How do you solve this equation? How do you solve this equation?

a-b+c=0 (1)

4a+2b+c=3 (2)

25a+6b+c=60 (3)

1)*2+(2) gives 6a+3c=3

2a+c=1 (4)

1)*6+(3) gives 31a+7c=60 (5)5)-(4)*7 gets 17a=53

a=53/17

Substitute a=53 17 into (4).

c=-89/17

Substitute a = 53 17 and c = -89 17 into (1) to get b = -36 17a = 53 17

b=-36/17

c=-89/17

c=b-a1

4a+2b+b-a=3 2

25a+6b+b-a=60 3

2= 3a+3b=3 a+b=1 4

3= 24a+7b=60 6

4= a=1-b 5

Then take a=1-b in 5 and put 6 into it.

Equations with unknowns are called equations. In this case, there are no unknowns or equations, so it is not an equation. It's simplification or calculation!

First, the denominator is rationalized, and then simplified and calculated. The result is root number 10, and the process is shown below.

This is not an equation, it's a fraction or fraction with a root sign. The denominator is rational: the same up and down multiplied by 10+2

The equation is solved a=240, and the calculation process is as follows:

This imitation equation looks complicated. In fact, the big search is relatively simple.

Solve systems of equations. 4 A 2+2 b 2=1 1 A 2+14 4b 2=1

Let x=1 a 2, y = 1 b 2, then.

4x+2y=1 ③

x+7y/2=1 ④

4- Gotcha. 12y=3y=1 4, substitute y=1 4.

x=1 Lao He 8

Then, 1 a 2 = 1 8, 1 b 2 = 1 next to late 4, so, a 2 = 8, b 2 = 4.

This is a good solution, that is, the square of a and the square of b are regarded as an unknown hidden sum, this is the binary quadratic fractional equation, which is solved by the elimination method, and the square of a and the square of b are obtained, then the value of a and the value of b will also come out, because it is a fractional equation, you have to test that the denominator can not be zero, and you can stare at it.

This is the first system of equations, let the first or second equation be converted into an expression about b, and then bring in another quadratic equation that is self-becoming a modular elimination a to solve the value of a, and then bring in the original equation to solve b. Number of yards.

In this system of equations, if a square part and b square are regarded as an unknown, then this is a binary system of equations. It's very convenient to solve and get the answer. First find out how much a square and a square b are equal to, and then after the filial piety is cracked, you can get a and b each equal to a and b.

This is a binary one-time triumph equation to be solved by cross-conversion method. You can stare and slam them into two new equations. It is then calculated until there is only one unknown left.

But the recent Nescafe coffee has changed a lot from the previous taste, so you will feel that the taste of the withered ear is different from the previous guess, and it does not have the previous taste, resulting in that rich aroma.

So as long as this Nescafe is **, there is no need to worry about anything else.

Your ** photo is very vague, you want to solve this equation, you can't see clearly**, I can't solve it for you.

4/a²+2/b²=1 ①

1 晌fierce a +14 4b = 1

Solution: Equation 4.

4 A +14 Bend B Banquet Bridge = 4

Formula - Formula.

12/b²=3

b²=12/3=4

Substituting b = 4 into .

4/a²+2/16=1

Solution: a = 32 7

How long does it take for this price to be absolutely reliable, as long as it goes to Huadu, the lender, the black gold, supervises each other, and what time it will be sent to your home, this equation is like this.

Solution: The system of equations is 4x-5y+m=0, x 25+y qiaodan 9=1;Reduced to x 25+1 9 [(4x+m) 5] =1,9x 25+(4x+m) 25=9,9x liter+(4x+m) =225,9x +16x +8mx+m -225=0,25x +8mx+m -225=0,δ=8m) -4 25 (m -225)=22500-36m, when filial piety disturbs -25 6 m 25 6, it gets: x=-4m (5625-9m).

Solve functionals with ordinary differential equations.

Hope you understand.

x/y=1/

x*y= is composed of the formula y=

Substituting the second formula: x*(

x=,y= I don't know how many digits to be exact, so let's change the shot and count it as 2. I don't know if it's right haha, I can't do math when I read the book of Hefan Envy. Sedans socks.

This problem looks simple, I did it for a while, but I didn't make it, and the solution is very simple, the left side of the equation is a-1, but this a-1 matrix can't be calculated, and the result can be calculated like this.

The elementary row transformation is performed by the left multiplication of the matrix, and the inverse matrix is obtained, and then the matrix multiplication is used.

Use the first formula, bring in the second formula, find cosr, and then bring the result into the first one

The first equation can get i3=i1+i2, and the third equation is substituted to become a binary system of equations, which can be solved by conventional methods.

This is a system of ternary equations with three unknowns, i1, i2, i3, and three equations, which can be eliminated by the element method.

The original system of equations is numbered sequentially

24+ got.

39i2=-195,i2=-5 substitute i2=-5 to get i1=10, then i2=-5, i1=10, substitute i3=5

How can this equation be solved?