Can you help me with this math problem in the first year of junior high school? Thank you!

Step 1: The temperature difference between the top and bottom of the mountain is 6 degrees.

Step 2: Represent a total of how many parts there are.

Step 3: Because every decrease (which can be understood as the difference in degrees every 100m from the top of the mountain to the bottom of the mountain, so there is a total of one degree, then they are 750m different from each other, which is the height of the mountain.

I'm the first 2, LZ adopt it next!

1. The temperature measured at the top of the mountain is -1 degrees, and the temperature measured at the foot of the mountain is 5 degrees: [5-(-1)]=6;

5 degrees to -1 degree, the temperature dropped by 6 degrees.

2. For every 100 meters increase in the height of the area, the temperature decreases by about 100 degrees

The height at the foot of the mountain is specified as 0 meters) the temperature decreases by 6 degrees, and the height increases by a few 100 meters, so 6 means that there is one;

x 100 = 750 m means an increase in altitude of 100 m.

To use the temperature difference, then find the temperature difference first.

The temperature difference is 6 degrees.

If the temperature difference is yes, the mountain is 100 meters high.

Look at how many of them are in 6 miles, and there are as many as 100 meters high in this mountain.

So it's 750 meters.

That's all I can say ...

First, calculate how many degrees are different from the top of the mountain and the bottom of the mountain.

Then count how many have been reduced in total.

Because it's every 100 drops, so at the end *100ok?

The temperature at the foot of the mountain is 5 degrees Celsius, and the temperature at the summit is -1 degree, and the temperature decreases by 5-(-1) = 6 degrees, and the temperature decreases by about 100 degrees for every 100 meters of altitude in the area.6

1. All assumptions are that A is x vehicles and B is (x+1) vehicles According to the title, 45x+60(x+1)=270 can be obtained, and x=2 y=3 freight=

350 * 2 + 400 * 3 = 1900 yuan.

Prompt him that B has 1 more car than A, and the number of computers = 270 It is not difficult to come up with the formula 45x+60(x+1)=270 As for A B, it has been calculated The freight is the sum of all the cars cost by A B, I hope I can understand.

There are too many conditions to give, and in the end, it is a junior high school question - -0 I'm afraid you won't be able to do the inequality group 45x+60y 270

350x+400y≤2000

where x is the type A car used, Y is the type B car, and there is y=x+1 to get x 2 y 3

It can be seen that if you want to save 2 A3 B

The shipping cost is 350*2+400*3=1900

Set up A type X set B type Y set freight w yuan.

A alone is 270 45 = 6 units Cost WA=6*350=2100 yuan.

B alone is 270 60 = = 5 units Cost wb = 5 * 400 = 2000 yuan.

is made up of a group of known available inequalities.

y-x=145x+60y>=270

w=350x +400y<=2000

The solution is 2<=x<= so x=2

Therefore, 2 types of A cars and 3 sets of type B cars have a freight of w = 1900 yuan.

Solution: If you use X cars of type A, then X + 1 cars of type B.

Type A only: (270 45) 350 = 2100 Type B only: 270 60 = so 5 cars are needed 5 400 = 2000A B uses 45x+60 (x+1) 270350x+400 (x+1) 2000

Settle for yourself.

Dissolve X cars of type A and cars of type B (X+1).

45x+60(x+1 270 solution x 22 350+(2+1) 400=1900 yuan You calculate the answer 、、、

A pentagon is surrounded by five hexagons, and each vertex is shared by three figures (one pentagon, two hexagons) with x white and y black.

x+y=32;

1 2 6x=5 y, the number of vertices is the same.

Solution, x=12, y=20

Since x minus x is equal to 2, the square of the two sides gives the square of x, and adding the square of x gives us 0

1.Original = -1000-25+1+13

Original = 3x2-3(x-1)+1

3x2-3x+4

104.There are x rooms on the ground floor and x+5 rooms on the second floor.

4x＜485x＞48

3（x+5）＜48

4（x+5）＞48

The solution is so x=10

5.If there are x white balls, then 60-2x 3 red balls.

x＜60-2x/3

2x＞60-2x/3

Solve x Because 60-2x 3 is a positive integer, x=9 (9 white balls) and 60-2x 3=14 (14 red balls).

1、（-1）+（25）+6+13=-7

2. Know that one of a b c is negative and two are positive. x=0 Answer13, [3*(2*2)]-2*2+1=[3*(3)(1)]-3)(1)+1=3*3-3+1=(4)(2)-3+1=8-3+1=6

4. Set the bottom layer x the second layer x x+5

4x<48<5x (1) then 5, set red x white y

3y+2x=60 know x=

When y=11 or 9 x is not a whole, round off, when y=10, x=15