1 Knowing 2a 3b, find a square of ab b square b square b square a square b square b

A square of AB + B square - A square of B square - B square = A square of AB - A square of B square of B square.

It is divided into ab squares.

About a ...... of b-squaresLap 1

And because 2a = 3b, a = 3/2b ......Lap 2 brings lap 2 into lap 1 and simplifies it to get 2/9

2.The simple algorithm didn't think of it for the time being (I forgot what I learned when I was a child) to provide you with an idea (the stupidest kind:

Solve the m value first, and then bring it in.

3.Let B be able to type x per hour, and A can type per hour.

1800 divided by x -5/60 = 2000 divided by solution x = 2400

So A can type 3,000 words per hour? Can B type 2400 words per hour?

What I'm going to say is 1, I don't calculate very accurately, I suggest you calculate again. 2. For the second question, it seems to be related to the multiplication of crosses or something, listen to your teacher.

1 Knowing 2a 3b, find a square of ab b square b square b square a square b square b

2a=3ba=3b/2

a²+b²)/ab-(a²-b²)/b²

9b 4+b ) (3b 2)-(9b 4-b) b 2, if m squared - 3m + 1 = 0, find the value of m square + m squares 1 m square - 3m + 1 = 0

m-3+1/m=0

m+1/m=3

m+1/m)²=9

m²+2+1/m²=9

m²+1/m²=7

3. The work efficiency of typist A is 25% higher than that of B, and the time for A to type 2000 words is 5 minutes less than the time for B to type 1800 words.

If B can type x per hour, then A can type x per hour.

1600/x=1800/x-1/12

x=2400

1. It is known that 2a=3b, a=3b 2

ab a square + b square - b square a square - b square = [ab-a 2] b 2 = 3 2-9 4 = 0

2. If m squared - 3m + 1 = 0, we can know that m ≠ 0

So there is, m+1 m=3

m 2 + 1 m 2 = (m + 1 m) 2-2 = 9-2 = 73, B can type x words per hour, then A can type (1 + 25%) words per hour.

2000 [x(1+25%)]=1800 x-1 12 solution x=24000

A can type 30,000 words per hour, and B can type 24,000 words per hour.

Divide the back into the square of 2b of ab - the square of 2a, and the ten fingers in front of Bi Li are crossed: (a+b)(3a+2b)=0, the repentance is a+b=0, and the scattered number is in the original formula =0

a+b) = a+2ab+b.

a+b) = a+2ab+b.

There are two types of perfect squares, one is the perfect sum of squares formula, which is the sum of two integers and the squares outside the brackets. The other is the perfect squared difference formula, which is the square of the difference between two integers.

（a-b）^2+|a2b+3|=0

a-b）^2≥0

a2b+3|≥0

a-b=0a2b+3=0

It's good to find ab and bring it in.

I don't know what your A2B means, so I'm not going to do it for you.

Your question is wrong, what does it mean to find c by the square of a+2b+3ab-7b?

A square + ab = 3, b square + ab = 2

So replace B square + AB with A square + AB

So square A + 2AB + square B = 5

Party A - Party B = 1

A squared + 2ab + b squared equals = 5

a-squared - b-squared equals = 1