A few exercises on chemical electrolytes in the first year of high school.

1) A is correct, the conductivity of the solution is related to the ion concentration in the solution, the ions in ammonia water are mainly ionized by ammonia monohydrate (weak electrolyte), the ion concentration is small, and the conductivity is weak; After the introduction of HCl gas, the reaction generates ammonium chloride (strong electrolyte), and all the strong electrolyte is ionized, so the ion concentration increases and the conductivity increases. B is false, AGN3 + NaCl = AGCL (precipitation) + nano3 It can be seen that the concentration of ions decreases due to the formation of precipitate after the reaction, so the conductivity is weakened. (2) The answer is b 2[cu2+]+k+]=2[so42-]+cl-] because cu2+:

k + =3:4 can be set to 3 and 4 respectively, 2[SO42-]+Cl-]=10, and then the answers are substituted separately, and the substitution of item b is expanded by 2 times at the same time, which is in line with this relationship, and the rest of the answers are not.

，zn-2e-=zn2+；cu，cu2++2e-=cu；zn+cuso4=znso4+cu

2.It becomes lighter, precipitates a red hail substance, and turns blue.

Electrolytic NaCl:

Cathode: 2h+ +2e- =h2

Anode: 2Cl- -2E- = Cl2

Electromold slag hydrolysis CuCl2

Cathode: Cu2+ +2E- = Cu

Anode: 2Cl- -2E- = Cl2

4.Negative, plating positive, plating electrolyte of metal ions, electrolysis.

1.Zinc is the negative electrode and copper is the positive electrode.

Zinc loses electrons and becomes divalent zinc ions, and divalent copper ions gain electrons and become copper.

1. zn,zn-2e-=zn2+,cu,cu2++2e-=cu,zn+cu2+=zn2-+cu2+

2. Deepen, liquid air slowly dismantled red, molded solid precipitation, blue.

co2 ca(oh)2=caco3|H2ocaCO3 CO2 H2O=Ca(HCO3)2 free electrons. Free-moving charged ions. There is no ionization,

Hydrochloric acid conducts electricity. Acetic acid solution is OK. Sodium chloride solution can. Sodium hydroxide solution can. Ammonia can.

Judgment: First of all, if the electrolyte is a compound, it is not a mixture of elemental substances. Secondly, the substance should be able to conduct electricity in the molten state or its solution.

It is the electrolyte that does not necessarily conduct electricity, for example, sodium chloride itself cannot conduct electricity, but it can conduct electricity in aqueous solution and molten state, and it is a chemical compound, so sodium chloride is an electrolyte.

I only know that hydrochloric acid is OK, sodium chloride solution is OK, sodium hydroxide seems to be OK, and the rest is not known. At that time, I was using rote memorization, and I knew the pattern when I was more exposed. Here are some people who know chemistry, I hope it will be useful to you.

The conductivity of the solution is realized by the freely moving ions, so the conductivity is related to the concentration of the freely moving ions in the solution and the amount of charge carried by the ions.

All of the above are electrically conductive. Because they are soluble in water, they can undergo ionization reactions, producing positive and negative ions. The electrolyte needs to be soluble in water to conduct electricity.

Cathode: Cu2+ +2E- = Cu

Anode: 2Cl- -2E- = Cl2

So when the copper element is generated, the chlorine gas produced is.

v = transfer electrons = electrons.

A Barium sulfate crystals b pure sulfuric acid c fused sodium hydroxide d molten alumina e liquid sulfur trioxide f alcohol g graphite h aluminium i aqueous solution of sodium chloride.

1) Among the above substances, the one that can conduct electricity is CDGHI

2) The one of the above substances that belongs to the electrolyte is ABCD

3) The non-electrolyte of the above substances is EF

4) ABCE that can conduct electricity after being dissolved in water in the aqueous solution of the above substances

The conductivity of the solution is related to the concentration of ions contained in it, and generally the higher the ion concentration, the better the conductivity. Barium hydroxide is a strong base and is completely ionized, so its solution has strong electrical conductivity. When sulfuric acid is added, barium sulfate precipitates and water are formed, so the concentration of ions in the entire solution decreases and the conductivity decreases.

Sulfuric acid was added until the barium hydroxide in the solution was completely reactive, and the ions had the lowest concentration and the worst conductivity. When sulfuric acid is added, there will be excess sulfate and hydrogen ions in the solution, and the ion concentration will gradually increase, and the conductivity will also increase. Hence the choice D.

Select C: H+ in a strong acidic environment can just inhibit the hydrolysis of Zn2+ and Al3+, and Fe3+ is reddish-brown, so A is not selected.

AG+ and Cl- precipitate, so B is not selected.

Strong acidic environment HCO3- does not exist, so D is not selected.

All I know is that B is not right, because there is agcl generation, and I am not very good at it when I first enter high school.

The yellow precipitate reacts with hydrogen ions to form carbonic acid, which then decomposes and runs away into carbon dioxide.

Strong acid, exclude D, because HCO3- will become CO2 or BaCO3 precipitate colorless, exclude A, because Fe3+ is yellow.

Transparent, excluding B, because AG+ and CL- will generate precipitation, so the answer is C

Generate AGCL precipitates for yellow and Cl.

and NH4+ to form NH3 and CO2

The answer is C