A problem I haven t learned, a problem I don t know?

1) Buy 1 liter: the first type: yuan).

The second type: meta).

The third type: about = yuan).

2).(3) and (1) are similar.

I don't know if it's the easiest way!

Let the first one be the x bag, the second one is the y bag, and the third one is the z bag (xyz is a positive integer or 0, I have forgotten it, I don't know that 0 is not a positive integer, forgive me).

1) Because the third type is available in one bag, so in the first question, you don't need to consider y125x+250y=1000 (1l=1000ml)x=8-2y.

y=0 1 2 3 4

Corresponding to x=8 6 4 2 0

In other words, there are five ways to buy!

Put these five sets of numbers separately, substitute them into the middle, and see which set of values calculates the least value, which method is the cheapest Worry about it yourself, calculate it. Hehe! ~

The following can be calculated in this way

The first one should be, so you can find the price of 125ml of each type of milk. Because the milk content of the three middle schools is a multiple of 125, and the volume in the problem is also a multiple of 125ml. So you can do the math.

To learn, you must first learn the method. The process comes after that.

1) Buy four second types of milk for the cheapest.

2) Buy eight second types of milk for the cheapest.

3) Buy a third type of milk is the cheapest.

Let x carts be transported, there is x:16 = 20:20 (1-20%), so x=16 (1-20%)=20 (carts).

Let x car be transported, x:16 = 20:20 (1-20%), and x=20 (car).

You're wrong.

Planned time = 300 30 = 10 days, the original plan was to produce 24000 parts per day 10 = 2400 pcs.

Or plan to produce x parts per day, 24300 x + 30 = 2400 x, x = 2400 pcs, planned time = 24000 2400 = 10 days.

2.Complete the task 2 days ahead of schedule, and produce 24000 parts 8 = 3000 pieces per day, of which 2400 are produced by workers and 600 by robots. Each group of robots produces 120, 20 workers produce 100 per day, a total of 24000 100 20 = 480 workers.

A: There were 13 30 people who did not drink.

According to the topic, we can first calculate how many people drink something, and then subtract the number of people who drink the drink from unit one.

Assuming that all of them are chickens, then there should be 330 feet 2 = 660 (only) less than the actual 1160 660 = 500 (only) pigs have 500 (4 brothers, 2) = 250 chickens have 330 envy liquid 250 = 80 (only)."

Solution: Set up a 42-seater passenger car for rent.

42a+30=60（a-1）

42a+30=60a-60

90=18a

a=5 then: There are 2 situations in the sixth grade of 42x5+30=240 (people):

1. Only 42 seats are rented.

6 cars are required, and the cost is (6x1500=9000) yuan.

2. Only 60 seats are rented.

4 cars are required, and the cost is (4x1800=7200) yuan.

Because it is 9000>7200, it is the most cost-effective to rent 4 60-seater buses.

Write your own !! You'll never do that!