How do you write these math problems? How do you write these math problems?

25.(1) b

2) Sn squared = b

3) On the straight line AB, when point P coincides with point A, by the title, point Q is the midpoint of the line AB, then the line AP=0, PQ=BQ. Here's the idea.

I just wrote it on the paper.,But I found that the words are too ugly.,The pixel of the mobile phone is not high.,Don't send the picture.,Just write it.,If there are individual letters in the process that are wrong.,Please forgive me.,If there's anything unclear.,You can ask.。

Evidence: Pass point C to the direction of AB to make the ray CN, so that ACP= PCN, take the M point on the CN, make CM=AC, connect PM, MQ

In ACP vs. MCP:

ac=cm，∠acp=∠mcp，pc=pc△acp≌△mcp

ap=pm，∠cap=∠cmp=45°

In BCQ and MCQ again:

bc=cm，∠bcq=∠mcq，cq=cq△bcq≌△mcq

bq=mq，∠cbq=∠cmq=45°

pmc+∠qmc=90°

pm^2+mq^2=pq^2

ap^2+bq^2=pq^2

I can't see it clearly.,If only this picture could be straightened.。

1): Production in February (1-15%) A units.

2): profit 64-x yuan.

3）：a/（1+10%）

1）：10*5%+10%x

2）：（2x+5y）/100

3）：（2x+1）*x

26. The function is continuous on [0,2].

27. The left and right limits and function values are all 0, continuous.

29. Obviously, x≠0 is continuous, at x=0, the left limit = e 0 = 1, the right limit = a+0 = a, the function value f(0) = a, to make the function continuous on r, only a = 1

31. Remembering f(x) = x 5-3x-1, then f(1) = 1-3-1=-2<0, f(2) = 32-6-1=15>0, since the function is continuous in [1,2], it is known by the mediator theorem that there is x0 (1,2) so that f(x0) = 0, so x 5-3x=1 has at least one root between 1 and 2.

32, y(1) = -5<0, y(2) = 8>0, and the function is continuous at [1,2], so it is known from the mediatority theorem that there is x0 (1,2) so that y(x0) = 0, i.e....

This part of the problem needs to use the volume formula of cylinder and cone, and you can't do it if you don't know the volume formula of cylinder and cone. The volume of the cylinder = the base area is high, the volume of the cone = 1 3 the base area is high, the bottom surface of the cone and the cone are both circles, and the area of the circle = r, so, the answers to the above questions are.

3 and 3 or, in primary mathematics, they are generally taken, while in secondary mathematics, if the accuracy of the calculation is not specified, the result is expressed in an algebraic formula, and cannot be taken, otherwise it is considered an error.

And 8 The second problem should be applied to the formula of the circumference of the circle, the circumference of the circle 2 r(1) the volume of the cone 1 3 (6 2) 4=

2) Bottom radius.

So, the base radius =

Cone volume 1 3

15.Connect the point A and the point C, because ABCD is a parallelogram, so the diagonal intersects at their midpoint O, and it is easy to prove that the quadrilateral AFEC is a parallelogram, so the diagonal AC intersects with EF at point O, so EF passes through FC.

One, 1, b 2, b 3, c 4, b 5, y=

6. y=y=The questions will be asked separately in the future.

11、 1

12. Can't see clearly.

13、 a=29

14. No, there should be a definition in the book.

or 6 times the root number of 7

n-2