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1).It takes X days for two engineering teams A and B to complete the project at the same time, which is derived from the title.
1 30 + 1 20) * x = 1, so x 12 = 1, so x = 12, that is, it takes 12 days for the two engineering teams A and B to complete the project at the same time.
2).A needs to pay 30 * 200 = 6000 yuan to complete alone, B needs to pay 20 * 280 = 5600 yuan to complete it alone, and A and B need to pay (200 + 280) * 12 = 5760 yuan for cooperation, so B alone construction costs the least.
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Solution: (1) Let the total engineering quantity be s, the velocity of engineering team A is v1, and the velocity of engineering team B is v2, then the system of equations: s v1=30
s/v2=20
v1=s 30 v2=s 20
A and B construction at the same time, the total speed is v1 + v2 = s 30 + s 20 = s 12, so the number of days required n = s (s 12) = 12 (days) 2), the cost of A sole construction m1 = 200 * 30 = 6000 The cost of B alone construction m2 = 280 * 20 = 4800 The cost of joint construction m3 = (200 + 280) * 12 = 5760, so the choice of B team alone construction is the most cost-effective.
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1) The sum of 1 divided by 1/30 + 1/20 equals 12 days to complete.
2) A alone construction costs 200 * 30 = 6000 yuan, B alone: 280 * 20 = 5600 at the same time (200 + 280) * 12 = 5760 yuan, so B alone to complete the province, the disadvantage is slow.
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1) 1 (1 30 + 1 20) = 12 (days).
2) B is the most cost-effective to build alone, because as long as 5600 yuan, this price is the cheapest.
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Divide 1 by 30 and 20 and 12 days and the second one is also very simple Do it yourself.
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2-kxy-3xy-3y 2-8=x2-(k+3)xy-3y2-8 does not contain xy, then k+3=0, k=-3 because the polynomial (a-4)x to the power of 4 - (5+b)x to the power of 5 + the power of x to the power of 2 -3 is about the quadratic polynomial of x, which means that the coefficients of the 4th power of x and the 5th power of x are 0
Therefore, it can be obtained: a-4=0,5+b=0.
So: a=4, b=-5.
a-4)x to the power of 4, which can be denoted by: (a-4) x 4. 1
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1.What about k in a polynomial?
2..a=4,b=2,a+b=6
0 and ≠-1, (-m+1) polynomial.
m= 1, 2nd order polynomial.
m>0 and ≠1, (m+1) polynomial.
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Solution: Suppose the distance is s
The speed of the car is 20m s
2s=20*4+340*4
s=720(m)
Answer:..
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72k/h=72/
Sound walking: 340*4=1360m
Car walking: 20*4=80m
The sound is more than a person, and the distance from the location of the sound to the valley is 2 times (you can draw a picture yourself to see the .......))s=(1360-80)/2=640m
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72 km/h = 20 m/s.
20*4=80 meters.
340*4=1360 meters.
1280 2 = 640 meters.
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Set the reverberation to be heard when you move away from x
72km h=20m s, you can quickly know that 2 (x+4*20)=340*4+4*20
x=640
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(1) Solution: If x cars are set to transport B vegetables, then 8-x x + cars are to be transported to C vegetables
x+x=2∴8-x=6
Answer: 2) Solution: If the car transporting vegetables A is x, then the car transporting vegetables B is 8-x 500*2x+700*1(8-x)=65001000x+5600-700x=6500
1000x-700x=6500-5600
300x=900
x=3∴8-x=5
Answer:..
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Brother, it's been almost two months since I graduated from my senior year of high school. I've almost forgotten what I've learned, haha.
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Question 1: Since the common solution is x=1, 1+b=a+3, so b=a+2, so (a-1)x1, x<1; a<1, x>1; a=1, there is no solution.
Question 2: According to the formula, we can get a(b-3)x+b, so it becomes bx+b<0, b(x+1)<0; And then because K1>K2, B-3>-3, B>0
So x+1<0; x<-1
Give it points, it's hard enough to get 5 points.
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Are you sure it's the first year of junior high school、、、
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1. The common solution of y=x+b and y=ax+3 is x=1, and the calculation is obtained by substituting x, 1+b=a+3, that is, b-3=a-1
x+b ax+3 can be transformed into x<(b-3) (a-1), then the solution set is x<1
2. From the problem, it can be seen that x>a, and x<1, if there are only 3 integer solutions, then there are only 3 solutions, 0, -1, and -2, so the range of a is:
3k2,
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Solution: Simplifying the original formula = kx -2x +2 3 y 2 -3 2 x -1 3 y 2
k-7/2 )x +1/3 y^2
As can be seen from the problem, when x = 2 and x = -2, the values of the algebraic equation are equal.
So, (k- 7 2)*2 = (k- 7 2)*(2) so k= 7 2
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First, we bring x=-2 and y=2 3 into the equation to get -2k+7+12 27;Then substituting x=2 and y=2 3 into the equation gives 2k-7+12 27, and finally makes -2k+7+12 27=2k-7+12 27, and solves k=7 2
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The answer is 2 7
Multiple choice questions will not.
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Multiple choice: Because -x+2y=6, x-2y=-6
Original formula = 3*(-6)*(6)+5(2y-x)+6
Solution: Set the purchase price to be X yuan per piece.
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