A few high school biology problems rubbing eyelids with a loud sound

1. Various biofilms are not functionally independent of each other, but affect each other.

2. Hormone proteins.

3 Lysosomes are protein-degrading.

4 The role of ribosomes is to produce proteins, and germinated seeds need a large amount of protein, so there are many ribosomes.

Finally, rubbing your eyelids with a loud sound is not a serious illness, but it just means that you are tired.

1. All kinds of biofilms are interrelated in structure and function, and there is a division of labor and a relationship in function.

2. Antibodies, digestive enzymes, some hormones, etc.

3 Lysosomes hydrolyze some of the proteins.

4. The germinated seeds are vigorously metabolized and need more proteins and ribosomes. Dry seeds have a weak metabolism.

Sometimes rubbing your eyes does make a noise, and you may not have slept well.

1.The various biofilms inside the cell function similarly and have similar structures.

2.Secreted proteins refer to proteins secreted by cells, such as insulin secreted by pancreatic B cells. Others, such as various digestive enzymes secreted by villous epithelial cells in the small intestine.

3.Ignorance. 4.Because some proteins such as enzymes need to be synthesized during loading germination, and proteins are synthesized on ribosomes, the activity of ribosomes should be strengthened. (P.S. You have a stye, most likely caused by fire).

5.Ignorance. 6.Yes, only mRNA (messenger RNA).

The type of genotype can be determined first: for example, AAB*AAB can be divided into two categories to calculate its species: AA*AA and BB*BB, so there are 2*2=4 species; The offspring generation AA accounts for 1 2, AA accounts for 1 2, BB accounts for 1 2, and BB accounts for 1 2.

So: aabb:aabb:

aabb:aabb=1/4:1/4:

That's how 1:1 is calculated, and about the self-crossing of textbooks, it's the same as this, but it's just a lot of calculations, and it's a compulsory second course in the second year of high school.

1 Because the auxin of the terminal bud is transported downward, the side buds will also produce auxin, and the buds are more sensitive to auxin, so they will be inhibited.

2. Generally speaking, it is to make the side buds grow slowly. It's not about stopping.

This is the normal way. There are many easy ways to do this, but in general these two conclusions are to keep in mind.

You can buy a reference book for Wang Houxiong or something.

This is easy to do, just do a little math. Heterozygous self-inbred (assuming AA) and the F1 generation is AA:AA:

aa = 1:2:1 (the law of separation), that is, heterozygous accounts for 1 2

If self-breeding continues, the homozygous does not have trait separation, then just look at the heterozygous, and the heterozygous offspring are aa:aa:aa=1:

2:1,F2 heterozygous accounts for 1 2*1 2, and then find the law, the probability of heterozygous after n generation is (1 2) n, then the probability of homozygosity is naturally 1-(1 2) n.

Relative traits are traits that are determined by a pair of alleles and are clearly different, and the error is obvious.

Genotype is inferred from the law of segregation and phenotype is inferred from genotype.

One: You don't know what you're talking about, but the problem in this area is generally clear in combination with the law of graph separation and a little mathematical reasoning.

Two: Coats are not relative traits, only long and short, thick and fine are relative traits Three: draw a diagram and then combine the law of free distribution, you can know some basic trait classification ratio, like hybridization, the trait ratio is 3:

1, The self-crossing shape ratio is 1:1, if it is not clear, read more textbooks, do typical questions, of course, the most important thing is to follow the teacher.

I hope it helps you, I'm just going to say it in general, you have to rely on yourself, and it's not too late now. Say that you are very interested in biology, this section is a difficult one, you should seize the opportunity to take the class, come on!!

The percentage of homozygotes is equal to this, depending on how you manage in the first generation, different methods are different) (the first generation is heterozygous AA, then the second generation has half of the homozygous, the third generation has a quarter, that is, and so on).

The different types of expression of a trait in the same organism are called relative traits. (Actually, I don't think it's wrong, is there a suspicion of stealing the subject?) ）

Something out of nothing is hidden, and something out of nothing is also hidden.

1 d 2 d 3 In addition to viruses, cells are the material basis of life activities 4 The hepatitis B virus attacks cells invaded by viruses through the body's immune system.

The self-metasosis is n and the ratio of homozygotes is 1-2 n

There is nothing wrong with the second.

The third problem is to draw it out and analyze it, and the specific problem should be treated concretely.

Recessed, across, embellished, hydrophilic head, hydrophobic tail.

integral proteins, peripheral proteins, and lipid-anchored proteins

Hydrophilic and hydrophobic.

The correct answer is D.

This topic informs that if a female offspring is produced, the paternal gene must be W red, W is dominant, and it is impossible for a female to produce a female white trait, so a WW female white fruit fly cannot be produced.

Give the formula first.

The number of dehydrated water = the number of amino acids - the number of peptide chains.

570=x-4

x=574First, three bases correspond to one amino acid, but a gene has two chains, so it is equivalent to 6 bases corresponding to one amino acid.

Base number = 6 * 574 = 3 444

570 + 4 = 574

574 x 3 = 1722

1722 x 2 = 3444

Explanation: During the translation process, the three adjacent bases on the mRNA are a codon and are translated into one amino acid, so the base number in the mRNA is 3 times the number of amino acid molecules in the protein; During transcription, a strand of DNA is transcribed into mRNA, so the base number in DNA is 2 times the base number in mRNA and 6 times the number of amino acids in protein.

