My question is how to get rid of the negative score, how can I get rid of the negative part of the q

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Of course, Lu Qing is positive.

Because a fraction is equivalent to the numerator divided by the denominator, if the numerator and denominator are both negative sail grips, and the negative is positive, the result is of course positive and empty.

Not necessarily, anyway, there is a non-positive number: 0 (-1) is not a negative number and is not a positive number.

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Quite simply, matter is made up of molecules, and atoms make up molecules. Like a glass of water, it is said that there are countless water molecules, but a water molecule H2O is said to be composed of two hydrogen atoms and one oxygen atom.

Molecules are made up of atoms, for example, a water molecule is H2O, which is made up of two hydrogen atoms and one oxygen atom.

The spacing between the gas molecules is very large, and the interaction force is very small, so the gas does not have the shape of a solid orange branch. Due to the fluidity of the gas, there is no fixed volume of the gas erected.

The total number of valence electrons of n5+ is 5 5-1 = 24, and it takes 5 8 = 40 to reach 8 electrons, and the difference of 16 electrons needs to share 8 pairs of electrons to make up for it. Then the number of lone pair electron pairs is 4.

Without considering the formation of a ring structure, its structure is as follows (lone pairs are omitted, because it is really difficult to write; The formal charge is marked to the right of the atom, and the non-charged charge is 0):

n(-)=n(+)=n(+)=n(+)=n(-)n≡n(+)n=n(+)=n(-)n≡n(+)n(-)n(+)n]↔④n(-)=n(+)=n-n(+)n]

Among them, n with a positive charge of 1 unit form is directly connected, which is particularly unstable, and the approximation can be ignored, and only two approximations are considered to account for 1 3, then the bond level of the two NN bonds is 8 3 (end 3 (middle) respectively.

Chemistry competition, right? This is a classic question, look for it in the competition book, and Jiangsu's can turn to the "Standard Course".

The formula is 0 0 type.

Deriving lnx (2x 2-2) with Lobida, up and down, and deriving 1 (4x 2) with Lobida

x tends to 1 to 1 4

Note: Lopida's Law Variable limit integral derivation is very important, and it must be firmly mastered if it is often used in the future.

Nitrogen molecule nitrogen atom, each nitrogen molecule is made up of two nitrogen atoms.

The N2 molecule is made up of N and N is nitrogen.

...Then the value of k is (a -3 or 1).

Solution: Let the two real roots of the equation be x1 and x2, and according to Veda's theorem, x1+x2=-(2k+1).

x1x2=k^2-2

x1^2+x2^2

x1+x2)^2-2x1x2

-(2k+1)]^2-2(k^2-2)=4k^2+4k+1-2k^2+4

2k^2+4k+5

2k^2+4k+5=11

2k^2+4k-6=0

k^2+2k-3=0

k+3)(k-1)=0

k = -3 or k = 1

You can take it to the equation and do the math.