The root of equation x 3 x 0 is, and the root of equation x 1 x 3 0 is

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The root of x -3x=0 is 0

Because any power of 0 is 0

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(x-1) (Zhiqing x+3) = 0, x-1 = 0 or x+3 = 0, x 1 = 1 or x 2 = -3, so it is understood that the judgment is x 1 = 1 or x 2 =-3

Solution: x +x-6=0

x-2）*（x+3）=0

, x-2=0, or x+3=0

, x=2, or x=-3

then x1 = 2 and x2 = -3

That is, the solution of x + x-6 = 0 is x1 = 2 and x2 = -3.

Solution: x-2x+3=0

3=2x-x (shift) let's dress.

3=x (merge the same kind of item absolute code).

x=3 (move x to the left side of the equation).

Not very will have a keyboard in = =

Untie; (open parentheses) x square + 3x = 0

x times x = --3x (subtract 3x from both sides of the equation at the same time, the point is to understand x square = x times x).

x1 = --3 (both sides are divided by x at the same time).

x2 = 0 (a root that is easy to forget).

Because the original equation is equal to 0

So there are 3 cases.

0, x +3 is any real number.

is an arbitrary real number, x+3=0

3.Zero on both sides.

Solution: x = 0 or x + 3 = 0

x 1=0,x2=-3

0 and -3 are very simple, how to write the process.

x 2 + 2 x - 3 = (x - 1) (x + 3) = 0 so x = 1 or x = -3

Cross multiplication breaks down the factors and then solves the equations.

This is the factorization solution equation.

If that doesn't work, let's use the root finding formula.

The solution of the 2nd order equation can be multiplied by crosses.

Partially yes):

Original = (x+1) * (x-3) = 0

x-3 = 0 or x+1 = 0

So x1=3 x2=-1

Or use the root-seeking formula (all of which can be used to endure):

ax 2+bx+c=0 is the root of the balance, when b 2-4ac>=0.

is x=[-b (b 2-4ac) (1 2)] 2a;

When b 2-4ac < 0.

is x=[-b i(4ac-b 2) (1 2)] 2a