.

a'is a character constant, and the value is 97

b'is a character constant, and the value is 98

ab'is not a legal character.

Summary. a+b=6b+c=9a+c=7abc.

Dear, the calculation process is shown in the figure above. a=2，b=4 ，c=5。

The value of a&&b, the logical value of a and b. It is a logical expression in the C language. &&& means logic and operation in mathematics.

In C, a non-0 is 1, because in the question a=4 and b=5, the result of a&&b is 1. So the final result of x in the question is 1. The calculation process is a&&b=1, c<'b'=1, x=1&&1, so x=1.

The value of a&&b, the logical value of a and b. It is a logical expression in the C language. &&& means logic and operation in mathematics.

In C, a non-0 is 1, because in the question a=4 and b=5, the result of a&&b is 1. So the final result of x in the question is 1. The calculation process is a&&b=1, c<'b'=1, x=1&&1, so x=1.

As can be seen from the question, A + B + C = 97, and C = 6. Substituting c = 6 into the first equation gives a + b + 6 = 97, i.e., a + b = 97 - 6 = 91.

From this we get a + b = 91, and since a and b are positive integers, and the values of a and b are at least 1, the following two systems of equations can be listed:

a + b = 91

a + b = 90

Substituting a + b = 91 into the second equation gives a + b = 91 while satisfying the condition c = 6, thus:

a + b + c = 91 + 6 = 97

where a = 1 and b = 90.

Substituting a + b = 90 into the second equation gives a + b = 90, while satisfying the condition c = 6, thus:

a + b + c = 90 + 6 = 96

Since the condition that a, b, and c are all positive integers is not satisfied, they are rounded.

In summary, the solution that satisfies the conditions is: a = 1, b = 90, c = 6.

a+b+c=97

c=6a+b=91

There should be one formula left.

Two unknowns require two formulas to solve.

a+b=92.

b+c=94.

a+c=95.

Subtract (2) with (1) formula:

a-c=-2.

a=c-2.

Substituting into the (3) stool segment:

c-2+c=95.

2c=93.

c=a=b=Solve to complete the search.

What is the reputation of ABC jujube?

C language's & is the "bitwise and" operation, first prepare the two operands to express the binary number, and then perform the "and" bitwise, a=17 b=9 then a&b is: plex rolling.

The osmotic pose is valued at a&b as 1.

C can define hail after a and b, a=b=9 is assigned. It first assigns the value b=9, then the value of the source part is 9, and then the scatter is assigned a=9.

In C, this is a bitwise and burn-resistant operation, where two integers are converted to binary and the result is obtained after the operation is not fragmented. C language: a=17, b=9, then withered cherry a&b is 10001&1001=1

Since only the single digit of the binary representation of 17 and 9 is 1, the result is 1 when the bits and manipulations are performed on them.

In C, the order in which expressions are evaluated is determined by the precedence and conjugation of the operators. Specifically, when there are multiple operators of the same priority in an expression, the order of the evaluation is from left to right. For autoincrement operators like A++ and ++B, they take precedence over most other operators.

In this expression a+++b+++c, it can be split into three parts, i.e., a++, b, and ++c. Since the auto-increment operator has a higher priority, each auto-increment operation is executed first. In left-to-right order, you can rewrite this expression equivalently as follows:

a++)b)) c)

For a=1, b=2, c=3, the result can be calculated as 7 as described above.

Hello. We can solve it by the process equations. According to the title, there are the following three equations:

a + c = 9

b + c = 7

a + b =

Shift the first brother key equation to get a = 9 - c, move the second equibent equation to get b = 7 - c, and substitute a and b into the third equation to get :

A + B = 9 - C) +7 - C) = 16 - 2C, therefore, A + B has a value of 16 - 2C.