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Anonymous users2024-02-10Two right-angled lines intersect to form 4 angles, both of which are 90 degrees. These two straight lines are perpendicular to each other, and their intersection is called the perpendicular foot.
The hour round, the angle between the minute hand and the hour hand on the clock face is an acute angle.
The angle between the minute and hour hands on the clock face is obtuse.
Because the distance of the plane is equal, it is like a project. Therefore, "flying 880 km per hour" and "flying 760 km per hour" are equivalent to work efficiency.
"Working hours" when the plane went: 1 880 (hours).
"Working hours" on the return of the plane: 1,760 (hours).
The ratio of the "working time" of the plane to the time of return: (1 880) :(1 760) = (1 880) (1 760) = (1 880) x 760 = 760 880 = 19 22 = 19:22
Total servings: 19 + 22 = 41 (servings).
The distance traveled by plane: 880x(171 41)=150480 41 (km).
So the maximum distance from the airfield when the plane performed the mission was 150480 41km.
Two right-angled lines intersect to form 4 angles, both of which are 90 degrees. These two straight lines are perpendicular to each other, and their intersection is called the perpendicular foot.
The hour round, the angle between the minute hand and the hour hand on the clock face is an acute angle.
The angle between the minute and hour hands on the clock face is obtuse.
Set the time to go to x and the time to return to (9-x).
Then 880x=760(9-x) is solved: x=
So the maximum distance is 880*
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Anonymous users2024-02-09Vertical, with the feet hanging down.
1 o'clock, 2 o'clock, 10 o'clock, and 11 o'clock are acute angles.
4 o'clock, 5 o'clock, 7 o'clock, and 8 o'clock are obtuse angles.
Let the maximum distance be x, x 880+x 760=9x=
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Anonymous users2024-02-08Let the binary equation be a binary one-dimensional equation, the integer part is the selling match x, and the decimal part is yx+3y=
x+8y=solution. x=3
y=The original small is matched with a large pure vertical number of 3+
process yourself and then modify it)
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Anonymous users2024-02-07Let the volume of milk and soy milk in the first two cups be equal, both are A, and the volume of the spoon is B
She first took out a spoonful of soy milk from a cup of soy milk, poured it into the cup of Shengniu milk and stirred well, then the volume of soy milk is now a-b The volume of milk is a+b
Then take out a spoonful of mixed milk and soy milk from the cup of milk and pour it into the cup of soy milk, then the volume of soy milk is now 2a-b The volume of milk is a
Compare the sizes of 2a-b and a.
When A>B milk cups have more soy milk.
When A = B, the soy milk in the milk cup is as much as the milk in the soy milk cup, when A
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Anonymous users2024-02-06There is a lot of soy milk in the milk cup, and the soy milk taken out is a spoonful, and the milk poured back is not a spoonful.
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Anonymous users2024-02-05The first number of the box is in the first row (1 2-1) and the second number is in the third row (2 2-1)...Each number is on an odd-numbered row.
So the 10th number is on line 19 (10 2-1) and the first number in the odd row is 1+2+...Add to the sum of the number of rows.
The first number in line 21 is 1+2+.21=(1+19) 19 2=190 Observe that the number of numbers in each row is exactly equal to the number of rows.
There are 19 numbers in line 19.
The numbers in the box are all in the middle of the row, which is the 10th in the row.
So the number is 181
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Anonymous users2024-02-04No, it should be a fifth-of-the-fold discount.
Originally, 5 bottles cost 5 * 50 = 250, but now 5 bottles only need 4 * 50 = 200 discounts of 250-200 = 50 yuan.
The ratio of the discount is 50 250 = 1 5
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Anonymous users2024-02-03Wrong! Set the travel time of the first car to t
then the travel time of car B is .
t+1-7+4 = t-2 < t
1 : [Car B departs one minute earlier than Car A].
7 : [but stayed in place B for seven minutes].
4 : [Finally, car B arrives at C four minutes later than car A].
Thus, car B travels less time than car A, and the speed should be greater than that of car A, but [the speed of car A is 80% of the speed of car A] contradictory!
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Anonymous users2024-02-02If the root number A + the root number B root number C + the root number D
i.e. a+b+2*root number (ab) is ab< cd, because a c d b, is true.
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Anonymous users2024-02-01Both sides are squared.
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Anonymous users2024-01-31a-c=d-b<0, verify: root number a + root number b root number c + root number d is root number a - root number c root number d - root number b
Both sides are squared at the same time.
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Anonymous users2024-01-30∵-1＜x＜3
k 0, x = -1, x = 3 should be the solution of the equation kx -(k +1) x-3 = 0 into the calculation k=1
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Anonymous users2024-01-29k = 1 is actually -1 and 3 are the two solutions of the inequality into the equation, and you can find it by bringing it in.
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Anonymous users2024-01-28When the constructor f(x)=kx 2-(k 2+1)x-3k=0, f(x)=-x-3
The solution set satisfying f(x)<0 is x>-3
So k≠0 if k<0
The image opening of f(x) is downward, and the solution set satisfying f(x)<0 is inconsistent with the known solution set from a certain point to negative infinity and from a certain point to positive infinity.
So k>0
f(x) has an image opening pointing upwards.
And there are two intersections with the x-axis (-1,0), (3,0)f(-1)=k+k2+1-3=0
k^2+k-2=0
k-1)(k+2)=0
k = 1 or k = -2 (rounded).
f(3)=9k-3(k^2+1)-3=0
3k^2-9k+6=0
k^2-3k+2=0
k-1)(k-2)=0
k = 1 or k = 2
In summary, k=1
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