If there are 320 adenine in a gene in the DNA, it accounts for 20 of the total base of the gene

Since A is 20% and A has 320, there are a total of 320 20% = 1600 bases.

And because in the DNA duplex a=t, c=g

So c+g=1600-320*2=960

So there are 480 g.

Because you now have a total of 320 a.

The first copy requires 320 t, and the second copy requires 640.

So a total of 320 + 640 = 960

Actually, you can think of this as follows, the first replication is a DNA duplex replication, and there are 320 A to get 2 duplexes.

The second replication of two more DNA duplexes was replicated, and there were 320*2 A to obtain 4 duplexes.

The third replication has four DNA duplex replications, and there are 320*4 A to get eight duplexes.

Known conditions: a=320, because it is a DNA double-stranded, conforming to a=t, g=c.

1600-320-320=960=g+c

g=480.。。1）

Replicate once: c=g=480

Replicate twice: c=g=480 because there is a double chain, 480*2=960 added together: 960+480=1440

Adenine and guanine make up half of all bases, and adenine accounts for 20 percent of the total, so there are 480 guanine. The number of adenine and thymine is equal, so it takes 3*320=960 to replicate twice.

On a strand adenine than guanine accounts for 24% of the total number of bases of the DNA molecule, then it accounts for 48% of this strand.

Let guanine account for x of the chain, then adenine for xx+

Solution x=20%.

So adenine occupies.

On the other strand, thymine = adenine on this strand = 28%.

I don't want to type any calculation questions because I don't feel like I can write clearly.

I'll teach you a trick: two that don't correspond....The proportion is 50%, for example, this question A accounts for 15, which C and G each account for 35, whether it accounts for this chain or all of them are the same, it is very convenient to do the question, and it is not difficult to prove, you can try it yourself.........Hope it helps....

Purines and pyrimidines are paired, then, 70% and half and 35% are both sought.

Let guanine g be x, then adenine a is , then the thymine t on the other chain is also m, and each base of each chain is m, then a total of 2m.

x+ is found on-chain.

Choosing C, adenine (A) accounts for 30% of the total number of bases in a DNA molecule, according to the principle of complementary pairing of bases, thymine (T) also accounts for 30% of the total number of bases, and guanine (G) and cytosine (C) each account for 20% of the total number of bases;

To make the most guanine (g) in a chain, all guanine (g) should be on this chain, so that the total number of bases is n, then the chain contains all guanine (g) 20%*n, accounting for (20%*n) (n 2) = 40% of the chain

Double-stranded: A30% then T30% C 20% G 20%The maximum case of guanine on a chain is that all the gs are located in only one chain and the other chain has a content of g in that chain is 40% (the other 60% can be a ; Another chain 40% c 60% t ) answer c

d 70%

The maximum value of guanine and thymine in this DNA molecule is 70%, then the maximum value of guanine in a strand is 70%.

The answer c lets the proportion of g be x, and the proportion of a is , total, so x=10%, so a's is 14%, and the nucleus is paired with complementary bases, so the t on the other chain and the a of this chain are equal to the limbs, and the total number of bases in both chains is the same, so the answer is 14%.

Assuming that the DNA is a two-stranded strand, and the orange touch knows that this strand is the No. 1 delicate strand, let the ratio of the base circle of G1 be a, then the proportion of A1 bases is , and (G1+A1) (A+T+G+C)=24% (A+T+G+C=2(A1+T1+G1+C1) Pushout(G1+A1) (A1+T1+G1+C1)=48% Solve a=20% The proportion of A1 is T2=A1=28%.

This question is simple, no matter how many times it is copied, the offspring DNA is the same as the original DNA, there are 100 base pairs, of which A has 40, since A=T, so T is also 40, then C=G should be 60, so choose B