What are the rules for naming metaaluminic acid such as bias and subordinate and high ?

You can remember this in particular.

First of all, there are only two biases that we are often exposed to: the first metaaluminic acid (root) metaphosphoric acid, we can find that the valency of the elements has not changed, it is just an ordinary acid that has detached a water molecule, which is bias.

And then again, there is a high and by the way.

This is all arranged according to the valence You can also make a special note: generally take Cl as an example: HCL4, perchloric acid, HCO3, chloric acid, HCLO, hypochlorous acid.

Take sulfur as an example H2SO4 sulfuric acid H2SO3 sulfurous acid.

H3alo3 is called aluminic acid, which forms metaaluminic acid after removing a part of water, and "bias" refers to the new acid formed after the original acid is removed from a part of water, such as metaphosphoric acid, metaaluminic acid, etc. The "high" in perchloric acid refers to the chlorine element with the highest valency of +7 valence, and then +5 valence chlorine chloric acid, +3 valence chlorous acid, +1 valence hypochlorous acid and other "bias" acids are acids with constant valence, and "high", "sub" and "secondary" and so on refer to the level of valence.

The "high" in perchloric acid means that the valency of chlorine is the most ** (+7), and the metaaluminic acid is not known, sorry.

Metaaluminic acid is halo2, also known as tetrahydroxyaluminic acid or HAL[OH]4, tetrahydroxyaluminic acid can be regarded as metaaluminic acid plus 2 water. Metaaluminic acid is a weak acid, an acid that is weaker acidic than carbonic acid.

Metaaluminic acid and tetrahydroxyaluminic acid are actually two compounds, but high school textbooks consider them old discovery errors. In fact, they have different compositions and structures.

Chemical reaction. Cannot react with CO2. But if it's a metaaluminate solution, it's fine. Because metaaluminic acid is less acidic than carbonic acid, it is equivalent to the replacement of weak acid by strong acid, (taking sodium metaaluminate as an example) to generate sodium carbonate and aluminum hydroxide precipitation, and if CO2 is excessive, sodium bicarbonate and aluminum hydroxide precipitation will be generated.

Metaaluminate can react with excess hydrogen ions (strong acids) to form trivalent aluminum ions.

alo2- +4h+ = al3+ +2h2o

alo2- +h+ +h2o =al(oh)3↓

al(oh)3 +3h+ = al3+ +3h20

Al(OH)3 can be regarded as a monobasic weak acid or a ternary weak base for the following reasons:

al(oh)3 + 3h+ = al3+ +3h2o

al(oh)3 + oh- = alo2- +2h2o

Therefore, it can be regarded as the reaction of the ternary weak base with the acid, and the reaction of the monobasic weak acid with the base.

Note: The reason why it is said weak is because it is all weakly ionized. The compound is an amphoteric compound.

Al(OH)3 is a very weak electrolyte, Al3+ and AlO2- do not coexist in aqueous solution, and double hydrolysis occurs, and the products are both Al(OH)3

al3+ +3alo2- +6h2o ═ 4al(oh)3↓

Metaaluminate can react with acid solutions (including all strong and weak acids exposed to in high school, including ammonium ions) to form aluminum hydroxide precipitates, and the chemical equations that need to be mastered are listed below

alo₂﹣＋h﹢＋h₂o＝al(oh)₃↓

naalo₂＋hcl＋h₂o＝al(oh)₃↓nacl

2naalo₂＋h₂so4＋2h₂o＝2al(oh)₃↓na₂so4

alo₂﹣＋ch₃cooh＋h₂o＝al(oh)₃↓ch₃coo﹣

naalo₂＋ch₃cooh＋h₂o＝al(oh)₃↓ch₃coona

2alo₂﹣＋co₂＋3h₂o＝2al(oh)₃↓co₃²﹣

2naalo₂＋co₂＋3h₂o＝2al(oh)₃↓na₂co₃

alo₂﹣＋nh4﹢＋2h₂o＝al(oh)₃↓nh₃·h₂o

naalo₂＋nh4cl＋2h₂o＝al(oh)₃↓nh₃·h₂o＋nacl

alo₂﹣＋hso4﹣＋h₂o＝al(oh)₃↓so4²﹣

naalo₂＋nahso4＋h₂o＝al(oh)₃↓na₂so4

The essence of the reaction is that metaaluminate reacts with hydrogen ions and water to form an aluminum hydroxide precipitate.

