Senior One Biology Concept, Senior One Biology to explain

Modified by integration, absolutely correct:

1. Yes, introns are part of the chromosomes but are not expressed.

2. No, it starts from the binding site of RNA polymerase or DNA polymerase, and is a regulatory sequence located upstream of the coding region.

3. Belonging, there are sequences in the non-coding region that regulate the transcription of the coding region, so there is a genetic effect.

4. Any fragment of DNA is composed of deoxyribonucleotides, which are connected to each other.

5. Yes, coding regions include introns and exons.

1 Yes, introns are part of the chromosomes, that is, and DNA 2 is not, and promoters are also part of genes.

3 No, genes are the ones that have the function of encoding.

4 is the same.

5 No, the exon is expressed, which is the coding region.

1.Be. 2. No, the new genes include regulatory genes upstream of the promoter.

3.It belongs to the non-coding region and there are genes that regulate the transcription of the coding region.

4.The chemical essence is the same, and the base sequence is inconsistent.

5.Belong.

1. b The ratio of oxygen absorbed by aerobic respiration to the carbon dioxide released is 1:1, and because the amount of carbon dioxide released is measured to be twice as large as the amount absorbed by oxygen, the ratio of carbon dioxide released by anaerobic respiration to the carbon dioxide released by aerobic respiration is 1:1.

Aerobic respiration consumes 1 mol of glucose to release 6 mol of carbon dioxide, and anaerobic respiration consumes 1 mol of glucose to release 2 mol of carbon dioxide, so the ratio of glucose consumed by aerobic respiration to anaerobic respiration is 1:3. Pick B

2. The complete decomposition of B glucose is judged to be aerobic respiration. The carbon dioxide produced by aerobic respiration is 6mol, and the oxygen consumed is 6mol, so the ratio is 1, choose b

1 yeast aerobic: 1 portuguese, 6O2, 6CO2

Anaerobic: -1 Portuguese, -0O2, +2CO2

The amount of CO2 released is 2*O2 consumption.

then aerobic (1 Portugal, 6O2, 6CO2): 3 anaerobic (-1 Portugal, -0O2, +2CO2) satisfies B

2. Thorough oxidation and decomposition into aerobic.

6o2，＋6co2b

First of all, A is deoxyribonucleic acid, A is DNA, X is RNA, B is an amino acid, B is a protein, Y is a chromosome, and B1, B2, and B3 are three proteins with different functions: immune protein, enzyme (protein), and hemoglobin.

1: Transcriptase.

2: Within the mitochondria, in the cytoplasmic matrix.

3: There are many kinds of amino acids that make up proteins; The spatial structure of proteins varies4: Yes, the genetic material is the same.

5: chromosome, 1; 2

6: peptide chain, 3m+3 (terminator does not translate protein).

1) Processes 1 and 2 show that polymorphic sugars and proteins of S-type bacteria are mixed with R-type bacteria, and their progeny are R-type bacteria.

2) Process 3 shows that the DNA of type S bacteria is mixed with live bacteria of type R, and type R bacteria are transformed into type S bacteria.

3) Process 4 showed that the offspring of the transformed S-type bacteria were also virulent S-type bacteria. Mountain Book.

1) Polysaccharide protein r

2)dna r s

3)s toxic s

This is a very simple problem of separation and combination, which is quite a simple lease for Wang Youhong. After careful analysis, most people will make a difficult book. Unless you're at primary school level.

It's been many years since I graduated, and I forgot what I used to be best at.

The starch that can decompose at room temperature is called Diankong and powder enzyme, which belongs to protein.

aProtein is easily denatured under high temperature permeation, and is not easy to denature at low temperature.

B proteins definitely contain the element S.

c Amylase is specific and specializes in breaking down starch.

Dcorrect Proteins are made up of amino acids, both amino and spindle. Pick D

1 Starch is a polysaccharide, not a reducing sugar.

Chloroplasty soybean seeds Soybean seeds are high in protein.

2. The solution of biuret reagent turns purple.

Filin reagent water bath brick red glucose.

2. There are one bottle of unlabeled Hepin protein, glucose, and starch solution, and they can be identified by biuret reagent and Feilin reagent.

With a reagent (biuret reagent) - you can separate the dilute protein from the filter, and the phenomenon is (the solution turns purple).

Glucose and starch can be distinguished with the reagent Filin reagent, and if the water bath is heated and there is a (brick-red) precipitate to form, it is a reducing sugar

1. Because starch is not reducible.

Chlorophyll soybeans.

Soybeans are rich in protein.

2 biuret reagent.

Purple or blue-violet complex.

Filin reagent. Solution reddish-brown copper oxide.

Starch is not a soluble reducing sugar Vacuole Soybeans Soybean seeds are rich in protein.

The solution turns purple after shaking the biuret reagent.

Filin reagent water bath brick red precipitate glucose.