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Try to brush the version.
The tutorial is as follows. iphone 3gs
iphone 3g
iPhone generation.
Hope you succeed.
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Did you get it? There is no crack.
The crack patch is for.
You have only one way: restore, re-jailbreak, unlock, if you need to activate it, you need the original SIM card, and the unlocked version doesn't use the original card, and you don't need to activate it.
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Obviously, just brush the machine again.
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My answer is similar to the answer of the master below!
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(1) Let half a = third b = quarter c = 201120122013 = k, then a = 2k, b = 3k, c = 4k
If m = 4a + 3b - 4 parts of 4c + 4b + c, then m = (6k + 12k + 4k) (8k + 9k - 16k) = 22k k
Divide 22 into the sum of several integers so that their product is maximized.
22 should be divided into several sums of 2s as much as possible.
i.e., 22 2 2 ......2 (sum of 11 2's) then, n 2 2 ......2 (product of 11 2's) 2 to the 11th power (3) 1/2x4 + 1/4x6 + 1/6x6 + 1/6x8. nx(n+2) one.
1/2)×(1/2-1/4+1/4-1/6+1/6-1/8+……1/n-1/(n+2))
1/2)×(1/2-1/(n+2))
n/4(n+2)
2 to the 11th power) 4 (2 to the 11th power + 2) (2 to the 8th power) (1 + 2 to the 10th power).
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(1) A 2 = B 3 = C 4 = 201120122013 = K then A = 2K, B = 3K, C = 4K
If m=(3a+4b+c) (4a+3b-4c) (there should be parentheses, right?) Then m=(6k+12k+4k) (8k+9k-16k)=22kk
Divide 22 into the sum of several integers so that their product is maximized.
Then 22 should be divided into 6 3's and 1 4, and their product size should be n=3 6x4=2916
3)1/(2x4)+1/(4x6)+1/(6x8)..1 [n(n+2)] (There should be parentheses, right?) )
1/2)(1/2-1/(n+2))
1/2)[(n+2)-2]/[2(n+2)]=1/2)n/[2(n+2)]
n/[4(n+2)]
2916/(4x2918)
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This is equivalent to 4 more undersides, divided by 4.
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A :2 2Degree * degree = degree degree degree 12 * 2 = 60 degrees 60 degrees * degree = degree degree = degree = 6 degrees * degree = two.
Thank you for the trouble to adopt!
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Because AD bisects BAC, the angle EAD is equal to the angle DAC, and because, C=90° ed BC
So ed parallel ac
So the angle DAC is equal to the angle EDA (inner wrong angle).
So the angle EDA is equal to the angle EAD
So ed=ae (equiangular to equisome).
Because df ab, ed parallel ac
So the parallelogram aedf
and because ed=ae (the flat four of the marginal equities is diamond-shaped).
So it's diamond-shaped.
The diamond diagonal is bisected perpendicular to each other.
Finished...
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