Super easy math problems, very simple math problems

Student: The "=" in your question should be "+" or "-"!

First of all, if your "=" is "+", you know that f(x)=x 5+ax 3+bx+8, so that g(x)=x 5+ax 3+bx

Since f(-2)=10, g(-2)=f(-2)-8=10-8=2 is obviously an odd function of g(x), so g(2)=-2

So f(2)=g(2)+8=-2+8=6

If your "=" is "-", you know f(x)=x 5+ax 3+bx-8, so g(x)=x 5+ax 3+bx

Since f(-2)=10, g(-2)=f(-2)+8=10+8=18 is obviously an odd function, so g(2)=-18 so f(2)=g(2)+8=-18-8=26

Is there a problem with what you wrote, is it to remove the "8", if you remove it, because f(x) is an odd function, f(-x)=-f(x), so f(2)=-10,

If you want to write the equation f(x)=x5+ax 3+bx-8, then f(2)=-26

Solution: Let g(x)=x 5+ax 3+bx, then f(x)=g(x)-8f(-2)=g(-2)-8=10

g(-2)=18

g(2)=-g(-2)=-18 (g(x) is an odd function) f(2)=g(2)-8=-26

Apples are kilograms, pears are times that of apples, oranges are twice as many as pears, pears (kilograms, oranges (3y) kilograms.

I can't find a formula for this.

Pears are kilograms.

Oranges are 3y kilograms.

The length of the road along the lake is 1920m, A and B are walking on the road along the lake, the two set off at the same time and walk in the opposite direction, A walks faster than B, and meets after 12 minutes. If the two people walk an extra 16m per minute, the meeting point is 20m different from the previous one

1.Find the original walking speed of A and B.

1.If A and B each set off at the same speed and walked in the same direction at the same time, where did A catch up with B for the second time?

40 8 Buy a ticket for 40 people, cheaper than 36 people.

1. (1-1 20 10) (10-2) = 1 161 1 16 = 16 (days).

Solve with equations: Let it take x days for B to do it alone.

1 20 + 1 x) 10 = 1-1 x 22, set to take x days to complete.

1/15×x+1/25×（x-7）=1

x=12 is solved by arithmetic

Total quantity = 1 + 1 25 7 = 32 25

Didn't you say it's super easy, so why do you still ask about the problem solving process and answer pinching?