f x 1 x 3 2x 2 3x, f 1 f 2 f 3 f n 503 2014 5

Solution: Set f(x)=ax 3+bx 2+cx+dg(x)=kx+t

by f(x)-1 2g(x).

ax^3+bx^2+[c-（1/2）k]x+[d-(1/2)t]=-x^3+2x^2+3x+7

So a=-1;b=2；

c-（1/2）k=3……①

d-(1/2)t=7……②

So f(x)=-x 3+2x 2+cx+d and f'(x)=-3x 2+4x+c

Because f(x) has an extreme value of 2 at x=1

So f'(1)=-3+4+c=0 f(1)=-1+2+c+d=2 gives c=-1 d=2

Replace c=-1 d=2 generations to get k=8 t=10, so f(x)=-x 3+2x 2-1cx+2 g(x)=8x+10g(x) is incremented within the defined domain r.

f’（x）=-3x^2+4x-1

x-1)(3x-1）

Let f'(x)=0 give x=1 or x=1 3

And because x is on x<1 3 and x>1 f'(x)<0x is at (1 3)0

So f(x) decreases monotonically on (- 1, 3) and (1,+).

f(x) increases monotonically on (1 3,1).

Note: f'(x) is a derivative of f(x). It will be very simple to follow the question in this kind of question. Map.

Are you satisfied with the above?

f(x)=1 (x 2+2x+3)x=1 x((x+1) 2+2) can be proved by multiplying (x+1) by (x+1) by (x+1) under the root number by (x+1) under the root number.

Summary. It is known that f(x)=x -3x+5 is found f(1)f(-1) and f(2)f(1)=1 2-3 1+5=4

It is known that f(x)=x -3x+5 is used to find f(1), f(-1) and f(2) derivatives. It is known that f(x)=x -3x+5 is found f(1)f(-1) and f(2)f(1)=1 2-3 1+5=4

Do you want to find the derivative first, and then find the value of the derivative?

Well. Dear, is that so? ok

I have written you the results and the calculation process as shown in the picture above.

The teacher can simply ask f'(x).

How is it solved?

With the derivative formula.

There are books that you need to master or memorize.

f(x)=1 (x+1), then f(1 Zen x) = 1 (1 x +1) = 1 [(x+1) x]=x (x+1), so f(x)+f(1 x)=1 (x+1) +x (x+1)=(x+1) large attack state (x+1) = 1 then f(2)+f(1 2)=1f(3)+f(1 rolling source3)=1......f(2012)+f(1, 2012)=1, so f(2)+f(3)+f(2012)+f(1/2)+f(1/3)+.

Summary. Knowing f(x)=2x +3x, find f(1)Hello<>

This is to find the expression of the second derivative, and then substitute the value.

Title. Wait a minute. <>

There is also a sub-question in the fifth question.

Summary. Hello, please add the question**, it is best to take a picture of the question, so as to better answer for you.

Knowing f(x)=-3, find f(1),f[(2)] Hello, please add the question**, it is best to be able to take a picture of the question, so as to better answer for you.

Closed interval. You can send a process, no.

If you have any questions, please feel free to ask.

f(f(x))

x²-x+3)²-x²-x+3)+3

The part after the first equal sign above can be simplified.

Let the analysis be appropriate in x=-3 first, so that you can calculate the value of f minus three, which should be equal to 15, so the formula in this parentheses is equal to 15, so the next calculation of f15 can get the final result of this problem, 447

Solution: Let x-1=t, then x=t+1

f(t)=(t+1)²-3(t+1)+4=t²+2t+1-3t-3+4=t²-t+2

T and x are also taken on the definition field, replacing t with x

f(x)=x²-x+2