Find a math problem for the second year of junior high school, and ask for a math problem for the se

Vedic theorem: x1 + x2 = -4k, y1 + y2 = k squared, add the two equations given in the problem to get the square of -4k=4+k, solve k = times x2 = 3, y1 times y2 = p, x1 = y1 + 2, x2 = y2 + 2, multiply the two equations, then there is x1 times x2 y1 times y2 + 2 (y1 + y2) + 4, thus solving p=9

First, for any one of the quadratic equations.

x1+x2=-b/a

x1*x2=c/a

x1-y1=2……（1）

x2-y2=2……（2）

x1-yi+x2-y2=2+2

x1+x2)-(yi+y2)=4

x1+x2=-4k

yi+y2=k^2

4k-k^2=4

k^2+4k+4=0

k1=k2=-2

Replace k = -2 generations x 2 + 4 kx + 3 = 0

x^2-8x+3=0

Trouble, don't count.

Find x1 and x2

x1-y1=2, x2-y2=2, find y1 and y2y1*y2=p

According to Vedic theorem, x1+x2=-4k, y1+y2=k, add up the above 2 to solve k, and multiply x1=y1+2, x2=y2+2 to solve p.

Proof: On equilateral ABC

a=∠c=60°

prc+∠cpr=120°

qpr=60°

apq+∠cpr=120°

prc=∠apq

In APQ and CRP.

a=∠cprc=∠apq

pq=pr△apq≌△crp

aq=cpac=6，ap=2

pc=4aq=4

The answers are all in the picture, see for yourself, don't forget to give some points.

Solution angle a = angle f

Because angle 2 = angle AHC (equal to the apex angle).

And angle 1 = angle 2

So db ec

So angle DBA = angle c

Angle c = angle d

So the angle dba = the angle d

So DFAC

So the angle a = the angle f

====Haha, I remember that I didn't do such a winding question when I was in my second year of junior high school, and I'm now a freshman in high school.

In other words, I worked so hard to answer while facing the picture.

Just give me that, thanks!

Because 2= AHC [equal to the apex angle].

and 2 = 1 [Title].

So ahc = 1 [equivalent substitution].

So db ec [isotope angle equal].

Then C= DBA [due to parallel].

and c= d [Title].

So DBA= D [Equivalent Substitution].

So df ab [the inner wrong angles are equal, so they are parallel].

So f= a [because of parallelism, the inner misalignment angles are equal].

There are x dormitories, a total of y people, then there are: y=4x+20;and x is an integer;

When there are 8 owners in each dormitory, and one dormitory is not full and there are no vacant rooms, then there is 0 to 5< x<7, because x is an integer, x=6, y=44, so there are a total of 44 boys living in the school.

There are x names for boys, room y, and a system of equations.

4y+20=x

8y-8 brings x=4y+20 into the inequality.

Find y=6 and x=44

There are x rooms in the dormitory, 8 (x-1)< 4x+20<8x, x is an integer, get x=6, boys 4x+20=44

There are x dormitories, and there are Y male students living on campus.

then 4x+20=y and 7x then 7x<4x+20<8x

Solve 5 because x is an integer, so x=6

Therefore, the male students in the boarding school y=4*6+20=44 (people).

There are x rooms in the dormitory.

8x-7<=4x+20

4x+20<=8x-1

8x-7<=4x+20

4x<=27

x<=4x+20<=8x-1

4x>=21

x>=<=x<=

Therefore, x=6 school boarding boys in total: 4x+20=4*6+20=24+20=44.

It can be divided into (A+4) (A-2) Answer 1 of this question

Let v1 be walking, v2 be cycling, and walk to work time t

v1t=,v2(t+1/3)=,3v1=v2

v1=5,v2=15(km/h)

It feels like there are fewer conditions. Go back and have a good look.

The triangle area is 4, and then CB = root number 5, so the obtained is equal to 8/5 of the root number

First of all, the area of this triangle is 4, and the shortest side of the triangle is 5, so the height is 8/5 times that of the root number.