In triangle ABC, the length of AB is t, the length of BC is 4, the length of AC is 8 t, and the maxi

By the cosine theorem:

s=1 2*ab*acsin60 4( 3) If and only when ab=ac, take the equal sign sail reed, you can calculate ab=4

Let the height of bc be x, and the length of half of bc is y, and according to the problem, xy= x 2+y 2=5 2, and solve the equation to get 2y = 10 or 3 10, so the length of bc is 10 or 3 10

Summary. Is there a picture, please.

In rectangular ABCD, EF is the midpoint of AB and BC, respectively. If the surface shape of the rectangle is guessed to be 48 square meters, what is the area of the triangle BEF.

Is there a picture, please.

There are no drawings to draw yourself.

Solution: It can be seen from the question design, a

b and c are the opposite sides of angle a, angle b, and angle c, respectively.

The trilateral relationship of a triangle is: a 2 + b 2-2ab*cosc = c 2 The area of a triangle is formulated as s=

It should also be a 2 + b 2 + 2 c 2 = 8 in the text

So (a,b are both greater than 0,so c<2,a<2sqrt(2),b<2sqrt(2).

and s=tanc*(8-3c2).

Bring in tanc and eliminate c with the above equation to get an algebraic formula containing a and b, which is added by the above inequality to get the final answer.

Construct the Lagrangian function f(a,b,c)=s abc+ [a +b +2c -8],s abc= {p(p-a)(p-b)(p-b)(p-b),p=(a+b+c) 2, and then solve the equations fa=0,fb=0,fc=0,f =0, and solve a=?，b=?，c=?

The maximum value of SABC can be determined. This is called the maximum value of the conditional extremum.

Party A? Party B2c square = 8 is,"?What about the operator notation? Or not? Multiplicative relationship?

Summary. In the triangle ABC.

D is the midpoint of BC.

The triangular ADC is half the area of the triangular ABC.

e is the midpoint of AD.

The triangular CED is half the area of the triangular ACD.

The same goes for you. The triangle def is 1 8=1 of the area of the triangle abc, the rectangle abc+de is known to be the midpoint of bc, the triangle ad+f area is eight squares, and the area of the rectangle a + bcd is found.

In the triangle ABC. '.'D is the midpoint of BC. '.

The triangular ADC is half the area of the triangular AC'.'e is the midpoint of AD. '.

The triangle CED is half of the area of the triangle ACD, and the buried triangle DEF is 1 8=1 of the area of the ABC of the triangle

Hope mine is helpful to you.