15x 5x 2 0 configuration method in detail

Divide both sides by 5 at the same time, and the quadratic term coefficient becomes 1.

x^2-3x=0

Add half of the square of the coefficient of the primary term on both sides, i.e., the squared, to obtain.

x^2-3x+

The square is plus or minus.

i.e. x1=0 x2=3

The equation is deformed: x 2 - 5 2 x = -1, and the formula is obtained: x 2 - 5 2 x + 25 16 = 9 16, that is, (x- 5 4) Qing brother 2 = 9 16, and the prescription is Hongzheng sleepy:

x- 5 4 =±3 4 ..

Equation x22x-15 = 0, deformation gets: x2

2x=15, a sparrow.

Matching years of lead: x2

2x+1=16, that is, (x-1)2

16, the square gets: x-1=4 or x-1=-4, the solution gets: x15, x2

Solve with the matching method: Solution:

3×2+10x+5=0

3[ 2+(10 3) ]5=0

5 3) Jane Tsai Yin2 = 10 Qi Dou 9

5/3=√10/3or-√10/3

x=(-5+√10)/3 or (-5-√10)/3

Divide by 2 on both sides, get, x 2 + 5 2 x- 1 2 = 0, shift the term, get x 2 + 5 2 x = 1 2 , formula, x 2 + 5 2 x + 25 16 = 1 2 + 25 16 , x + 5 4 ) 2 = 33 16 , solve this equation, or the world feast this x+ 5 4 = 33 4 , then x 1 = 33 -5 4 , x 2 = 33 -5 4

The stupid root of this chain potato with an equation is not a rational number, and it cannot be matched by a method.

You can use the hand cherry formula method, a=-2, b=-5, c=10, x=[-b (b -4ac)] 2a), and substitute it to obtain x=(-5 105) 4.

Summary. pro, x=1, x=5

1 2x 2-3x+5 2=0 is used.

Dear, that's the title, right?

Would you like to see if your topic is on this?

If not, can you take a ** picture of the teacher?

pro, x=1, x=5

Are there any other questions that the teacher needs to solve?

5x^2+10x+15＝0

x^2-2x+1＝4

x-1)^2＝4

X-1 Yugakure 2

Hao Kai Hall x 3 or x Sun Hail -1

1. Interpretation of methods.

The unary quadratic equation ax 2+bx+c=0, a≠0 can usually be solved by two methods: the matching method and the root finding formula.

Second, the solution demonstration.

Solution: (x-5 2) 2=21 4, so x-5 2= 21 2 so x=(5 21) 2

3. Description: When formulating, you can find half of the coefficient of the term.