In the following ion equations, the wrong one is

The first mistake should be Fe(OH)3 + 3H+ == Fe3+ +3H2O

If one is excluded, then only B is wrong.

Due to the order of metal activity of Cu after h.

So the second reaction can't be carried out.

Since both Ca(OH)2 and Na2CO3 are considered to be completely ionized, the third is true.

Fe2O3 is insoluble, so write the chemical formula, so the fourth is correct.

Cu does not react with dilute hydrochloric acid, the second one is wrong.

Fe(OH)3 reacts with dilute sulfuric acid: Fe(OH)3 + 3H+ == Fe3+ +3H2O

Cu does not react with dilute hydrochloric acid, and the order of metal activity of Cu is after H: K Ca Na mg al Zn Fe Pb h Cu Hg Ag

B is false, copper is weaker reducing than hydrogen, and this reaction does not follow the relevant theorems of redox reactions.

The first one is that you made a mistake yourself.

Due to the order of metal activity of Cu after h.

So the second reaction can't be carried out.

Cu does not react with dilute hydrochloric acid, and the order of metal activity of Cu is after h.

Order of metal activity: K Ca Na mg al zn fe pb h cu hg ag

Cu does not react with dilute hydrochloric acid, the second one is wrong.

Fe(OH)3 reacts with dilute sulfuric acid: Fe(OH)2 + 3H+ == Fe3+ +3H2O

It should be Fe(OH)3

Select B Cu does not react with dilute hydrochloric acid. The order of metal activity is after h.

The second Cu does not react with dilute hydrochloric acid

b.Copper does not react with dilute hydrochloric acid.

The problem is that every one looks wrong on a closer look!

Option A, the reaction of iron and dilute hydrochloric acid to produce Fe2+, the correct ion equation is Fe+2H+=Fe2+ +H2, and the BCD is correct.

Answer] B Answer Analysis] Test Question Analysis: A. Add Na2S solution dropwise to the AGCL suspension, and the white precipitate becomes black: 2AGCl + S2 = Ag2S +2C1, correct; B. Na2O2 is left in moist air for a period of time and turns into a trembling white viscous, and the reactions involved are:

2na2o2+2h2o===4naoh+o
na2o2

2co2=2na2co3+o2

Mistake; c. Add H2O2 to the acidic KMno4 solution: 2Mno4 +5H2O2 + 6H2 2MN2 +5O2 +8H2O, correct; d. According to the conservation of materials, 0 1mol l

CH3COONA solution: C(Na+) C(CH3COOH) C(CH3COO beating), correct.

Test point: Examine the true and false judgment of the equation, involving the transbase dongzhouization of precipitation, the properties of sodium peroxide and the conservation of materials.

Wording issues.

In fact, strictly speaking, it should be excessive.

Excess CO2 is passed into the caustic soda solution:

2oh- +CO2===CO32- +H2O CO32- +CO2 + H2O ===2HCO3- Together: OH- +CO2====HCO3- So... The word "sufficient", compare.

Ambiguous.

Sufficient amount of carbon dioxide to produce bicarbonate.

oh-+co2=hco3-

En. A sufficient amount will convert carbonate into bicarbonate.