In the series circuit, the lamp L is connected in series with the ammeter, if the ammeter is short c

There will be an indicator, if your ammeter is highly sensitive, there must be an indicator! However, the indication will become smaller than before the short circuit, think about it: if you connect the two ends of the ammeter with wire 1, when most of the current passes through wire 1, will a small part of the current also slip through the ammeter?

Because they are all together. Since you have slipped away, there must be a sign! Even if there is no indication, it is only because your ammeter is blunt, but there is still current passing through the ammeter, (it is another matter if the ammeter is broken) It is recommended that you use a high-sensitivity ammeter when doing this experiment).

When the current is very strong, then you can't directly intervene the wire in the ammeter, for example, if you want to test the current in a power plant、、、 how big is the ammeter? The ammeter in the power plant uses this circuit: in the closed circuit, at a certain distance, two taps are played, and the total current can be measured through simple calculations when the ammeter is connected here.

There is definitely no indication of three after the ammeter is short-circuited.

The ammeter is short-circuited, just like the circuit short-circuit, there is no current through the ammeter, the short-circuit time meter should be broken, there must be no indication.

If the ammeter is connected to the electrical appliance, it is regarded as a wire; If it is connected in parallel with the wire, it is regarded as an electrical appliance.

Yes, but it's too small for a normal watch to see. At the middle school level, I don't think there is any.

Dizzy! You shorted the ammeter, how can it still have a reading if there is no current flowing through it???

If the resistance of the bulb is short-circuited, it is zero.

1. The indication of the voltmeter is zero. U=IR because r =0 . 2. The indication infinity of the ammeter (the internal resistance of the power supply is ignored) i=e r e is the power supply potential!

The bulb and the ammeter are connected in series in the circuit, the ammeter passes through the bulb current, and the voltmeter is connected in parallel at both ends of the bulb to measure the voltage drop on the bulb. If the bulb is short-circuited, because the internal resistance of the voltmeter is almost infinite, the power supply is equivalent to direct on, and the short-circuit current flows through the ammeter, and the voltmeter reads zero.

Normal display. Because the bulb has a short circuit, it is entering the normal working state.

If the bulb is disconnected (burned), which is equivalent to a disconnected circuit, the current is zero (no-pass) and the voltage remains normal (the power supply remains normal).

Voltmeter reading = 0, ammeter reading increases rapidly, is a short circuit current.

Summary. Hello, I am glad to serve you and give you the following answer: the current indication number is 0, which means that the circuit is open.

Open circuit means that the circuit is disconnected, so that the current cannot flow, the resistance value in the circuit becomes infinity, and the current value becomes 0. An open circuit can be caused by a faulty component in a circuit, a broken connection line in a circuit, or a broken circuit board in a circuit. An open circuit will cause the current in the circuit to not flow, which will affect the normal operation of the circuit.

In a series circuit, the current is indicated as 0, indicating whether it is a short circuit or an open circuit, and the reason is explained.

Hello, I am glad to serve you and give you the following answer: the current indication number is 0, which means that the circuit is open. Open circuit means that the circuit is disconnected, so that the current cannot flow, the resistance value in the circuit becomes infinity, and the current value becomes 0.

An open circuit can be caused by a faulty component in a circuit, a broken connection line in a circuit, or a broken circuit board in a circuit. An open circuit will cause the current in the circuit to not flow, which will affect the normal operation of the circuit.

I'm still a little confused, can you be more detailed?

Hello, I am glad to serve you and give you the following answer: the current indication number is 0, which means that the circuit is open. Open circuit means that the circuit is disconnected, so that the current cannot flow, the resistance value in the circuit becomes infinity, and the current value becomes 0.

An open circuit can be caused by a faulty component in a circuit, a broken connection line in a circuit, or a broken circuit board in a circuit. An open circuit will cause the current in the circuit to not flow, which will affect the normal operation of the circuit.

The result is a voltmeter.

Measure voltage voltage, there is an indicator; Ammeter.

Because the voltmeter is connected in series, there is no indication equivalent to an open circuit.

However, there are two kinds of circuits, and I am talking about the common one, which is the following circuit:

If it is the following connection, the voltmeter does not read the equivalent of measuring the wire voltage, and the ammeter may burn out the power supply or ammeter because of the short circuit, the current is very large.

1. In the series circuit, if the bulb is short-circuited, the current indication number becomes larger, and the voltmeter is 0;

2. In the series circuit, if the bulb is broken, the current is 0, and the voltage is the power supply voltage.

3. In the parallel circuit, if the bulb is short-circuited, the power supply is short-circuited, the current indication becomes larger, and the voltmeter is 0;

4. In the parallel circuit, if the bulb is broken, the number of branch current is 0, and the number of dry current is smaller; The voltage representation number does not change.

A short circuit is when a circuit or part of a circuit is shorted. If the load and the power supply are connected together by wires, it is called a short circuit, the current provided by the power supply during the short circuit will be much larger than the current provided by the path, and the short circuit is generally not allowed, if the short circuit is serious, the power supply or equipment will be burned out.

If the short circuit ammeter has an indication, the voltmeter has no indication: If the open circuit ammeter has no indication, the voltmeter has an indication.

It's so funny brother, you don't even have a voltage and current meter, who knows how to move?

The voltmeter is connected in series into the circuit, and its resistance is large, so the current in the circuit is very small, and the ammeter has almost no indication.

Why does the voltmeter have an indication? Because in a series circuit, the voltage is proportional to the resistance, and the voltmeter resistance is large, and the voltage at both ends of it is the largest, close to the power supply voltage.

One may be that the original measured by the voltmeter is disconnected, and there is no current, so the voltmeter has an indicator, and the ammeter has no indicator.

The two components of the circuit are all connected in series.

Three voltmeters.

The ammeter is reversed.

The voltmeter is connected in series into the circuit, because the internal resistance is too large, and it can be approximately regarded as an open circuit, and the measured voltage is the power supply voltage, so it causes i = u r, r is very large, and the indication of the ammeter is infinitely inclined to zero.

If your voltmeters are properly paralleled in the circuit, then the possible scenarios are:

1. The ammeter is broken.

2. There is a problem with the selection of the measuring range, and the current range is too large.

Hope your problem is solved!