From the first to the first year of junior high school, the process should be solved urgent the f

When buying tickets together, because 1080 can only be divisible by 9 and cannot be divided by 13 and 11, the ticket price can only be 9 yuan per person. Therefore, the total number of the two regiments is more than 100, but the number of regiment A is less than 50, so the number of regiments B must be more than 50

Obtained by the joint ticket fee: A and B have a total of 120 people. 51,100 in Regiment B and 50

In addition, A and B are xy people, x+y=120, 13x+11y=1392, and x=36, y=84, that is, 36 people in group A and 84 people in group B.

1.The number of people in Group B is greater than 50.

If the number of people in group B is less than 50, the number of people in group A and group B is less than 50 people, and the ticket purchase is that group A and group B should pay 13 yuan per person, and 1392 is not an integer multiple of 13, so the number of people in group B should exceed 50 people.

Suppose the number of people in group A is x, and the number of people in group B is y (09*(x+y)=1080, i.e. x+y=120

Joint solution. x=46,y=74

If you purchase tickets together as a group, the total ticket fee payable is 1080 yuan.

1080 is an integer multiple of 9, so the total number of 100, regiment B is not less than 50 people.

A x people, B y people.

13x+11y=1392

x+y=120

11(x+y)+2x=1392

2x=1392-1320=72

x=36,y=84

1.If regiment B is less than 50 people, 1950 20=, not an integer, so regiment B is greater than 50 people.

2.Set up regiment A x people, regiment B y people, 20x 18y = 1950, because 20 and 18 are even numbers, even numbers multiplied equals even numbers, so the number of people in the two regiments A and B is greater than 100, 15 (x y) = 1545, and the two equations are combined: 48 people in regiment A and 55 people in regiment B.

Analysis: From the known conditions in the question, it can be seen that the operator must run 420 meters away to be safe within the short time of the fuse burning, that is, the time for the fuse to burn must at least allow the operator to run 420 meters in this time period.

Solution: Set the fuse to be more than x meters long.

i.e. x so x=84 cm.

A: The length of the fuse should be more than 84 cm.

Solution: Set the length of the fuse to be more than x cm, then.

x x = 84 cm.

A: The length of the fuse should be more than 84 cm.

The length of the fuse should be x cm.

x/>=420/6

x>=84

That is, the length should be at least 84 cm.

First of all, it depends on the speed of the operator's running is 6 meters per second, and how much time it takes to run beyond 420m = 420 6 = 70s

That is to say, the fuse must burn for more than 70 seconds to **, so the length must be at least =

420/6*

The length of the fuse should be more than 84 cm.

Let the wire length be x, then:

x solution gets x=

84 centimeters, which just means how long it takes the crew to run 420 meters away, and then (70 seconds), and then the fuse has to burn for more than 70 seconds, 70 times it. All you need to do is draw the diagram. You must do this in the future.

(420-x) 6=x The answer is self-calculated The people above don't count the length of the fuse, hey.

517715797 Q: You can't seem to see this.

Solution: Let the radius of the bottom surface be r

r²*16/9π=64

r = 36r = 6 or r = -6 (rounded).

A: The radius of the bottom surface is 6cm

The edge length of the iron block is 4 cm