The absolute value of x 3 is the opposite of y 2 to the power of 2 3, what is the x power of y?

The absolute value of x-3 + (y+2 3) to the power of 2 = 0 absolute value and the value of square are always non-negative values, and only when they are 0 at the same time, the sum is 0, so x-3 = 0, y + 2 3 = 0

x=3,y=-2/3

y to the xth power.

2 3) to the 3rd power.

The absolute value of x-3 and the 2nd power of (y+2 3) are both greater than or equal to 0, and if you want to guard the opposite number, then the 2 numbers are both 0

The solution yields x=3 and y=-2 3

So y to the power of x = (-2 3) to the power of the power = -8 27

First of all, you need to know the concept of opposites, right? That is, there are only two numbers with different symbols, and then the "absolute value" is non-negative, and the power of the second is also non-negative, and these two symbols are different, so even the formula is equal to "0" to be done. So x=3, y=-2 3.

Simple, right? And the x-power of y is not -2 to the 3rd power of 3, it's -8 27.

So the absolute value of x-3 + (y+2 3) to the power of 2 = 0 because the absolute value of x-3 is 0, (y+2 3) to the power of 2 0, so x-3 = 0, y+2 3 = 0

So x=3, y=-2 3.

y to the power of x = (-2 3) 3 = -8 27

The absolute value of x-3 is the opposite of the power of (y+2 3), so they are both 0

So x=3, y=-2 3.

The x-power of y is =-2 to the 3rd power of 3 =-8 27

x-2) absolute value 0, (y-3) 2 0

The two are inverses to each other, indicating that both are equal to 0

So (x-2) squared = 0, x = 2, y-3 absolute = 0, y = 3, so x + y = 2 + 3 = 5

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Answer: The absolute value of x-3 and the square of (y+2) are the opposite of the family coarseness, and the sum of the opposite numbers of the spike is 0:

x-3|+(y+2)²=0

So: x-3=0

y+2=0 decombustion-slip: x=3, y=-2

So: y x-xy

2,3,

Because the absolute value of x 2 is the opposite of the square of y 3, x2=0x=2y3=0

y= Argument 3

y to the power of x = (3) the absolute largest with macro = 9

The absolute value of x-2 is the opposite of the flat number of y+3.

The absolute value of x-2 and the square of y+3 are added to zero.

x=2y=-2

y to the power of x = (-2) Jane Bichen = 4

By the title of the world:

x+3) collapse fiber square = y-2 = 0

So: x=-3

y=2x to the power of y.

3) 2 times of the leak search party.

If the absolute value of x-y+3 and the square of (x+3y-2) are sold to the opposite number, then x-y+3=0

x+3y-2=0

The solution is x=-7 4

y=5/4,3,x=-7/4；y=5 4,1, the absolute value of x-y+3 = 0

x+3y-2) = 0

And they are the opposite of each other.

x-y+3=0

x+3y-2=0

The solution is x=-7 4

y=5 4,0, it is known that the absolute value of x-y+3 and the square of (x+3y-2) are opposite to each other, and the values of x and y per mu are found.

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The absolute value of x+y-2 is the opposite of the quadratic of (x-3y+5).

Then x+y-2 is a power of x+y-2 + (x-3y+5) = 0, then x+y-2 = 0

x-3y+5=0

The two types of large closure are subtracted from each other, and they are obtained.

4y-7=0

The solution is y=7 4

then x=1 4