For a train with a length of 150m, it takes 10s to cross the bridge with a length of 90m at an avera

The speed of this train: (150m+90m) 10s=24m s I am glad to answer for you, I wish you progress in learning! The [the1900] team will answer the questions for you.

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From the front of the train entering the bridge to the front of the car exiting the bridge, the train traveled 90m. But the rear of the car had not yet left the bridge. Only after the front of the train has traveled another 150m (the length of the train) does the rear of the train leave the bridge. So the car went a total of 90+150 240m

240÷10＝24m/s

The speed of the train is 24 meters per second.

As can be seen from the drawing, the entire body needs to pass through the bridge, so the total length is 150 + 90 = 240m

The velocity is 240 10 = 24m s

The speed of the train is the length of the bridge plus the length of the car divided by the time required. (150m+90m)÷10s=24m/s

The train speed is 10 meters sec and the train length is 200 meters.

The length of the bridge is km = 1800 meters.

Take a look at the schematic.

We use the line segment in parentheses to represent the bridge, the ellipsis to represent the train, the number 1 is the locomotive, and the number 0 is the end of the train.

The train crosses the bridge completely: 0......1[——0……1

The trains all run on the bridge: [0......1———0……1]

Because the train itself has a length, the locomotive is on the bridge, and the end of the train has not yet come, and when the end of the train is on the bridge, the locomotive has already run to the front, and the train has completely crossed the bridge, and the locomotive will run the length of "bridge length + car length"; The trains are all on the bridge, and the length of the locomotive is the "bridge length - car commander".

The train passes completely through the bridge, that is.

1800 + 200) 10 = 2000 10 = 200 seconds.

The trains are all on the bridge, that is.

1800 - 200) 10 = 1600 10 = 160 seconds.

The first question is 1800 10+200 10=200 seconds.

The second question (1800-200) 10 = 160 seconds The reason for the first question is that the reason for adding 200 is that the length of the body must be added to the complete exit from the bridge, and the reason for the second question minus 200 is that the body must be all on the bridge to be counted as all the time on the bridge.

Shouldn't this be a physics problem? Why do we all answer with direct math?

Solution: The train passing through the bridge means that it leaves the bridge from the front of the train to the rear of the car, so the distance passed is:

S car + S bridge 180m+600m=780m Time required to cross the bridge: t=s v=780m 20m s=39s Answer: The time required for the train to cross the bridge is 39s

1. The train length l 200 meters, the speed v 15 m s, the bridge length s 1600 meters, all the cars that are required to pass through the bridge all the time is from the front of the car to the head of the bridge to the end of the car leaving the end of the bridge.

That is, t total (l s) v (200 1600) 15 120 seconds 2, because the length of the car is less than the length of the bridge, when the rear of the car just arrives at the bridge, the car is all on the bridge, until when the front of the car just arrives at the end of the bridge, the car is also all on the bridge, and only a part of the car is on the bridge at other times.

So, the time for the car to be on the bridge is t (s l) v (1600 200) 15 seconds.

1. Answer:

From the front of the car into the bridge to the end of the car to leave the bridge, the train has traveled a total of 1600 + 200 = 1800m, and the time taken for the car to pass through the bridge is 1800 15 = 120s = 2min2, answer:

The distance of the car on the bridge refers to the distance from the end of the car entering the bridge to the front of the car leaving the bridge, the train has traveled a total of 1600-200 = 1400m, and the time taken by the car on the bridge is 1400 15 is approximately equal to.

Solution: According to the formula:

Distance = Speed * Time.

The train has been traveled in minutes = = km = 1040 m.

And distance = train length + bridge length.

So bridge length = distance - train length = 1040 - 180 = 860 meters.

Multiply the time to get the answer minus 180 meters, I can't see how long the train tail is behind the bridge, you can do the math yourself.

Hope it helps.

km, km = 1040 meters, 1040-180 = 860 meters, A: The bridge is 860 meters long.

1. The length of the train is 200 meters, and the speed is V 15

m s, bridge length s 1600 m.

All the cars you want pass through the bridge, and all the time is from the front of the car to the end of the bridge until the back of the car leaves the bridge.

i.e. t total (l s).

v＝（200＋1600）/

15 120 seconds.

2. Because the length of the car is less than the length of the bridge, when the tail of the car just rushes to the bridge, the car is all on the bridge, and the difference is not until the front of the car just reaches the end of the bridge, the car is also all on the bridge, and only a part of the car is on the bridge at other times.

So, the time that the car is all on the bridge is t

s－l）/v＝（1600－200）/

15 seconds.

180s, because it is all time, it is counted from the moment the front of the car touches the bridge until the rear of the car leaves.

1. Answer: From the front of the car entering the bridge to leaving the bridge at the end of the car, the train has traveled a total of 1600 + 200 = 1800m, and the time it takes for the car to pass through the bridge is all.

1800/15=120s=2min

2. Answer: The journey of all the cars on the bridge refers to the time from the rear of the car entering the bridge to the front of the car leaving the bridge, the train has traveled a total of 1600-200=1400m, and the time taken by the car on the bridge is all.

1400 15 is approximately equal to.

Answer: Known: s0=150m l=90m t=10s Find: v=?

Solution: The distance traveled by the train is s=s0+l=150m+90m=240m, and the speed of the train is v=s

t=240m

10s=24m/s．

A: The speed of the train is 24m s

(1) Solution: Let the speed of the vehicle be x, which can be obtained according to the meaning of the topic.

10x=150+90

So x=24The speed of the train is 24m per second

2) Solution: Set the required time to be y seconds. It can be obtained according to the title.

24y=1050

So y=seconds.