When X satisfies what condition, 3X 1 means a positive even number

Solution: 3x-1 is a positive even number, then:

3x-1 = 2k (k is a natural number).

Then simplify x = (2k+1) 3 (k is a natural number), i.e. x is a positive odd number divisible by 3.

Let any positive even number be 2n (n is an integer and n > 0), then.

3x - 1 = 2n

x = (2n + 1) 3 (n is an integer and n>0).

From the meaning of the title, we can see that 3x-1>0 then x>1 3 makes 3x-1=2k (k is a positive integer) so x=(2k+1) 3 In summary, when x=(2k+1) 3, 3x-1 means positive even.

Solution: Let n>0 and n be an integer.

3x-1>0 ①

3x-1=2n ②

From: 3x>1

x>——

Result: 3x=2n+1

2n-1 x=——

1 2n+1

Answer: When x>-and=-, 3x-1 means a positive and even number.

3x-1 indicates a positive and even number.

3x - 1 2 , and 3x-1 is an integer.

x 1 and 3x is an integer.

When x is a positive odd number, 3x-1 means a positive even number.

3x-1 is a positive and even number.

3x is a positive odd number.

Divide the odd by the odd to get the odd number.

x is a positive odd number.

Since 3x-1 represents a positive and even number, 3x should represent a positive odd number (and should be a positive odd number greater than or equal to 3), and the ode to the dust should be represented by x to indicate a positive odd number greater than or equal to 1.

Because 3x-1 represents a positive even number, it is a positive number.

So the seep smile sleeps 3x-1>0

So x>1 3

3x-1 is an even number.

So 3x is an odd number.

Odd multiply odd = odd.

So x is an odd number.

To sum up, x is an odd number greater than 1 3, that is, all positive odd numbers are completed.

Let any positive even number be 2n (n is an integer and n > 0), then.

3x - 1 = 2n

x = (2n + 1) 3 (n is an integer and n>0).

Because f(-x)=|1/2x-3|+|1/2x+3|=|1/2x+3|+|1/2x-3|=f（x）

So f(x) is an even function.

1) The function definition domain is r, f(-x)=(x) 3 +(x) 5 =-x 3 +x 5 )=f(x), and f(x) is an odd function. 晌limb bridge (2) Hungry segment x= 1, where f(x)=0,x , f(x) is both odd and even (3) The domain of f(x) is [ -2,0) (0,2], about.

1) Define the domain r with respect to the origin symmetry, f(-x)=3x+1≠f(x), and ≠-f(Sun slow x), then f(x) is not an odd function, nor is it an even function;

2) Define the domain r with respect to the origin symmetry, f(-x)=-3(-x) 2 +2=-3x 2 +2=f(x), the bucket family.

then f(x) is an even function

Let any positive even number be 2n (n is an integer and n > 0), then.

3x - 1 = 2n

x = (2n + 1) 3 (n is an integer and n>0).

x=2k-1 (k=1,2,3，……

3x-1 is an even number, then 3x is an odd number, 3x=2x+x2x is definitely an even number, then as long as x is an odd number, it is fine.

x=2n-1

If it is a positive even number, then n 1

Solution: 3x-1=2n (where n 1 and n is a natural number).

The solution is: x=(2n+1) 3 (where n 1 and n is a natural number).

That is, the condition that x satisfies it.