How do fish swim in a spaceship in weightlessness ?

How to swim or how to swim, because both fish and water are weightless, and they are stationary relative to the frame of reference.

The water has resistance and the fish should have no problem swimming, as long as the water does not fly out of the tank.

Use a container to hold the water in place and put the fish inside.

If there is water, the fish will die, and you think, why do fish raised in a fish tank transmit oxygen, and fish breathe differently than people.

The fish ticket is useless.

Oxygenation and water change equipment are contained in the loaded and sealed containers???

Is there any other way? ``

The first thing to understand is what weightlessness and overweight are. Weightlessness refers to the state in which the pressure or pull of an object on the object supporting it is less than its own gravitational force, and if the object has no pressure or pull on the object supporting it, then it is a state of complete weightlessness. Overweight is a state in which the pressure or pull of an object on the object supporting it is greater than its own gravitational force.

The spacecraft has no object to support it in space, which means that it has no pressure on the object that supports it, and is in a state of complete weightlessness. There is no object to support it, so why didn't it fall? That's because the gravitational pull of the Earth on it acts as the centripetal force for its circular motion around the Earth.

The effect of gravity on it is eliminated in a completely weightless state. The steel balls we make on the earth are not real spheres due to the influence of gravity, but if they are completely weightless in space, without the influence of gravity, the steel balls solidify freely, and they are a real sphere. Also, colloidal is a kind of suspended particle very small suspending agent, on the earth due to the influence of gravity colloids are uneven, but in the state of complete weightlessness in space, colloids are very uniform In many applications that we do not want to have the influence of gravity, we can avoid the influence of gravity in space.

Of course, there is the issue of cost.

b.Because the other three instruments all require gravity. A and D both require the equilibrium of gravity on the instrument to determine the mass of the object; cThe gravity of mercury is required to balance the atmospheric pressure and thus calibrate the air pressure. B only uses the principle of thermal expansion and cold contraction, and has nothing to do with gravity.

a b d

A and D are tools for measuring the mass of an object and are independent of gravity.

b is based on the principle of thermal expansion and cold contraction, which has nothing to do with gravity.

c is the gravity of mercury to balance the atmospheric pressure, and the actual atmospheric pressure cannot be marked in weightlessness.

a. The balance is based on the principle of lever, and the balance balance requires the gravity of the object, so the balance cannot be effectively used in weightlessness

B, the principle of the spring scale is: the greater the tension of the spring, the longer the elongation of the spring Although gravity can not be shown in the weightless state, the tension is always there, so the spring scale can still be effectively used in the weightless state, c, the mercury barometer, in the weightless state, the mercury will not produce pressure, so it can not be effectively used in the weightless state

d. The rod scale is based on the principle of lever, and the balance balance requires the gravity of the object, so the balance cannot be effectively used in the weightless state

Therefore, choose B

a. The balance is based on the principle of lever, and the balance balance requires the gravity of the object, so the balance cannot be effectively used in weightlessnessb. The principle of the spring dynamometer is: the greater the tensile force of the spring, the longer the elongation of the spring Although gravity cannot be expressed in the weightless state, the tensile force is always there, so the spring scale can still be effectively used in the weightless state; c. The density of the liquid measured by the density meter is measured according to the balance of gravity and buoyancy by the density meter, which is completely weightless, without gravity and buoyancy, and the density of the liquid cannot be measured by the density meter, so the density meter can not be used effectively; d. In the weightless state, the liquid will not produce pressure, so the piezometer can not be used effectively, so choose B

The instrument cannot be used in weightlessness.

Most electronic devices are fine, right? Sweat.

The man in the window of the spaceship, detached from the gravitational pull of the earth.

Due to the lack of science and technology, it may take a few hundred years for mankind to solve the problem of weightlessness in spaceships.

dThis question is a comprehensive question of physics and chemistry. There is a certain force between the particles, so mixing gold and copper powder or mixing milk in water can be done on Earth as well as in space. In the same way, heating can also make the molecules overcome the intermolecular forces and volatilize, so C can also be completed.

None of the above experiments have anything to do with gravity. However, in the filtration operation, the separation of solid and liquid is completed by the liquid flowing to a low place under the action of gravity, and without gravity in space, the liquid will not flow from a high place to a low place, so the most difficult thing to complete in the space laboratory is option D.

a. The essence of the balance is the equal-arm lever, due to the gravity of the object in the plate, the balance is balanced, if there is no gravity, the balance can not be used, and the mass can not be measured; therefore a error;

b. The thermometer is made according to the principle of thermal expansion and cold contraction of liquid; The thermal expansion and contraction properties of an object are not affected by gravity; Therefore b is correct;

c. The mercury barometer uses atmospheric pressure to work, and if there is no air in space, the barometer will not work; Therefore c is wrong;

d. The essence of the rod scale is the lever, and the product of the force and the arm is equal in the balance condition of the lever; In weightlessness, the rod scale will not be usable; Therefore D is wrong;

Therefore, choose B