If a 5, b 2, c 6, and a b a b , a c a c, find a b

This question is enumerated.

Solution: By |a+b|=-(a+b) is introduced, a+b<0 is launched by |a+c|=a+c launched, a+c>0

a|=5，|b|=2，|c|=6, there are the following combinations, and the above inequality group verification is brought in in turn, and the result is as follows.

1)a>0,b>0,c>0；5+2>0, inconsistent;

2)a>0,b>0,c<0；5+2>0, inconsistent;

3)a>0,b<0,c>0；5+2>0, inconsistent;

4)a>0,b<0,c<0；5+2>0, inconsistent;

5)a<0,b>0,c>0；-5+2<0,ok;-5+6>0,ok;Yes, a=-5, b=2, c=6, so a-b+c=-1

6)a<0,b>0,c<0；-5+2<0,ok;-5-6<0, inconsistent.

7)a<0,b<0,c>0；-5-2<0,ok;-5+6>0,ok,yes,a=-5,b=-2,c=6,so a-b+c=1

8)a<0,b<0,c<0；-5-2<0,ok;-5-6<0, inconsistent.

Does the question ask about the absolute value of a-b+c?

A minus B plus C equals 3 A minus B equals minus 3

a+b|=-Rough Pants Fierce a+b) Rock Pure Knowledge 0

a+b≤0|a|=5 |b|=2

a=-5,b=±2

a+c|=a+c≥0,|c|=6

c = 6a-b + c = -1 or 3

Let a:3=b:4=c:5=k, then eliminate laughter a=3k, b=4k, c=5k, so, 3k+4k-5k=6, the solution is k=3, so, take a = 9, b = 12, c = 15

So the answer is: 9, 12, 15

Hello, the answer is as follows:

Because 5 6 = 6 5

Therefore, (5*c+6) hand-transported leather (5*6) = 6*c+5) (6*5) denominator is the same, so the numerator is also quiet, that is, 5c+6 = 6c+5, so c=1 is a b= (a+b) (a*b) so the original formula = 3+2) (3*2) *4+5) (4*5)3 Bicha 8

|a|=3，|b|=1，|c|=5, and |a+b|=a+b，|a+c|=-a+c), closed hole.

a=3, b=1, c=-5, a-b+c=3-1+(-5)=-3, loss or a-b+c=3+1+(-5) pin tung = -1

|a|=3，|b|=2, split the key and shout a= 3, b= 2, |a-b|=b-a, a-b 0, i.e. a b, when a=3, b=2, a b does not match the original question, the hostel goes; When a=3 and b=-2, ab does not match the original question and is discarded; When a=-3, b=2, a+b=-3+2=-1;When a=-3, b=-2, a+b=-3-2=-5 so answer.

The Wolf Hunter team will answer for you.

a+b|=-(a+b), a+b 0, and |a|=5 ，|b|=2，a=-5，b=±2，a+c|=a+c, a+c>0, c=6, a=-5, b= 2, c=6,a-b+c=3 or -1.

Because |a+b|=-(a+b)，|a+c|=a+c, so a+b 0, a+c 0

And |a|=5 |b|=2 |c|=6, so a = 5, b = 2, c = 6

So a=-5, b=2, c=6

Then a-b+c=5 2+6=9, or 13

Hello, the answer is as follows:

Because 5 6 = 6 5

So (5*c+6) (5*6) = (6*c+5) (6*5) the denominator is the same, so the numerator is the same, i.e. 5c+6 = 6c+5 so c=1

i.e. a b = (a+b) (a*b).

So the original = (3+2) (3*2) *4+5) (4*5) = 5 6 * 9 20

According to 5 6 = 6 5, substitute the value of c in a b= (a*c+b) (a*b), and the following 3 2 and 4 5 can be found.