Kneel and ask for 1 A 1 B 1 45, ask for A B 30

Unless otherwise specified, there are 29 sets of integer solutions, and any substitution will be counted as the answer.

a = 1980，b = 44

a = -630，b = 42

a = -360，b = 40

a = -180，b = 36

a = -90，b = 30

a = -36，b = 20

a = -30，b = 18

a = 18，b = -30

a = 20，b = -36

a = 30，b = -90

a = 36，b = -180

a = 40，b = -360

a = 42，b = -630

a = 44，b = -1980

a = 46，b = 2070

a = 48，b = 720

a = 50，b = 450

a = 54，b = 270

a = 60，b = 180

a = 70，b = 126

a = 72，b = 120

a = 90，b = 90

a = 120，b = 72

a = 126，b = 70

a = 180，b = 60

a = 270，b = 54

a = 450，b = 50

a = 720，b = 48

a = 2070，b = 46

Integer solution, not unique:

So a = 60 b 180, a b = 240

If the basic inequality is greater than or equal to 180, is this question required to find a specific value? Just guess the specific value of 180, don't spray the gods

I guess I didn't write it all.

Because of such conditions, there are countless solutions that can be obtained.

The landlord, the conditions are insufficient.

The value of a+b could not be determined.

Please improve the problem so that it can be solved for you.

sinα^2+cosα^2=1

Combine the above two drafts.

sina = 0 or key talk 3 5

cosa = 1 or -1 or 4 5

tana = 0 or 3 local potatoes 4

You may want to set the opposite edge a, the adjacent edge b, and the hypotenuse c

Plain cos = 1 4

b/c=1/4

Let b=x, c=4x

a=√[4x^2)-x^2]

a=√15x

Row pure sin = a c = 15 4

tan = a b = 15

Summary. f(x) = 3sin(2x+6) and the minimum positive period is .

k-3 axis of symmetry: x=k2+6, center of symmetry: x=k2-12

tan +1 tan -1 2, find sin cos

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3cos²θ

sinθcosθ=3cos²θ

Because sin +cos = 1

sinθ=3cosθ

So sin cos = 3 10

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f (x) minimum positive period of 3sin (2x+6), axis of symmetry, center of symmetry.

f(x)= 3sin(2x+6), and the most positive period is . kπ-π3

If cos = 1 2 , then, = 4 + 2k

k is an integer.

The left and right sides are desquared at the same time: (sin -cos) =1 The law of right angles: (sin +cos) 2sin cos =1 gives the following: 1- sin2 =1

Derivation: sin2 = 0

Trigonometric calculation: 2 = k

Derivation: =k 2,k z (

Left extraction root number 2Except to the right. Simplified sin on the left (x-45) = root number 2 2Then find it according to the x range. If there is no range, there are many answers.

sin -cos = 1, squared on both sides.

2sinθcosθ=0

sin2θ=0

kpai k is a natural number.