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Anonymous users2024-02-11Computer major, mainly computer operation, the test is to answer questions online, upload in the form of **, if you are familiar with C, C++ can also be programmed with C, but comparatively, it is a waste of time to be troublesome, MATLAB is better, the syntax of programming is the same as C, MATLAB is used for data processing, data fitting, and drawing are very convenient, and various functions are stored inside.
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Anonymous users2024-02-10The knowledge required for mathematical modeling can be summarized in a nutshell:
1. Mathematical modeling methods: optimization classes, evaluation classes, models, differential equations, various intelligent algorithms, graph theory, etc.
2. Software: MATLAB, Lingo, SPSS, etc.
Recommend the school garden digital model can be seen, there are a lot of mathematical modeling students, I hope to, thank you.
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Anonymous users2024-02-09High mathematics is not very important, modeling is mainly a systematic mathematical thinking, it is recommended that you look at operations research, you can get started as soon as possible.
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Anonymous users2024-02-08If the speed of a large truck is v (backwards are v 5), then the speed of the car is 3v (backwards are 3v 5).
If the reversing distance of the large truck is S, the reversing distance of the car is 4S1If you let the big truck reverse, because the speed of the car is greater than the speed of the big truck backwards, when the big truck exits this road, the car can also pass this road, leaving the big truck to complete this section of the road alone.
The reversing time of the large truck t1=s (v 5)=5s v The time when the large truck has completed this road t2=(s+4s) v=5s vThe total time taken by the truck is t1=5s v+5s v=10s v2If the car is reversed, because the speed of the big truck is greater than the speed of the car reversing, when the car exits this section, the big truck also completes the section, leaving the car to walk the whole road alone.
Car reversing time t3 = 4s (3v 5) = 20s 3v car after driving this road time t4 = (s + 4s) 3v = 5s 3v total time t2 = t3 + t4 = 20s 3v + 5s 3v = 25s 3v In summary, T2 is more reasonable to let the car reverse.
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Anonymous users2024-02-07Solution: The speed of the two cars reversing is 1 5 of their normal speeds, so the reversing speed of the car is 3 of the large truck.
Let the reversing speed of the large truck be V, and the reversing distance is S.
Then the reversing speed of the car is 3V, and the reversing distance is 4s.
The time taken by the car to reverse is t=4s 3v, and the time it takes for the big truck to take a taxi is t=s v, so the reversing time of the large truck is more reasonable.
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