In general, the following ionic reactions are commonly examined.

1. Add a small amount of hydrochloric acid dropwise to sodium metaaluminate.

ALO2 +H++H2O=AL(OH)3 2, sodium metaaluminate dropwise with excessive hydrochloric acid.

alo2－+4h+ =al3++2h2o

3. A small amount of CO2 is introduced into sodium metaaluminate

Excess CO2 is introduced into 2alo2 +CO2+3H2O=2Al(OH)3 +CO32-4 and sodium metaaluminate

AlO2 +CO2+2H2O=Al(OH)3 +HCO3-5, sodium metaaluminate solution reacts with aluminum chloride solution.

3alo2－+al3++6h2o= 4al(oh)3↓

You can use the ionization constant of the weak acid, the acidity of the weak acid.

ka= of metaaluminic acid

Ka2 = of bicarbonate

KA = of hypochlorous acid

The ionization constant of metaaluminic acid is the smallest, so the acidity of metaaluminic acid is weakened, followed by bicarbonate, and hypochlorous acid is the most acidic.

Modern science no longer acknowledges the existence of metaaluminic acid, because it does not exist in this way. Jujube osmosis is actually tetrahydroxyaluminic acid.

i.e. hal[oh]4. It's actually aluminic acid (aka aluminum hydroxide.

Combined with a stool spine with water, it is a weak acid, an acid that is weaker acidic than carbonic acid.

Metaaluminic acid, also known as tetrahydroxyaluminic acid, is a weak acid, and the properties of metaaluminic acid are as follows:

1. Metaaluminate solution can react with carbon dioxide to form sodium carbonate and aluminum hydroxide precipitation, and sodium bicarbonate and aluminum hydroxide precipitation will be generated if CO2 is excessive;

2. Metaaluminic acid is less acidic than carbonic acid, and carbonic acid is formed by substitution reaction to form Changli metaaluminic acid;

3. Metaaluminate reacts with excess hydrogen ions to form trivalent aluminum ions of Huixun Brigade;

4. Sodium metaaluminate exists in the form of coordination compounds in aqueous solution.

Yes, equivalent to aluminum hydroxide.

1. First of all, aluminum generates aluminum ions under acidic conditions. The chemical equation is as follows: 2AL (Aluminium) + 6HCl (HCl) = 2ALCL (Aluminium Chloride) + 3H (Hydrogen).

2. Secondly, aluminum ions react with a small amount of NaOH (sodium hydroxide): chemical equation:

AlCl3 (aluminium chloride) + 3NaOH (sodium hydroxide) = 3NaCl (sodium chloride) + Al(OH)3 (aluminium hydroxide).

3. When NaOH (sodium hydroxide) is excessive: chemical equation:

AlCl3 (aluminum chloride) + 3NaOH (sodium hydroxide) = 3NaCl (sodium hydroxide) + Al(OH)3 (aluminum hydroxide).

Al(OH)3 (aluminum hydroxide) + NaOH (sodium hydroxide) = Naalo2 (sodium metaaluminate) + 2H2O (water).

After the above steps, aluminum generates metaaluminate.

Aluminum is an amphoteric metal, which forms aluminum ions under acidic conditions, and reacts with strong alkalis to form metaaluminate under strong alkali conditions.

Aluminum reacts with a strong base to form metaaluminate, which does not react with a weak base.

The reaction between sodium metaaluminate and hydrochloric acid is not a redox reaction, but the neutralization of metaaluminate and hydrogen ions in hydrochloric acid to form metaaluminic acid, which combines a molecule of water to form aluminic acid, which is aluminum hydroxide. Follow my prompt, trusting the clever you to write its reaction equation.

Sodium metaaluminate and excess hydrochloric acid form aluminum hydroxide and sodium chloride, and aluminum hydroxide and hydrochloric acid undergo neutralization reaction.

H+ a small amount, AlO2- +H+ +H2O=Al(OH)3 precipitate.

H+ excess continues to react with Al(OH)3.

2al(oh)3+6h+=2al3+ +3h2o