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Solution: Connect BG BH, which is divided into three by E and F as AB and ABC, and the midpoint g and h of the BC edge as AC.
bg fd bh ed so the quadrilateral bhdg is a parallelogram.
gd = hb chb = cge = agd (to apex angle) ag = ch chb = agd gd = hb agd chb
ad=cb ∠gad=∠hcb
ABCD is a parallelogram.
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Connect BHConnect BGBecause it is a trisect of AC, so AG=HC, H is the midpoint of CG, G is the midpoint of Ah, because it is the midpoint, so HF is parallel to BG, EG is parallel to BH (median line theorem), so ED is parallel to BH, DF is parallel to BG, so the quadrilateral BGDH is a parallelogram, so DG is equal to BH, because ED is parallel to BH, so the angle AHB is equal to the angle age, so 180° minus the angle AHB is equal to 180° minus the angle age, So the angle bhc is equal to the angle agd
In the triangle BHC triangle AGD, HC is equal to AG, BH is equal to DG, and the angle BHC is equal to the angle AGD, so the triangle BHC is all equal to the triangle AGD, so BC is equal to AD, and the angle HBC is equal to the angle ADG, so BC is parallel to AD, and because BC is equal to AD, ABCD is a parallelogram.
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Two identical triangles = one parallelogram.
One parallelogram = two identical triangles.
Two identical right triangles = a square or a rectangle.
A rectangle or a square = two right-angled triangles that are exactly the same.
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The area of a parallelogram is twice that of a triangle (equal base and equal height).
The height of the parallelogram is half of the triangle (the face is filial piety, the product is invisible, etc., the bottom phase is imitated, etc.).
The base of the parallelogram is half the size of the triangle (the area is equal and the height is equal).
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Triangles: pyramids, camera tripods, high-voltage power towers, old-fashioned bicycles (frames), ancient house structures (beams). The stability of the triangle is used.
Parallelograms: sliding doors, hand-woven baskets, folding hangers. This is due to the use of the parallelogram's easy deformability.
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Parallelogram.
The area is triangular.
2 times. Wait for the bottom and wait for the muffled shouting and high).
The height of the parallelogram is half of the height of the triangle (equal in area, equal in base and equal in depth) and half the height of the triangle (equal in area, equal in height).
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12 (square centimeters), answer: the area of the parallelogram of the stove source of the same height as it is 12 square centimeters
So the answer is implicit: 12
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(1) The number of the smallest triangles in the figure: 9, the larger triangle: 3, the largest triangle: 1, the total number of triangles: 9 + 3 + 1 = 13 (pieces);
2) Parallelograms: Parallelograms composed of 2 triangles: 9, Parallelograms composed of 4 triangles: 6, the number of parallelograms in total: 9 + 6 = 15 (pieces);
3) Trapezoid: 3 triangles composed of trapezoids: 4, 5 triangles composed of trapezoids:
1, 8 triangles of trapezoids: 1, each triangle has 6 such trapezoids at the vertices, a total of: (4+1+1) 3=18
So the answer is
Let the waist length be x, from the inscription: one part is 2cm longer than the other, 8+x 2=x+x 2+2 or 8+x 2=x+x 2-2 >>>More
Extending the extension line of BE AC at N, bisecting BAC and BE perpendicular to AD by AD, we can get the congruence of triangle ABE and triangle ANE, so E is the midpoint of Bn and M is the midpoint of BC to get EM is the median line of the triangle BNC, so EM 1 2CN 1 2 (An AC) 1 2 (AB AC).
Proof is that the connection CE, AD bisects the angle BAC and DC perpendicular AC, DE is perpendicular to AB Angle CAD=angle EAD, angle ADC= angle AD=AD The triangle ACD is all equal to the triangle AED AC=AEconnects the CE angle AD at point F AC=AE, the angle CAF = the angle EAF, AF=AF The triangle ACF is fully equal to the triangle AEF Angle AFC=Angle AFD=90°; CF=EF AD is the perpendicular bisector of CE. >>>More
I choose BCongruence, based on SAS
By a+ b= c, b'+∠c'=∠a'and a+ b+ c=180, b'+∠c'+∠a'=180 >>>More