Math Problem Solving The first problem requires steps .

1.Workshop A counts 10 copies, and if one of them is transferred to B, there are still 10-1 = 9 copies, and the number of people in the two workshops is equal, so B is also 9 copies, so B turns out to be 9-1 = 8 copies.

Per serving: 216 divided by 8 = 27 (person).

A: 27*10=270 (person).

2.3 4 A = 1 3 B, then B = 9 4 A, then 3 4 B = 9 4 A * 3 4 = 27 16 A.

As a result, there are 2 more surfaces in one knife, and each surface area is 4*4=16 (square centimeters).

The total extra surface area is 3 * 3 * 2 * 16 = 288 (square centimeters).

Method 2: Large cube surface area: 6*4*4=96 (square centimeters).

Each surface area of all small cubes is 6 (square centimeters), and there are a total of 4*4*4=64.

So the surface area becomes 64*6=384 (square centimeters).

Subtraction: 384-96 = 288 (square centimeters).

4.Conversely, with this same result, subtract 4 to get the first number, add 4 to get the second number, divide by 4 to get the third number, and multiply by 4 to get the fourth number. The sum of these 4 numbers is 100 - is that the equation?

Let the equal result be x, then:

x-4)+(x+4)+x/4+4x=100

25/4x=100

x=16, so these 4 numbers are 20, 12, 4, 64.

5.Let the wire be x meters long. Then the square side length is x 4 and the radius of the circle is x 2. (here =.)

x/4 - x/2π =

x - 2x =

x = wire length.

1.Let the original number of people in workshop A be x, and the equation x-x 10=216+x 10 can be listed from the problem, and x=270 can be solved

5.Let the length of the wire be l by the radius of the circle r=l 2 and the side length of the square a=l 4

So l 4-l 2 = calculated l = taken.

1.Suppose x people are transferred from workshop A to workshop B, then there are 10x people in workshop A, then 9x=216+x, x=27, then there are 270 people in workshop A.

2., assuming that the number A is 4, then B is 9, 9*3 4 4=27 16

3.The original surface area was 96, and the surface area after sawing was 64*6=384, increasing by 384-96=288

4.Suppose the number obtained after the change is x, then x+4+x-4+4*x+x 4=100, and the solution is x=16, then 4 numbers are.

5.Assuming that the side length of the square is x, then the radius of the circle is equal to the circumference of 4x= *2* (solve x = take the length of the wire in meters.)

1) There are x people in the armor workshop then.

It can be solved x=270 The original 270 people in workshop A are obtained.

2) 3 4 A = 1 3 B B = 9 4 A.

Then 3 4 B = 9 4 A * 3 4 = 27 16 A 》3 4 B = 27 16 A.

I don't understand the fifth question.

1. Assuming that the number of people in workshop A is a, then, set up the equation: a*(1-1 10)=216+a*1 10, and the solution is a=270

2. Let A be x, B be y, 3x 4=y 3, and the solution is y=9x 4, 3y 4=9x 4*3 4=27x 16

Subtraction of logarithms:

2-log2(5)=log2(4)-log2(5)=log2(4/5)

Logarithmic identity:

2^(log2(4/5))=4/5

With the auxiliary angle formula:

y=2+3 cos(x+), where tan =3, 2) = 13 cos(x+).

The range of the cosine function is [-1,1].

The maximum value of y is 13

y=2cosx-3sinx

13cos(x+φ)

where, tan = 3 2).

Therefore, when cos(x+ )=1, the maximum value is 13.

1 (1) 6 outfits (2) 8 selections, 15 selections (3) 240 different combinations (4) 20 (5) 25 types, 20 (6) 64 (7) 312 (8) 9 (9) 6 (10) 12 types.

2(1)b(2)b(3)d(4)c(4)a3(1)p(2,3)=6 species.

2）a. p（3，6）=6*5*4=120b. p（2，6）=6*5=30

3) a. p4-p3=4*3*2*1-3*2*1=18b.p2*p2=4 species.