The question is factored in the question supplement

Hello! Higher polynomials are generally grouped decomposition, cross multiplication, formulas, etc.

y²(x² -2x)³ y²x

y²[ x² -2x)³ x ]

When x=0 or 1, (x -2x) x = 0, so there is a factor x(x-1) i.e. x -x

x² -2x)³ x

x² -x) -x ]³x

x² -x)³ 3x(x² -x) +3x²(x² -x) -x³ +x

x² -x)³ 3x(x² -x) +3x²(x² -x) -x(x²-x) -x² -x)

x -x) [x -x) 4x + 3x -1 ](x -x) [x 4-5x +7x -x-1 ]So primitive = y x(x+1) (x -5x +7x -x-1)x -11x +31x-21

When x=1, the above equation = 0, so there is a factor (x-1)x (x-1) -10x(x-1) +21(x-1)(x-1) (x -10x + 21).

x-1) (x-3)(x-7)

x³ -3x² +4

When x= -1, the above equation = 0, so there is the factor x+1x (x+1) -4x(x+1) +4(x+1)(x+1)(x -4x+4).

x+1)(x-2)²

2x +xy-y - 4x+5y - 6 double cross multiplication.

x y -3

2x -y 2

Original = (x+y-3)(2x-y+2).

All questions are factored using cross multiplication. The process is as follows:

x²-43xy+14y²

4x-7y）（5x-2y）

x²-19x+5

9x-5）（2x-1）

x²-13x+6

3x-2y）（2x-3y）

x²+4xy-28y²

x-2）（5x+14）

7、-35m²n²+11mn+6

35(mn)²+11mn+6

-5mn+3）（7mn+2）

11a-35a²

（35a²-11a-6）

3-5a）（2+7a）

11a-35a²

（35a²+11a-6）

（5a+3）（7a-2）

If you have any questions, please feel free to ask. If satisfied, thank you for adopting o( o haha

[1] Let these two consecutive odd numbers be: 2n-1, 2n+1, where n is an arbitrary natural number.

Obviously"An even number sandwiched between these two consecutive odd numbers"is 2n: the product of two consecutive odd numbers plus the greater of them.

2n-1)(2n+1)+(2n+1)=(2n+1)[(2n-1)+1]

2n(2n+1)

The result is:"An even number sandwiched between these two consecutive odd numbers"with"Larger odd numbers"of the product.

2] [Outer d= inner diameter d=

The shape of the disc is a ring, and its area s = outer circle area s1 - inner circle area s2;

Whereas the circular area s = r 2 = (d 2) 2 = (1 4) d 2

So you can find the disc area:

s=(1/4)πd^2-(1/4)πd^2=(π/4)(d^2 - d^2)

π/4)(d+d)(d-d)

3] The side lengths of squares 1 and 2 are set to a and b respectively;

4a-4b=96;(From this we know that the square is 1 to 2 larger) a2 - b2 = 960

From the first equation we know that 4(a-b)=96, so a-b=96 4=24;

From the first equation we know that (a+b)(a-b)=960, i.e., 24(a+b)=960So: a+b=960 24=40;

Get a system of binary linear equations:

a+b=40

a-b=24.

Easy to solve. a=32,b=8.

c1=4a=4*32=128;

c2=4b=4*8=32.

1.I've done the math myself: 3 times 5 plus 5 equals 20, 4 times 5 equals 20

2.The middle of the disc is empty. So its area should be the area of the outer circle minus the area of the middle circle: d d 4 d d 4 The answer is to calculate it yourself according to the formula.

3.Let the length of the side of square 1 be a centimeter, and the side length of square 2 be b centimeter

4a － 4b = 96;i.e. a b = 24;

a×a － b×b =960;i.e. (a b) a b ) = 960;Substituting a b = 24, we get a b = 40

It can be calculated that a=32, b=8 , then the circumference of square 1 is 4a centimeter or 128 cm, and the circumference of square 2 is 4b centimeter or 32 centimeters.

Hehe, I'm having cramps with my hand typing.

Solution: The method is the scattering chain that treats the equation 2x 2--5xy+y 2=0 as a quadratic equation about x.

Then solve this equation to find its two roots, x1 and x2

Finally, write in the following way, and you're done. 2x^2--5x+y^2=2(x--x1)(x--x2).

For example, to decompose the factor 2x 2--5xy+y 2, you can first solve the unary quadratic equation 2x 2--5xy+y 2=0 for x

Got to the two roots x1=(5+17) 4, x2=(5--17) 4

So 2x 2--5xy+y 2=2[x--(5+root17) 4][x--(5--root17) 4].

This completes the factorization. Late shipments.

For example, solving the equation x 2--2x--4=0 yields x1=1+root number 5, x2=1--root number 5

So x 2--2x--4=[x--(1+root5)][x--(1--root5)]

x--1--root number 5) (x--1 + root number 5).

Do you understand? Will you do it yourself?

x²-2x-4

x2-2x+1-5

x-1) 2-root No. 5 of the Ping and Qin Chun Fang.

x-1 + Root No. Mori Shou Stare 5) (X-1 - Root No. 5).