The hemoglobin has four peptide chains, and 570 molecules of water are shed, indicating that the hemoglobin has 574 amino acids. An amino acid corresponds to three codons, and in the DNA double strand of the gene, there are six deoxynucleotides, that is, six bases, that is to say, one amino acid corresponds to six bases in the gene, so 574*6=3444

Four peptide chains, 570 molecules of water, so there are a total of 574 amino acids, a total of 574 * 3 codons, multiplied by 2, and the base number is the base number.

Option D are all high-efficiency substances.

aNot all are produced by living cells.

Can be synthesized.

Not necessarily. But most of them are egg whites.

For example, sex hormones are sterols, and epinephrine is amines.

cNot all of them can be adjusted.

For example, vitamins, some of which are only essential components of the body's structure and do not have a regulatory effect.

d Indeed, they are all highly effective material correct.

CBase is a catalytic organic matter produced by living cells.

D There is helicase enzyme acting on DNA in the cytoplasm.

Transcription of DNA.

Translation requires helicase enzymes.

a. Low temperature can not destroy the structure of the enzyme and make it inactive.

The genotype of the yellow female in question 3 is aarr or aarr! The reason is from the analysis of the parents. The cover ratio is calculated as 3 64, and my idea is that the cover rate of aa's cover law is 1 2 times 3 4 (the cover rate of AA's offspring showing dominant yellow is 3 4) multiplied by 1 4 (rr's offspring rr's cover rate is 1 4) and then multiplied by 1 2 (the probability of females) is equal to 3 64

Is AR on the XY chromosome, I am older, and I almost forgot about it.

Lover's Japanese link to Teresa Teng.

Answer: The probability of a child having only one genetic disorder, C or D, is (), the probability of having two genetic disorders at the same time is (

Analysis: First, calculate the probability of 8 (aaxbxb or aaxbxb) and 9 (aaxby or aaxby) offspring suffering from 1 disease.

1) Calculate the probability of 8 and 9 offspring developing C disease as:

xbxb xby or xbxb xby xbxb xbxb xby xbxb xby xbxb xby each accounts for 1 2, so the probability of suffering from C disease is 1 2 1 2 = 1 4.

2) Calculate the probability of 8 and 9 offspring suffering from Ding disease as:

aa aa or aa aa

aa aa aa

In each case, it is 1 2, so the probability of developing Ding disease is 1 2 1 2 = 1 4.

Therefore, the probability of suffering from only one disease is: 1 4 3 4 + 3 4 1 4 = 3 8, and the probability of suffering from both diseases at the same time is: 1 4 1 4 1 16.

This is not good to judge, whether No. 3 and No. 6 are sick or not, assuming that they are healthy, they will calculate the No. 8 gene xx One with Ding disease and one healthy.

Nine xy one with C disease and one y healthy.

Then you get four kinds of children.

The probability of suffering from only one disease is 1 2 and 1 4 for both

1.is a cell.

2.First of all, the natural situation must be that the charge is balanced, but the negatively charged ions are not named. So when the positively charged K+ is outflowing, the cell is negatively charged, and the outside is positively charged; Action potential is also a truth.

3.The sodium-potassium ion pump is not required by high school, it is the structure of pumping K+ into the cell and pumping Na+ out of the cell, that is, it makes the K+ concentration in the cell greater than the outside, and the Na+ concentration inside is smaller than the outside. That is to say, its function is to transport substances against the concentration gradient, which is active transport.

Assisted diffusion occurs in the process of potassium outflow and sodium influx described above, and is along the concentration gradient.

4.is the cell membrane.

5.Excitatory neurotransmitters can cause the next nerve cell to develop an action potential; I don't know about the inhibitory, but the apparent inhibitory neurotransmitter can open the chloride channel, causing chloride to flow inward, hyperpolarizing the cell membrane, and thus inhibiting the occurrence of action potential.

Hope it helps

1. The synaptosome with synaptic axon terminals and the cell body or dendritic contact of the next neuron itself synaptosome is collectively called synaptosome by the anterior membrane of the previous neuron and the posterior membrane of the next neuron.

2. The points are comparative, for example, 10 positive charges and 1 negative charge together, a negative one will be neutralized by a positive one, so 11 charges are positively charged externally, so although there are positive charges inside and outside the membrane, there are much more in the membrane than outside the membrane, so the positive charge in the membrane is contrasted with the negative charge in the membrane.

3. I haven't learned anything about the refractory period, so I won't be embarrassed Sodium ion is an assisted diffusion Active transport includes assisted diffusion and free diffusion.

4. That membrane is called the myelin sheath, what our teacher said, but it's useless, I won't take the test, nerve fibers are made up of multiple neuronal links, and neurons are nerve cells, and they are cells, and they have cell bodies, and nerve cells exist in the spinal cord and brain, just like muscle cells control muscles, and nerve cells also regulate nerves.

5. There is no difference.

I just learned this in my second year of high school.

Hey, hey, hey, if you're satisfied, accept it!